Re: [Matplotlib-users] legend border, frameon keyword

2011-11-11 Thread Paul Ivanov
On Fri, Nov 11, 2011 at 12:40 PM, magurling wrote: > I updated matplotlib to 1.1.0; both methods work now. Thanks for letting us know, and glad it works for you now - that information is useful for those who search for similar error messages in the future and find this thread. > I would say "Tha

Re: [Matplotlib-users] legend border, frameon keyword

2011-11-11 Thread magurling
I updated matplotlib to 1.1.0; both methods work now. I would say "Thanks Paul and Francesco" but I just read the mailing list etiquette. -- View this message in context: http://old.nabble.com/legend-border%2C-frameon-keyword-tp32807933p32828355.html Sent from the matplotlib - users mailing list

Re: [Matplotlib-users] legend border, frameon keyword

2011-11-11 Thread Paul Ivanov
>> On Fri, Nov 11, 2011 at 8:53 AM, Paul Ivanov wrote: >>> might you be on an old matplotlib.__version__? On Fri, Nov 11, 2011 at 11:18 AM, magurling wrote: > This is probably it. I installed by "apt-get install" but keep getting > version 0.99.3 installed. > I need to install a more recent vers

Re: [Matplotlib-users] legend border, frameon keyword

2011-11-11 Thread magurling
This is probably it. I installed by "apt-get install" but keep getting version 0.99.3 installed. I need to install a more recent version before I trouble anyone further. Which version are you using Paul? Paul Ivanov wrote: > > Oops, didn't reply to list last time: > > On Fri, Nov 11, 2011 at 8

Re: [Matplotlib-users] legend border, frameon keyword

2011-11-11 Thread magurling
Thanks Francesco, but I've also tried to use the "draw_frame(False)" method with no luck. montefra wrote: > > Hi, > > I usually do like this > > l = ax.legend( (rects1[0], rects2[0]), ('set1', 'set2')) > l.draw_frame(False) > > Cheers, > > Francesco > > 2011/11/9 magurling : >> >> I want a

Re: [Matplotlib-users] legend border, frameon keyword

2011-11-11 Thread Paul Ivanov
Oops, didn't reply to list last time: On Fri, Nov 11, 2011 at 8:53 AM, Paul Ivanov wrote: > On Tue, Nov 8, 2011 at 4:49 PM, magurling wrote: >> >> I want a legend without the black border. I've tried a few things that have >> been suggested on this forum and elsewhere to no avail. According to w

Re: [Matplotlib-users] legend border, frameon keyword

2011-11-11 Thread Francesco Montesano
Hi, I usually do like this l = ax.legend( (rects1[0], rects2[0]), ('set1', 'set2')) l.draw_frame(False) Cheers, Francesco 2011/11/9 magurling : > > I want a legend without the black border. I've tried a few things that have > been suggested on this forum and elsewhere to no avail. According to

[Matplotlib-users] legend border, frameon keyword

2011-11-11 Thread magurling
I want a legend without the black border. I've tried a few things that have been suggested on this forum and elsewhere to no avail. According to what I've seen, it should be as simple as: import matplotlib.pyplot as plt import numpy as np N = 5 Means1 = (20, 35, 30, 35, 27) Means2 = (25, 32, 34,