e_id, ep, wafer_id, lot_id, date_time
>
> My problem is that when data_cst.image_measurer_id is NULL I don't get
> that data_cst row even though all the other part of the where clause
> are TRUE. I understand why that is, but in that case I want the row,
> but with NULL in the da
On Tue, Dec 11, 2012 at 8:48 PM, Peter Brawley
wrote:
>>ERROR 1054 (42S22): Unknown column 'data_tool.category_id' in 'on clause'
>>But category_id is a column in data_tool.
>
> Then a bit of reordering is required ...
>
> SELECT data_target.name, ep, wafer_id, lot_id,
>date_time, data_fil
On Wed, Dec 12, 2012 at 8:25 AM, Shawn Green wrote:
> On 12/11/2012 7:22 PM, h...@tbbs.net wrote:
>>
>> ... (Are all the distinct "id"s really needed? When one joins on a
>>
>> field with the same name in both tables, one may use 'USING', and
>> only the common field, with neither NULL, shows up i
On 12/11/2012 7:22 PM, h...@tbbs.net wrote:
... (Are all the distinct "id"s really needed? When one joins on a
field with the same name in both tables, one may use 'USING', and
only the common field, with neither NULL, shows up in the output.)
This is a perfectly acceptable naming convention t
>ERROR 1054 (42S22): Unknown column 'data_tool.category_id' in 'on clause'
>But category_id is a column in data_tool.
Then a bit of reordering is required ...
SELECT data_target.name, ep, wafer_id, lot_id,
date_time, data_file_id, data_cstimage.name,
bottom, wf_file_path_id, data_m
t row even though all the other part of the where clause
are TRUE. I understand why that is, but in that case I want the row,
but with NULL in the data_cstimage.name column. I think I need a left
outer join, but I've been messing with this for hours, and I can't get
the syntax right. I
D data_cst.date_time BETWEEN '2012-09-01 00:00:00' AND '2012-09-07
> 00:00:00'
>
> ORDER BY target_name_id, ep, wafer_id, lot_id, date_time;
Thanks very much for the reply. This is giving me:
ERROR 1054 (42S22): Unknown column 'data_tool.category_id' in '
a_cst.date_time BETWEEN '2012-09-01 00:00:00' AND '2012-09-07
00:00:00'
ORDER BY target_name_id, ep, wafer_id, lot_id, date_time;
PB
http://www.artfulsoftware.com
I think I need a left
outer join, but I've been messing with this for hours, and I can't get
the syn
Martin Gainty wrote:
Good Morning-
Good afternoon :-)
http://www.mysqlperformanceblog.com/2006/09/04/group_concat-useful-group-by-
extension/
I did'nt see your where clause ?
I'm probably missing your point here. But there's no "where clause"
because I want all records from the tickets tab
Baron Schwartz wrote:
I'm tempted to solve this using a view or two, but would like to know
if there's a better way.
GROUP_CONCAT() takes an optional DISTINCT modifier, and that might do
what you're looking for.
It sure does the trick. I'll use that, I was afraid that I was missing
somet
PARATOR ' ') AS CHAR) AS text
FROM tickets
LEFT OUTER JOIN events AS events ON tickets.id = events.ticket_id
LEFT OUTER JOIN taggings AS taggings ON taggings.taggable_id = tickets.id
LEFT OUTER JOIN tags AS tags ON taggings.tag_id = tags.id
GROUP BY id;
The problem with this query is,
7;) AS CHAR) AS text
FROM tickets
LEFT OUTER JOIN events AS events ON tickets.id = events.ticket_id
LEFT OUTER JOIN taggings AS taggings ON taggings.taggable_id = tickets.id
LEFT OUTER JOIN tags AS tags ON taggings.tag_id = tags.id
GROUP BY id;
The problem with this query is, that it return
06/01/2004 04:33 Subject: Left outer join combined with
inner join
products
and in the tag column they should have a tag if there is one. I can do
the left outer join to join the product and many-to-many table
ProductTag:
select Product.id, ProductTag.TagId from Product left join ProductTag
on Product.id = ProductTag.productId
select Product.id,Product.cost,Tag.tag
they should have a tag if there is one. I can do
the left outer join to join the product and many-to-many table ProductTag:
select Product.id, ProductTag.TagId from Product left join ProductTag on
Product.id = ProductTag.productId
but how do I then, in the same, select statement describe the
At 14:20 +0100 1/22/04, Frederic Wenzel wrote:
Mike Mapsnac wrote:
What is the difference between Left Join and Left Outer Join?
Thanks
If I get it right, there is none.
Greetings
Fred
You got it right. There is none.
--
Paul DuBois, MySQL Documentation Team
Madison, Wisconsin, USA
MySQL AB
Mike Mapsnac wrote:
What is the difference between Left Join and Left Outer Join?
Thanks
If I get it right, there is none.
Greetings
Fred
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
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What is the difference between Left Join and Left Outer Join?
Thanks
Hello all,
I have three queries that I need to join together and cannot figure out
how. The first query returns 161 records and I want all these records with
nulls in the fields added with queries 2 and 3.
Any help will be greatly appreciated!!
EMAIL PROTECTED]
Sent: Friday, February 28, 2003 3:11 PM
To: Rob
Cc: [EMAIL PROTECTED]
Subject: Re: left outer join
Hi,
You have one thing wrong in your query...
You're using LEFT JOIN but then you use a condition over DFL in the
where clause. That's why it doesn't give you the results expec
EMAIL PROTECTED]
Sent: Friday, February 28, 2003 3:11 PM
To: Rob
Cc: [EMAIL PROTECTED]
Subject: Re: left outer join
Hi,
You have one thing wrong in your query...
