On Fri, May 23, 2008 at 1:35 PM, Rob Wultsch <[EMAIL PROTECTED]> wrote:
>>> SELECT
>>> p1.POPS AS `POPA`,
>>> p2.POPS AS `POPZ`
>>> FROM
>>> circuits
>>> INNER JOIN pops.POPS as p1 WHERE circuits.popID_A =p1.popID
>>> INNER JOIN pops.POPS as p2 WHERE circuits.pop_ID_Z =p2.popID
Wow... I can't be
On Fri, May 23, 2008 at 3:06 PM, <[EMAIL PROTECTED]> wrote:
>
> - Original Message -
> From: "Rob Wultsch" <[EMAIL PROTECTED]>
> To: [EMAIL PROTECTED]
> Cc: "MYSQL General List"
> Sent: Friday, May 23, 2008 11:10:56 AM GMT -08:00 US/Canad
- Original Message -
From: "Rob Wultsch" <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Cc: "MYSQL General List"
Sent: Friday, May 23, 2008 1:42:07 PM GMT -08:00 US/Canada Pacific
Subject: Re: Query Output Issue
On Fri, May 23, 2008 at 1:35 PM, Rob Wultsch
- Original Message -
From: "Rob Wultsch" <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Cc: "MYSQL General List"
Sent: Friday, May 23, 2008 11:10:56 AM GMT -08:00 US/Canada Pacific
Subject: Re: Query Output Issue
On Fri, May 23, 2008 at 1:47 PM, <[EMAIL PROTEC
On Fri, May 23, 2008 at 1:47 PM, <[EMAIL PROTECTED]> wrote:
> Still getting and error on the last line
>
> SELECT
> p1.POPS AS `POPA`,
> p2.POPS AS `POPZ`
> FROM
> circuits
> INNER JOIN pops.POPS as p1 WHERE circuits.popID_A =p1.popID
> INNER JOIN pops.POPS as p2 WHERE circuits.pop_ID_Z =p2.pop
Canada Pacific
Subject: Re: Query Output Issue
On Fri, May 23, 2008 at 12:04 PM, <[EMAIL PROTECTED]> wrote:
> Thanks for the quick reply, however i am getting a failure on line 2.
>
> SELECT
> 11.POPS AS `POPA`,
> 12.POPS AS `POPZ`
> FROM
> circuits
> INNER JOIN pop
On Fri, May 23, 2008 at 12:04 PM, <[EMAIL PROTECTED]> wrote:
> Thanks for the quick reply, however i am getting a failure on line 2.
>
> SELECT
> 11.POPS AS `POPA`,
> 12.POPS AS `POPZ`
> FROM
> circuits
> INNER JOIN pops.POPS as 11 WHERE circuits.popA = 11.popID
> INNER JOIN pops.POPS as 12 WHERE
US/Canada Pacific
Subject: Re: Query Output Issue
On Fri, May 23, 2008 at 11:27 AM, <[EMAIL PROTECTED]> wrote:
> I have a table that has two has two secondary keys referencing the same
> primary key of another.
>
> Table-name =Circuits
> circuitID
> Ci
On Fri, May 23, 2008 at 11:27 AM, <[EMAIL PROTECTED]> wrote:
> I have a table that has two has two secondary keys referencing the same
> primary key of another.
>
> Table-name =Circuits
> circuitID
> CircuitID
> A_loc
> Z_loc
>
> Table-name = Location
> locationID
>
I have a table that has two has two secondary keys referencing the same primary
key of another.
Table-name =Circuits
circuitID
CircuitID
A_loc
Z_loc
Table-name = Location
locationID
location
circuits.A_locreferenceslocatioin.locationID
circuits.Z_
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