Decided to run up2date -u
I noticed that our website was tossing off mysql errors. Quickly
realized that mysql was down. Went to restart but it couldn't find
mysqld_safe, mysqld, mysqladmin, etc.
I used locate and it couldn't find the binaries anywhere...it appears
that up2date -u had
Glyn Astill wrote:
I'd back up the data directories then try and then re-install mysql (sorry, I
know little about red hat and it's package management). It shouldn't overwrite
your data if it's already present anyway.
Great. Thought that would be the case, but without sleep, I wasn't sure.
Bad news: I have a slow query that doesn't appear to be using an index
even if I force it.
Good news: the forehead shaped dent in my desk is really progressing well.
Here's the query:
SELECT DISTINCT poster_data.*
FROM poster_data, poster_prodcat, poster_categories
WHERE
One of the list readers (thanks Brent!) suggested using a full text
index on the category names field. Queries dropped from 10-49 seconds
down to 0.0085
Thanks for the emails folks!
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I'm trying to wrap my head around dealing with people in a table that
have multiple names or akas.
I run an entertainment news site and have to deal with people like
Pamela Anderson (who was once Pamela Lee, Pamela Anderson Lee, Pamela
Denise Anderson), Eva Longoria (who's now Eva Longoria
What version of MySQL are you using?
Our host, Interland, is running a pre-3.23 version.
back, 3.23.x supports them), then just issue a similar query and store
the result yourself...
Should've thought of that myself. Thanks.
Not wanting to reinvent the wheel here, I wonder if anyone else has ever
done a rating system.
There'll be two columns: title_id for the title of the movie being rated and
then a rating from one to ten.
What would be the most efficient SQL statement to find a title's weighted
average?
Many
[snip]
What do you mean by weighted? Taking into account the number of votes for
each and then weighting them against each other?
[/snip]
Yes, essentially each individual movie will show its raw average (people
think this movie is a 7/10) while an overall top rated list will take into
affect
-Original Message-
From: Andrew K-C [mailto:[EMAIL PROTECTED]]
you might be able to do a ORDER BY weighted DESC to get them to come out
in order of weight
Thanks...I'll give that a try...
Hmm, the only problem with that query is that it doesn't get it quite
snip
SELECT @totalVotes:=COUNT(titleid) FROM movieratings
/snip
Thanks for the reply.
Alas, the above query syntax gives me an error 1064.
--
Ian Evans
Chairman Executive Producer
Digital Hit Entertainment
http://www.digitalhit.com
[snip]
WHERE ap_type='Original Movie Poster'
ORDER BY sort_title ASC
HAVING sort_title LIKE 'G%'
ORDER BY sort_title ASC
You may have to swap the HAVING and ORDER BY lines of the query,
[/snip]
Thanks so much. There was a slight syntax change, replacing your first ORDER
BY with a GROUP BY, but
Ah, after I write my SQL SELECT query I discover that you can't use WHERE
with an alias.
Here's what I'm trying to do:
SELECT posterdata.*, IF (aptitle LIKE 'The %',SUBSTRING(aptitle,5), IF
(aptitle LIKE 'A %',SUBSTRING(aptitle,3),IF (aptitle LIKE 'An
%',SUBSTRING(aptitle,4),aptitle))) AS
I have a SQL statement that I use to grab movie profiles. When I constructed
the input form, I decided I didn't want to use blank entries for tables that
didn't have a entry for that particular film e.g. a poster wasn't available
for sale.
This SQL statement in PHP works fine when EVERY table
Thanks for your pointer. This SQL statement ended up working:
Thanks for your pointer! This ended up working for me:
SELECT * FROM profiles
LEFT JOIN allposters ON (profiles.titlesid = allposters.titlesid)
LEFT JOIN officialsites ON (profiles.titlesid = officialsites.titlesid)
LEFT JOIN titles
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