I'm sorry for missing the key word "not", it should be SELECT * FROM approvals
WHERE adminname != 'admin2'and photo_uid not in (select photo_uid from
approvals where adminname='admin2'),
在2009-11-22,shjunsin 写道:
>Hi\I think you can achieve this using a
Hi\I think you can achieve this using a single query like this: SELECT * FROM
approvals WHERE adminname != 'admin2'and photo_uid in (select photo_uid from
approvals where adminname='admin2'), of course, maybe it's not the best
solution, just for your information.在2009-11-22,"Ashley M. Kirchner"