Hi;
I have this command:
create table if not exists categoriesRelationships (ID integer
auto_increment primary key, Store varchar(60), Parent integer not null,
foreign key (Parent) references categories (ID), Child integer not null,
foreign key (Child) references categories (ID)) engine=innodb;
: Victor Subervi [mailto:victorsube...@gmail.com]
Sent: Monday, February 14, 2011 3:09 PM
To: mysql@lists.mysql.com
Subject: Foreign Key Error
Hi;
I have this command:
create table if not exists categoriesRelationships (ID integer
auto_increment primary key, Store varchar(60), Parent integer
Hi;
Can someone please explain to me why Passengers.weight comes up null for the
last value sometimes, and other times it comes up with the value 155??
mysql select p.id, c.id, p.name, p.weight, m.amount, p.round_trip,
c.first_name, c.middle_name, c.last_name, c.suffix, c.sex, p.confirmation,
Hi;
I have the following query:
select * from spreadsheets s join products p on p.Item=s.Item join
categories c on p.Category=c.ID where s.Client=%s order by p.category,
c.parent;
mysql describe products;
+-+--+--+-+-++
| Field | Type
: Victor Subervi victorsube...@gmail.com
Sent: Aug 24, 2010 1:14 PM
To: mysql@lists.mysql.com
Subject: Complex Select Query
Hi;
I have the following query:
select * from spreadsheets s join products p on p.Item=s.Item join
categories c on p.Category=c.ID where s.Client=%s order by p.category
Hi;
I have this code:
select f.id from Flights f join Planes p where f.plane_id=p.id and
p.in_service=1
mysql describe Flights;
+-+---+--+-+-++
| Field | Type | Null | Key | Default | Extra |
Hi;
mysql alter table personalData drop foreign key Store;
ERROR 1025 (HY000): Error on rename of './test/personalData' to
'./test/#sql2-14ce-a61' (errno: 152)
mysql describe personalData;
+---+--+--+-+++
| Field |
on Store.
How?
TIA,
V
Regards
John Daisley
Microsoft SQL Server 2005/2008 Database Administrator
Certified MySQL 5 Database Administrator
Certified MySQL 5 Developer
Cognos BI Developer
Telephone: +44 (0)7918 621621
Email: john.dais...@butterflysystems.co.uk
On 22 July 2010 14:02, Victor
On Thu, Jul 22, 2010 at 9:09 AM, John Daisley daisleyj...@googlemail.comwrote:
Sorry, my bad! Must learn to read the whole message!!
This can be caused because when a foreign key is created mysql adds an
index key to the column in addition to the foreign key. Why I'm not sure,
but I'm
Hi;
Perhaps I have a conflict of terms here, but my googling mysql data
dictionary turned up material that didn't seem to correspond with my
problem. In python I can create dictionaries:
my_dict = {'1': 'one', '2': 'two'}
Now, I would like to create the equivalent of an enum in which I could
Hi;
I have the following:
create table pics (
picture_id int auto_increment primary key,
product_sku int not null primary key,
picture_num int not null,
picture_desc varchar(100),
picture_data longblob
);
which doesn't work I need to auto_increment and declare primary key on two
2010/6/29 João Cândido de Souza Neto j...@consultorweb.cnt.br
As far as I know, if you have an auto_increment primary key, you cant have
any other field in its primary key.
Makes sense. Actually, I was just copying what someone else gave me and
adding the auto_increment, then I got to
2010/6/29 João Cândido de Souza Neto j...@consultorweb.cnt.br
I think the best, or may be the right way is to use picture_id as primary
key and a unique index to product_sku.
Yes, sounds good. So the purpose, then, is to speed lookups on fields
commonly accessed. I'd forgotten that.
Thanks,
V
Hi;
mysql alter table Flights type=InnoDB;
Query OK, 1 row affected, 1 warning (0.01 sec)
Records: 1 Duplicates: 0 Warnings: 0
mysql alter table Flights add pilot_id int not null;
Query OK, 1 row affected (0.01 sec)
Records: 1 Duplicates: 0 Warnings: 0
mysql alter table Flights add foreign
Problem solved. I tried everything that *should* have worked and didn't.
Then I just wiped the test database and started with everything *fixed* (all
engine=innodb, all keys of same type, etc.) and it all worked.
