Hi,
I've the following query
SELECT COUNT(players_id) AS players_count
FROM players
WHERE teams_id > 0
GROUP BY teams_id
ORDER BY players_count DESC
However, I've another field called original_teams_id and want to include the
COUNT with players_count, when original_teams_id = teams_id
Cheers
Ne
On Monday 18 September 2006 14:55, Brent Baisley wrote:
> You might try changing it to distinct if you are looking for unique count
> of ids from each. SELECT a.a,aa,COUNT(DISTINCT b.id),COUNT(DISTINCT c.id)
> FROM...
This return 0 or 1 for b.id (1 if there is 1 or more records) and the correct
v
y
work to filter out duplicates like NULL. Otherwise you'll need to do it long hand:
SELECT a.a,aa,COUNT(IF(b.id IS NULL,0,1)),COUNT(IF(c.id IS NULL,0,1)) FROM...
- Original Message -
From: "Jørn Dahl-Stamnes" <[EMAIL PROTECTED]>
To:
Sent: Monday, September 18, 2006
Hi Jörn,
I don't think you can do it in one SELECT
as you'll get the same number (the max)
as soon as the COUNT goes above zero.
If you think about how your resultset looks
if you remove your COUNTs it becomes clearer.
Say that for one a.a you have 3 matches in b
and 2 matches in c, this will resu
I have a query like:
SELECT a.a,aa,COUNT(b.id),COUNT(c.id) FROM a LEFT JOIN b ON (b.a_ref=a.id)
LEFT JOIN c ON (c.a_ref=a.id);
But it seems like SQL is mixing up the two count's. I get the count from table
c instead of table b for the first occurence of COUNT in the query.
Can I use two COUNT'
Andras -
If you create an additional table which contains all possible values
for the order_status field, you can do this. Something like this:
create table orderstatus (
statusname varchar(25) );
insert into orderstatus (statusname) values ('pending'),
('processing'), ('shipped');
Next yo
Hello,
I would like merge this 3 query into a single one...
SELECT COUNT(*) AS count FROM orders WHERE order_status = 'pending',
SELECT COUNT(*) AS count FROM orders WHERE order_status = 'processing',
SELECT COUNT(*) AS count FROM orders WHERE order_status = 'shipped',
I could do :
SELECT orde
. Then total number of
records is the last sum-up.
- Original Message -
From: "G r e g L a w r i e" <[EMAIL PROTECTED]>
To: "MySQL Mailing List" <[EMAIL PROTECTED]>
Sent: Tuesday, August 21, 2001 2:15 PM
Subject: SELECT COUNT(*) question ...
> Howdy all,
&
Howdy all,
I have two tables as described further down below ...
I use the following query to get the data I need ...
sql = "SELECT tblTempConsolidation.*, tblCustomer.customerLibrary FROM
tblCustomer, tblTempConsolidation WHERE tblCustomer.customerId =
tblTempConsolidation.customerId AND tblTe
> Update, which may be helpful:
>
> The number I'm getting back (which I said is vastly too high) is in
>fact the number of pictures multiplied by the number of ratings entries
>for that artist.
> I wanted to be able to get those two groupings separately. Is there a
>way I can d
Update, which may be helpful:
The number I'm getting back (which I said is vastly too high) is in
fact the number of pictures multiplied by the number of ratings entries
for that artist.
I wanted to be able to get those two groupings separately. Is there a
way I can do th
Hi--
I'm running an art archive, and for the artist listing pages I have to
come up with a query something like the following:
select name,dirname,sortname,pictures.artistid,count(pictures.artistid)
as imgnum,avg(rating) as rateavg,max(uploaded) as lastmod
from artists,pictures,r
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