On 29 Jun 99, at 18:06, Lucas Wiman wrote:
Therefore, to find the first one with 10^7 digits, we find ceil(10^7/log_10(2))
which is 33219281.
NO! The _correct_ formula is ceil((10^7-1)/log_10(2)) = 33219278.
The point is that 2^n have 1 decimal digit for n 4 ;-)
As it happens, 33219278,
The 10,000,000 digit prime would have an exponent of over
3010299.956, or 3010300
which is found by taking (log 2 * 10,000,000)
Actually, it's log10(2) * 10,000,000, which is a different number. Of
course, since I'm not at home, I can't figure out _that_ number offhand,
but see the posts
The 10,000,000 digit prime would have an exponent of over
3010299.956, or 3010300
which is found by taking (log 2 * 10,000,000)
J. Zylstra
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