V
On Tue, Jun 22, 2010 at 11:53 AM, jayabharath jbhara...@gmail.com wrote:
Hi Victor,
The actual problem is with the key field.
Flights.pilot_id is set to INT NOT NULL and you had specified Pilots.id to
INT NULL.
You have to change both the columns to NULL or else NOT NULL to avoid the
This is just for the sake of future googlers of this thread. The correct
mysql command is:
ursor.execute('create table if not exists Passengers (id int(11)
auto_increment primary key, flights_id int(11) not null, customer_id int(11)
not null, foreign key (flights_id) references Flights (id),
Hi;
When I try to execute this code from my Python script, I get this error:
Traceback (most recent call last):
File
/var/www/html/creative.vi/clients/sea-flight/reservations/create_edit_bags3.py,
line 38, in ?
create_edit_bags3()
File
I'm canceling this thread. It belongs in the Python list. Sorry!
V
On Fri, May 21, 2010 at 1:24 PM, Victor Subervi victorsube...@gmail.comwrote:
Hi;
When I try to execute this code from my Python script, I get this error:
Traceback (most recent call last):
File
/var/www/html/creative.vi
On Wed, May 19, 2010 at 12:02 PM, Shawn Green shawn.l.gr...@oracle.comwrote:
Victor Subervi wrote:
On Wed, May 19, 2010 at 10:59 AM, Shawn Green shawn.l.gr...@oracle.com
wrote:
Shawn Green wrote:
look again closely at your FK definitions. The pattern should be
FOREIGN KEY
On Tue, May 18, 2010 at 2:23 PM, Shawn Green shawn.l.gr...@oracle.comwrote:
Shawn Green wrote:
I may be confused but how can the ID of the Passengers table be both the ID
of the Flight they are taking and their Customer ID at the same time?
On Wed, May 19, 2010 at 10:59 AM, Shawn Green shawn.l.gr...@oracle.comwrote:
Shawn Green wrote:
AH! that's your mistake. You think that creating the FK will also create
the column. That does not happen. You have to define the table completely
before you can associate the columns on this
Hi;
mysql create table if not exists Passengers (id int unsigned auto_increment
primary key, foreign key (id) references Flights (flights_id), foreign key
(id) references Customers (customer_id), name varchar(40), weight
tinyint(3));
Query OK, 0 rows affected (0.00 sec)
mysql select c.first_name,
apparently it didn't like my foreign key. Do I need to do something with
the table I'm referencing or what?
TIA,
V
On Tue, May 18, 2010 at 3:44 PM, Victor Subervi
victorsube...@gmail.comwrote:
Hi;
mysql create table if not exists Passengers (id int unsigned
auto_increment
primary key, foreign
On Tue, May 18, 2010 at 1:09 PM, Shawn Green shawn.l.gr...@oracle.comwrote:
Johan De Meersman wrote:
For additional details about failed FK attempts, check the error details in
the SHOW INNODB STATUS report.
I get this:
100518 10:26:22 Error in foreign key constraint of table
On Thu, Jan 14, 2010 at 1:35 AM, Chris W 4rfv...@cox.net wrote:
I think the reason the other poster was so harsh is because others have
suggested the right way to do it, if not in a lot of detail, and you have
just argued with them.
I don't recall anyone doing that. I don't recall arguing. I
On Mon, Jan 11, 2010 at 3:21 PM, mos mo...@fastmail.fm wrote:
At 09:56 AM 1/11/2010, Johnny Withers wrote:
Victor,
The temporary table solution is not a good one. Use a single table and
store
each item put into a cart identified by the session ID of the user. A
process should clean out
On Wed, Jan 13, 2010 at 2:33 PM, Johnny Withers joh...@pixelated.netwrote:
No one designs a shopping cart system this way.
http://www.google.com/search?q=shopping+cart+database+table+design
If you are dead set on this crazy design it doesn't matter if you put the
temp tables in the main
On Mon, Jan 11, 2010 at 10:35 AM, Baron Schwartz ba...@xaprb.com wrote:
Victor,
On Sun, Jan 10, 2010 at 1:20 PM, Victor Subervi victorsube...@gmail.com
wrote:
Hi;
I have a shopping cart that will spawn a tmp table for every shopping
cart
instance. Would it be better to create
On Mon, Jan 11, 2010 at 10:49 AM, Baron Schwartz ba...@xaprb.com wrote:
Victor,
That strikes me as messy. Each tmp table has as many rows as necessary
for
the products that are to be bough. To do as you say I would have to
create a
table with a zillion rows to accommodate however many
On Mon, Jan 11, 2010 at 11:38 AM, Keith Murphy bmur...@paragon-cs.comwrote:
Victor,
Don't want to butt in, and not trying to be rude, but he gave you advice.
