Re: [Matplotlib-users] Version 0.98 behavior change - scatter

2008-06-16 Thread Manuel Metz
Eric Firing wrote: > Michael Droettboom wrote: >> As a quick-fix workaround, you can do: >> >> from matplotlib.pyplot import * >> p = scatter([0,1,2,3], [4,5,6,7], c ='k', alpha=0, edgecolor = 'k') >> p._alpha = 1.0 >> p.set_edgecolor('k') >> show() >> >> But the deeper question is for the rest of

Re: [Matplotlib-users] Version 0.98 behavior change - scatter

2008-06-16 Thread Eric Firing
Michael Droettboom wrote: > As a quick-fix workaround, you can do: > > from matplotlib.pyplot import * > p = scatter([0,1,2,3], [4,5,6,7], c ='k', alpha=0, edgecolor = 'k') > p._alpha = 1.0 > p.set_edgecolor('k') > show() > > But the deeper question is for the rest of the list is... what's the >

Re: [Matplotlib-users] Version 0.98 behavior change - scatter

2008-06-16 Thread Michael Droettboom
As a quick-fix workaround, you can do: from matplotlib.pyplot import * p = scatter([0,1,2,3], [4,5,6,7], c ='k', alpha=0, edgecolor = 'k') p._alpha = 1.0 p.set_edgecolor('k') show() But the deeper question is for the rest of the list is... what's the correct behavior? Should we just revert to w

[Matplotlib-users] Version 0.98 behavior change - scatter

2008-06-16 Thread S Murthy Kambhampaty
There seems to have been a change to the behavior of the 'alpha' keyword option to scatter(): where previously alpha only affected the facecolor, and the edgecolor always had an alpha of 1.0, alpha now seems to affect both facecolor and edgecolor. Tested with 0.93.1 and 0.98. Tested with new A