You're using LEFT JOIN but then you use a condition over DFL in the
where clause. That's why it doesn't give you the results
id
>WHERE DFL.document_id = 37
>AND DF.is_generic = 1
>-Original Message-
>From: Rob [mailto:[EMAIL PROTECTED]
>Sent: 28 February 2003 12:33
>To: [EMAIL PROTECTED]
>Subject: left outer join
>
>
>Could someone please tell me what I'm doing wrong h
.document_field_id
> WHERE DFL.document_id = 37
> AND DF.is_generic = 1
>
> Basically what I want to achieve is this. I want to select all the document
> fields that are
> generic and IF the document has values for those fields I want to see those
> to, otherwise
> I want to
ent
fields that are
generic and IF the document has values for those fields I want to see those
to, otherwise
I want to see null values?
I thought a left outer join worked as follows: Select all items on the left
table (document_fields)
and join them to all items on the right table (document_fields
Probably a simple error here, been a few years since i last did SQL work...
I've got 2 tables (actually just one aliased
nevermind just typing this much allowed me to figure it out :) Love the
way you can spend a whole day trying to figure something out, and then
as soon as you try to explain
Hi Eduardo,
I found the solution the left outer join + aggregate problem I had earlier
faced.
the query should be
SELECT p.nm_project, sum( dl.hours)
FROM PROJECT p LEFT OUTER JOIN DAYLOG dl ON (p.id_project =
dl.id_project
Desmond Lee wrote:
> Hi there
>
> I want to do a left outer join but i also have a bunch of where conditions
> in my sql statment that i need. Can anyone help me out:
>
> SELECT title, authorName, journalName, journalPages, aname, tname,
> avg(ranking)
> FROM p
Ah
Never mind, i got it. I did some stupid stuff, but figured it out. Here's
the working query:
SELECT title, authorName, journalName, journalPages, aname, tname,
avg(ranking)
FROM publications LEFT OUTER JOIN ranking ON (publications.pubID =
ranking.pubID),
area,
Whoops... forgot the "on" in the join stament.
I change it to include the on, but still no luck. Does anyone have any idea?
SELECT title, authorName, journalName, journalPages, aname, tname,
avg(ranking)
FROM publications LEFT OUTER JOIN
Hi there
I want to do a left outer join but i also have a bunch of where conditions
in my sql statment that i need. Can anyone help me out:
SELECT title, authorName, journalName, journalPages, aname, tname,
avg(ranking)
FROM publications, area, topic, pubTopicInt,
LEFT OUTER
|
| To: manu manickalal/PRTGROUP|
| cc: |
| Subject: RES: Aggregate + left outer join |
>
number of hours booked against a project for a date.
I needed to list the total hours booked against each project for any given
month.
My query
SELECT
p.id_project, p.nm_project, sum( dl.hours)
FROM PROJECT p
LEFT OUTER JOIN DAYLOG dl ON (p.id_project = dl.id_project)
WHERE
MONTH(dl.DATE) = 8
AND
Arul,
Monday, July 01, 2002, 3:58:48 PM, you wrote:
A> Can i use left outer join in MySQL.
A> Like i have one condition in Oracle
A> ex:
A> select * from user,company where u.companyid = c.companyid (+)
A> can i rephrase the query in mysql like this
A> select * from us
Hi
Can i use left outer join in MySQL.
Like i have one condition in Oracle
ex:
select * from user,company where u.companyid = c.companyid (+)
can i rephrase the query in mysql like this
select * from user left outer join company c using (companyid)
-Arul
sql , query
ect: RE: A LEFT OUTER JOIN question.
Hi Peter,
Thanks a lot - that does the trick!
Incredibly quick response :)
Ian
> -Original Message-
> From: Peter Normann [mailto:[EMAIL PROTECTED]]
> Sent: 16 June 2002 17:06
> To: 'mySQL list'; [EMAIL PROTECTED]
> Subj
Hi Peter,
Thanks a lot - that does the trick!
Incredibly quick response :)
Ian
> -Original Message-
> From: Peter Normann [mailto:[EMAIL PROTECTED]]
> Sent: 16 June 2002 17:06
> To: 'mySQL list'; [EMAIL PROTECTED]
> Subject: RE: A LEFT OUTER JOIN question
Try
SELECT Items.ItemID, Stuff.info FROM Items LEFT JOIN Stuff ON
(Items.ItemID = Stuff.ItemID && (type=0 || type IS NULL));
Peter Normann
-Original Message-
From: mySQL list [mailto:[EMAIL PROTECTED]]
Sent: 16. juni 2002 17:59
To: [EMAIL PROTECTED]
Subject: A LEFT OU
I have two tables, 'items' and 'stuff'.
Items has a primary key of itemid. and looksmlike this
ItemID other fields...
1 ...
2
3
4
5
6
Stuff contains something like this:
ItemID type info
1 0blah blah
2 0something
2 1...
3 1...
I want a query w
>Description:
Left outer join on null datetime column produces incorrect result.
The 2nd select below produces no rows, which is incorrect and inconsistent
with the fourth select which produces 1 row.
I get the same results with server version 3.23.41 - binary vers
11:12 AM
Subject: left outer join query question
> Hi, I am having a small formatting problem maybe someone can help with.
>
> I have a query that does a left outer join, which generates a table with a
> few NULL values in some columns. All okay so far. But what I need to do is
> s
Hi, I am having a small formatting problem maybe someone can help with.
I have a query that does a left outer join, which generates a table with a
few NULL values in some columns. All okay so far. But what I need to do is
sort on this column, and I need to put NULL values at the end. Normally
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