You don't seem inclined to take it. How else can he, or anyone else, help
you? Clearly you don't understand some fundamental issue
Hi;
I have a shopping cart that will spawn a tmp table for every shopping cart
instance. Would it be better to create a separate database for these instead
of having them in the same database as all the other tables for the shopping
cart?
TIA,
Victor
--
The Logos has come to bear
On Fri, Jan 8, 2010 at 2:26 AM, Thiyaghu CK theyaho...@gmail.com wrote:
Hi Victor,
You have given space after the comma(shown here: ('Small, Medium,
XSmall')). Take out the space and try, it will work.
Example:
mysql insert into products(sizes) values ('Small,Medium,small,medium');
Query
On Fri, Jan 8, 2010 at 9:29 AM, Thiyaghu CK theyaho...@gmail.com wrote:
Hi Victor,
Take out the double quotes from[ ('Small,Medium,XSmall'),
('teal_E2725B,black_FF,yellow_9ACD32')]. Its working fine for me.
mysql insert into products (sizes, colorsShadesNumbersShort)
OK, guys, I'm totally confused:
mysql insert into products (SKU, Category, Name, Title, Description, Price,
SortFactor, Availability, OutOfStock, Weight, ShipFlatFee, ShipPercentPrice,
ShipPercentWeight, sizes, colorsShadesNumbersShort) values (prodSKU1,
prodCat1, name1, title1, descr, 12.34,
Hi;
The following doesn't work with or without enclosing the sets in quotes:
update products set SKU=prodSKU2, Category=prodCat1, Name=name2,
Title=title2, Description=descr, Price=22.55, SortFactor=500,
Availability=1, OutOfStock=0, Weight=5.5, ShipFlatFee=10.0,
ShipPercentPrice=5,
there.
No, that thew the same errors. I know you have to enclose the sets in
parentheses and individually quote each element.
V
- michael dykman
On Wed, Jan 6, 2010 at 9:32 AM, Victor Subervi victorsube...@gmail.com
wrote:
On Wed, Jan 6, 2010 at 10:23 AM, Michael Dykman mdyk...@gmail.com
wrote
On Wed, Jan 6, 2010 at 12:14 PM, Michael Dykman mdyk...@gmail.com wrote:
so you dropped the quotes around the unneccessarily bracketed
expression? It's hard to diagnose when your example isn't even what
you think is syntactically correct.
Here's my example again. Syntactically correct. From
On Wed, Jan 6, 2010 at 2:18 PM, Hassan Schroeder hassan.schroe...@gmail.com
wrote:
On Wed, Jan 6, 2010 at 11:39 AM, Victor Subervi victorsube...@gmail.com
wrote:
Here's my example again. Syntactically correct. From my original post:
update products set SKU=prodSKU2, Category=prodCat1
On Wed, Jan 6, 2010 at 2:34 PM, Hassan Schroeder hassan.schroe...@gmail.com
wrote:
On Wed, Jan 6, 2010 at 1:25 PM, Victor Subervi victorsube...@gmail.com
wrote:
mysql update products set SKU=prodSKU2, Category=prodCat1,
Name=name2, Title=title2, Description=descr, Price=22.55
On Wed, Jan 6, 2010 at 2:40 PM, Michael Dykman mdyk...@gmail.com wrote:
How about you show us the schema for the table so we know what is
defined as what?
Done in last email.
Also, as the update does succeed, it would be interesting to see what
value actually got stored. After you have
On Mon, Jan 4, 2010 at 10:40 AM, Arthur Fuller fuller.art...@gmail.comwrote:
The ProductPackages table is what is known as an associate table, and is
used to implement a many-to-many relationship. You only need it if a given
product can be in multiple packages. If not, then you can eliminate
On Sat, Jan 2, 2010 at 11:20 AM, Arthur Fuller fuller.art...@gmail.comwrote:
Hi Victor.
