Re: getting socket identification numbers

2001-01-03 Thread Sivakatirswami
If you are going one-on-one, then you can just have the stack show your id, and use a different method (email, etc) to communicate that to the target. "different method" (to get the IP) which we once used with the now defunct Marionette (4 years ago) that DID rely on a known third server

Re: getting socket identification numbers

2001-01-02 Thread Mark Talluto
on 1/2/01 3:10 PM, [EMAIL PROTECTED] at [EMAIL PROTECTED] wrote: I'm working on a chat program, bolstered by the help of others on the list. I want to get the IP address of the person chatting with me, even if they don't know how to get it themselves. I investigated hostAddress and

Re: getting socket identification numbers

2001-01-02 Thread Mark Talluto
on 1/2/01 3:10 PM, [EMAIL PROTECTED] at [EMAIL PROTECTED] wrote: I'm working on a chat program, bolstered by the help of others on the list. I want to get the IP address of the person chatting with me, even if they don't know how to get it themselves. I investigated hostAddress and

Re: getting socket identification numbers

2001-01-01 Thread andu
This is a multi-part message in MIME format. --=_NextPart_000_0034_01C0740A.EED97EA0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable I do not have a permanent domain id. I can get a temporary one and set = up my mc server from my home pc,

Re: getting socket identification numbers

2001-01-01 Thread Geoff Canyon
At 3:53 PM -0500 1/1/01, Sound Medicine, Inc. wrote: I do not have a permanent domain id. I can get a temporary one and set up my mc server from my home pc, but the id #s change every time I log on. Is there a simple way for MC to initiate and identify these numbers for use in chat stacks

Re: getting socket identification numbers

2001-01-01 Thread michael kann
I'm working on a chat program, bolstered by the help of others on the list. I want to get the IP address of the person chatting with me, even if they don't know how to get it themselves. I investigated hostAddress and peerAddress but ran into a puzzle -- can anyone explain it? I'm chatting on my