> ...So the table song_x_artist contains references to all artists in a
> song and vice-versa. (Field names correspond between tables.)
How does song_x_artist reference the other databases? Is there a way to set
up a field to always be a reference to another table?
I am not quite sure what you
Hello all,
[~~I guess I could do something like MySQL>select FROM "Songs" where
"artists" contains $currentArtist~~]
I have a sampling section on a site that I am working on and am trying to
find out how to display a table of the artists featured in that song. The
sample section works as follows
I have been working all night on something then Outlook Express crashed my
machine and now after restarting, MySQL service will not start. I am running
it on Win2K Pro and have had no probs until just now. I right click on it
and choose WinNT::Start the service. The dialog comes up asking if I wan
I just started going into some of the other files that will need updating
and I have run into another little prob dealing with the same thing
Here it is, maybe you can shed some light on it for me.
$result=mysql_db_query("$DBName","SELECT Date,BuyerID,OrderNumber FROM
Buyers");
The $Result v
> .. if mysql_db_query is what you're using.
Actually below is waht I am using...
mysql("$DBName","INSERT INTO Category VALUES('$Category','')");
After your response, I changed it to...
mysql_select_db("$DBName");
mysql_query("INSERT INTO Category VALUES('$Category','')");
Works like a charm
> It means something is out of date...looks like you need an update of
> something...
This is the line 7 that it is talking about How do I know what is out of
date and how to fix it? Are there any utilities out there for updating
scripts or do I need to manually go into each .php file and upd
mysql_query() instead ) what the warning
says???
Any help would be greatly appreciated.
TIA
-Robbie Newton
-
Before posting, please check:
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