I think that the first thing you need to consider is whether a product can
be in more than one package, and second is whether a package can be in
another package. Also, I don't know why you need to
On Sat, Jan 2, 2010 at 12:03 PM, prabhat kumar aim.prab...@gmail.comwrote:
primary key
Oh! PK is primary key!
a compound key is a key that consists of 2 or more attributes that uniquely
identify an entity occurrence.
Thanks.
V
On Sat, Jan 2, 2010 at 11:20 AM, Arthur Fuller fuller.art...@gmail.comwrote:
Hi Victor.
I think that the first thing you need to consider is whether a product can
be in more than one package, and second is whether a package can be in
another package. Also, I don't know why you need to
Hi;
I have a table with products for a store to sell. I need to autogenerate
from code a table or series of tables into which I can enter (and from which
I can retrieve) the ID numbers of products which I am going to associate
together and their package price. Product associations will vary, in
Hi;
mysql describe products;
+--+---+--+-+-++
| Field|
Type
| Null | Key |
On Fri, Jan 1, 2010 at 4:34 PM, Don Read don_r...@att.net wrote:
On Fri, 1 Jan 2010 14:34:48 -0500 Victor Subervi said:
Hi;
snip
The following insert chokes when I try to insert multiple values from the
sets:
insert into products (SKU, Category, Name, Title, Description, Price
Hi;
mysql select * from products;
On Sun, Dec 27, 2009 at 11:27 AM, Mattia Merzi mattia.me...@gmail.comwrote:
2009/12/27 Victor Subervi victorsube...@gmail.com:
mysql select * from products;
[...]
mysql select last_insert_id() from products;
[...]
Now, I was expecting 1, not 0! What up?
[...] LAST_INSERT_ID
On Sun, Dec 27, 2009 at 12:00 PM, Michael Dykman mdyk...@gmail.com wrote:
last_insert_id() returns the last id auto-incremented in *the current
session*. If you disconnect and reconnect, it can not be retrieved.
Ahah! So how do I retrieve the last id inserted irrespective of connection?
TIA,
On Sun, Dec 27, 2009 at 1:30 PM, Gary Smith li...@l33t-d00d.co.uk wrote:
Victor Subervi wrote:
On Sun, Dec 27, 2009 at 12:00 PM, Michael Dykman mdyk...@gmail.com
wrote:
last_insert_id() returns the last id auto-incremented in *the current
session*. If you disconnect and reconnect
Hi;
I have the following:
mysql select SKU, Quantity, Name, Price, p.sizes,
p.colorsShadesNumbersShort from tem126080739853 t join products p on
t.ProdID-p.ID;
Empty set (0.00 sec)
mysql select * from tem126080739853;
+++--+-+--+
| ID |
On Mon, Dec 14, 2009 at 12:37 PM, Peter Brawley peter.braw...@earthlink.net
wrote:
... on t.ProdID-p.ID;
Your join clause subtracts the two IDs, so it's on IDs that differ, and
apparently there aren't any.
I beg to differ:
mysql select SKU, Quantity, Name, Price, p.sizes,
On Mon, Dec 14, 2009 at 1:04 PM, Peter Brawley
peter.braw...@earthlink.netwrote:
...on t.ProdID-p.ID... _subtracts_ the two IDs. To match them use '='
rather than '-'.
Thank you for all of you that caught that.
V
Hi;
mysql insert into tem126072414516 (ProdID, Quantity) values (2, 2);
ERROR 1062 (23000): Duplicate entry '2' for key 2
mysql select * from tem126072385457;
Empty set (0.00 sec)
mysql describe tem126072385457;
+--+-+--+-+-++
| Field|
On Sun, Dec 13, 2009 at 12:21 PM, Pinter Tibor tib...@tibyke.hu wrote:
Victor Subervi wrote:
Hi;
mysql insert into *tem126072414516* (ProdID, Quantity) values (2, 2);
mysql select * from *tem126072385457*;
mysql insert into *tem126072414516* (ProdID, Quantity) values (2, 2);
ERROR 1064
Hi;
I have a column defined as a set. How do I insert data into that column?
Please give me an example.
TIA,
Victor
On Sat, Dec 12, 2009 at 10:58 AM, David Giragosian dgiragos...@gmail.comwrote:
On Sat, Dec 12, 2009 at 9:54 AM, Victor Subervi
victorsube...@gmail.comwrote:
Hi;
I have a column defined as a set. How do I insert data into that column?
Please give me an example.
TIA,
Victor
Lots
Hi;
mysql update products set sizes=('Small', 'Large') where ID=0;
Query OK, 0 rows affected, 1 warning (0.00 sec)
Rows matched: 1 Changed: 0 Warnings: 1
mysql select sizes, colorsShadesNumbersShort from products where ID=0;
+---+--+
| sizes |
On Fri, Dec 11, 2009 at 4:48 AM, Jørn Dahl-Stamnes
sq...@dahl-stamnes.netwrote:
On Friday 11 December 2009 10:38, Victor Subervi wrote:
Hi;
mysql update products set sizes=('Small', 'Large') where ID=0;
Query OK, 0 rows affected, 1 warning (0.00 sec)
Rows matched: 1 Changed: 0
On Fri, Dec 11, 2009 at 4:48 AM, Jørn Dahl-Stamnes
sq...@dahl-stamnes.netwrote:
On Friday 11 December 2009 10:38, Victor Subervi wrote:
Hi;
mysql update products set sizes=('Small', 'Large') where ID=0;
Query OK, 0 rows affected, 1 warning (0.00 sec)
Rows matched: 1 Changed: 0
On Fri, Dec 11, 2009 at 4:43 AM, cars...@bitbybit.dk wrote:
On Fri, 11 Dec 2009 04:38:01 -0500, Victor Subervi
victorsube...@gmail.com
wrote:
Hi;
mysql update products set sizes=('Small', 'Large') where ID=0;
Query OK, 0 rows affected, 1 warning (0.00 sec)
Rows matched: 1 Changed
On Fri, Dec 11, 2009 at 5:13 AM, cars...@bitbybit.dk wrote:
On Fri, 11 Dec 2009 05:09:52 -0500, Victor Subervi
victorsube...@gmail.com
wrote:
mysql update products set sizes=('Small', 'Large') where
SKU='prodSKU1';
Query OK, 0 rows affected, 1 warning (0.00 sec)
Rows matched: 1
On Fri, Dec 11, 2009 at 5:33 AM, cars...@bitbybit.dk wrote:
On Fri, 11 Dec 2009 05:28:41 -0500, Victor Subervi
victorsube...@gmail.com
wrote:
On Fri, Dec 11, 2009 at 5:13 AM, cars...@bitbybit.dk wrote:
On Fri, 11 Dec 2009 05:09:52 -0500, Victor Subervi
victorsube...@gmail.com
On Fri, Dec 11, 2009 at 8:43 AM, Johan De Meersman vegiv...@tuxera.bewrote:
On Fri, Dec 11, 2009 at 11:19 AM, Mark Goodge m...@good-stuff.co.uk
wrote:
Jørn Dahl-Stamnes wrote:
On Friday 11 December 2009 10:38, Victor Subervi wrote:
Hi;
mysql update products set sizes=('Small
On Sun, Dec 6, 2009 at 2:42 PM, Steve Edberg edb...@edberg-online.comwrote:
At 1:26 PM -0500 12/6/09, Victor Subervi wrote:
Hi;
I have the following:
mysql select * from categoriesProducts as c inner join
relationshipProducts
as r on c.ID = r.Child inner join categoriesProducts as p
Hi;
I posted this Saturday. Perhaps it's too challenging for those who read it
to answer. I hope someone can.
I need to write a select statement that enables me to select column 'ID'
from a table where a certain value is found in an enum of a specific column.
For example...
select column_type
On Mon, Dec 7, 2009 at 8:08 AM, Tom Worster f...@thefsb.org wrote:
On 12/7/09 5:26 AM, Victor Subervi victorsube...@gmail.com wrote:
Hi;
I posted this Saturday. Perhaps it's too challenging for those who read
it
to answer. I hope someone can.
I need to write a select statement
Hi;
I have the following:
mysql select * from categoriesProducts as c inner join relationshipProducts
as r on c.ID = r.Child inner join categoriesProducts as p on r.Parent = p.ID
where p.Category = prodCat2;
ERROR 1054 (42S22): Unknown column 'prodCat2' in 'where clause'
mysql describe
Hi;
I remember vaguely how to do this but don't know how to google it:
show tables like categories$;
such that it will return tables such as:
categoriesProducts, categoriesPrescriptions, etc.
TIA,
Victor
On Sat, Dec 5, 2009 at 11:09 AM, Michael Dykman mdyk...@gmail.com wrote:
show tables like 'categories%';
Thanks.
V
Hi;
I need to write a select statement that enables me to select column 'ID'
from a table where a certain value is found in an enum of a specific column.
For example...
select column_type from information_schema.columns where
table_name='products' and column_name='Categories';
will give me the
Hi;
mysql insert into categories (Category, Parent) values ('test', NULL);
ERROR 1062 (23000): Duplicate entry '0' for key 1
mysql describe categories;
+--+-+--+-+-+---+
| Field| Type| Null | Key | Default | Extra |
Oops. Never mind.
V
On Sat, Dec 5, 2009 at 1:19 PM, Victor Subervi victorsube...@gmail.comwrote:
Hi;
mysql insert into categories (Category, Parent) values ('test', NULL);
ERROR 1062 (23000): Duplicate entry '0' for key 1
mysql describe categories
Hi;
I would like to create a table out of merging the fields in other,
previously created tables. I have the following syntax which doesn't work:
create table products union (b0basics, b0fieldValues, s0prescriptions,
s0prescriptions0doctors, s0prescriptions0patient, pics);
Please advise.
TIA,
On Sun, Nov 22, 2009 at 9:29 PM, Gavin Towey gto...@ffn.com wrote:
The form would be like:
CREATE TABLE products
SELECT b0basics, b0fieldValues, s0prescriptions,
s0prescriptions0doctors, s0prescriptions0patient, pics FROM table1
UNION
SELECT b0basics, b0fieldValues, s0prescriptions,
On Thu, Nov 19, 2009 at 9:34 PM, Ye Yuan yuan4...@gmail.com wrote:
Hi Victor,
It looks to me the foreign key syntax is wrong. Can you create the
Relationship table on your database by using below ddl?
create table if not exists Relationship
(ID integer auto_increment primary key,
Parent
Hi;
I don't claim to be an expert in MySQL. The following code was largely
supplied to me by someone who was. I don't really understand foreign keys.
He wrote this off the top of his head, and it's throwing an error. Here's
the python code:
def catTree():
user, passwd, db, host = login()
Hi;
I created a user and then granted privileges:
grant all to victor identified by 'pw';
Looked good. Tried to log in as victor an no go. Please advise.
Victor
Never mind. Had to add @'localhost'
On Mon, Nov 9, 2009 at 4:20 PM, Victor Subervi victorsube...@gmail.comwrote:
Hi;
I created a user and then granted privileges:
grant all to victor identified by 'pw';
Looked good. Tried to log in as victor an no go. Please advise.
Victor
/index.php?title=Storing_files_in_the_database
Regards,
Gavin Towey
-Original Message-
From: Victor Subervi [mailto:victorsube...@gmail.com]
Sent: Thursday, October 15, 2009 12:05 PM
To: mysql@lists.mysql.com
Subject: Inserting an Image
Hi;
I have successfully inserted
Hi;
I have successfully inserted images, like yesterday, before into MySQL with
the following code:
sql = 'update productsX set pic1=%s where ID=2;' % pic1
cursor.execute(sql)
where pic1 is simply an image uploaded through a form then sent over without
any alteration to another
4, 2009 at 2:04 PM, Victor Subervi victorsube...@gmail.com
wrote:
Hi;
I have the following python code:
sql = 'insert into products values(%s, %s, %s, %s, %s, %s, %s, %s,
%s,
%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s);', (id, name, title,
description, price, bedrooms, bathrooms
) values('1', 'name1',
'title1', 'descr1', '1.1', '2', '1', 'New', '1.5', 'new', 'princesse',
'princesse', '123 princesse', 'Not furnished', '', '', '', '', '', '');
Values are enclosed in single quotes for SQL.
- Original Message - From: Victor Subervi
victorsube...@gmail.com
Hi;
I have the following python code:
sql = 'insert into products values(%s, %s, %s, %s, %s, %s, %s, %s, %s,
%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s);', (id, name, title,
description, price, bedrooms, bathrooms, conditions, acreage, construction,
location, estate, address, furnished,
*From:* Victor Subervi [mailto:victorsube...@gmail.com]
*Sent:* Thursday, October 01, 2009 3:04 PM
*To:* Gavin Towey; mysql@lists.mysql.com
*Subject:* Re: Nested Joins
Well, your syntax is *exactly* what I had (with a few cosmetic changes).
I've been over the MySQL manual on joins
Hi;
I get the following error:
*SQL query:*
SELECT ID, Item
FROM products
JOIN categories ON categories.ID = products.Category
LIMIT 0 , 30;
*MySQL said:*
#1052 - Column 'ID' in field list is ambiguous
Please note the error is about ambiguity. products has an ID field and so
does categories.
Thanks
V
On Fri, Oct 2, 2009 at 11:08 AM, Mark Goodge m...@good-stuff.co.uk wrote:
Victor Subervi wrote:
Hi;
I get the following error:
*SQL query:*
SELECT ID, Item
FROM products
JOIN categories ON categories.ID = products.Category
LIMIT 0 , 30;
*MySQL said:*
#1052 - Column 'ID
Hi;
I'm new to join statements. Here's my python syntax:
cursor.execute('select * from %s left join products on
%s.Item=products.Item (left join categories on
products.Category=categories.ID);' % (client, client))
I believe it's clear how I want to nest, but I don't know how to repair my
On Thu, Oct 1, 2009 at 4:03 PM, Gavin Towey gto...@ffn.com wrote:
Joins aren't nested like that, unless you use a subquery. I think you just
need to remove the parens around the second join.
I tried that and no go :(
For better help:
1. show the real SQL -- echo the statement. Most
/articles/mysql-db-design-ch5.pdf
http://dev.mysql.com/doc/refman/5.1/en/join.html
Regards,
Gavin Towey
*From:* Victor Subervi [mailto:victorsube...@gmail.com]
*Sent:* Thursday, October 01, 2009 2:25 PM
*To:* Gavin Towey; mysql@lists.mysql.com
*Subject:* Re: Nested Joins
On Thu, Oct
Hi;
Please give me the syntax below such that I can force the insert statements
to use only selected values (item1, item2, item3):
create table (field SOMETHING_HERE item1 item2 item3,
...
)
TIA,
Victor
That's it! Thanks,
V
On Tue, Sep 29, 2009 at 12:13 PM, David Giragosian dgiragos...@gmail.comwrote:
On Tue, Sep 29, 2009 at 11:09 AM, Victor Subervi victorsube...@gmail.com
wrote:
Hi;
Please give me the syntax below such that I can force the insert
statements
to use only selected
Hi:
I have the following python code:
import os
os.system(mysqldump -u root -pPASSWORD --opt spreadsheets dump.sql)
This nicely creates the file...but the file is empty! The database exists
and has lots of data, I double-checked it. If there is nothing wrong with my
code, is there some way to do
-
From: news [mailto:n...@ger.gmane.org] On Behalf Of Emile van Sebille
Sent: Wednesday, September 02, 2009 7:18 AM
To: mysql@lists.mysql.com
Cc: python-l...@python.org
Subject: Re: Problem w/ mysqldump
On 9/2/2009 3:43 AM Victor Subervi said...
Hi:
I have the following python
for a mysql dump tool ;-)
Mysql dump is the better way to go in either situation.
-Original Message-
From: Victor Subervi [mailto:victorsube...@gmail.com]
Sent: Wednesday, September 02, 2009 1:43 PM
To: Daevid Vincent; mysql@lists.mysql.com
Subject: Re: Problem w/ mysqldump
I
'; database exists
This is the answer.
2009/8/24 Victor Subervi victorsube...@gmail.com
Hi,
I have the following python code:
cursor.execute('create database if not exists spreadsheets;')
cursor.execute('use spreadsheets;')
but it generates this warning:
Warning (from warnings module):
File
Hi,
I have the following python code:
cursor.execute('create database if not exists spreadsheets;')
cursor.execute('use spreadsheets;')
but it generates this warning:
Warning (from warnings module):
File C:\Python25\mysqlConverter.py, line 140
cursor.execute('use spreadsheets;')
Hi;
I would like to test the following:
update maps set map where site=mysite;
to see if there is such an entry in maps. If there is, then update. If there
is not, then I would like to execute an insert statement. How do I do that?
TIA,
Victor
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