On Sun, 10 Jun 2001 19:13:01 -0700, "Vladimir Kravtsov" <[EMAIL PROTECTED]>
wrote:
>>
>>
>>
>>>connectdb();
>>mysql_select_db(xtopsites);
>>$validated=1;
>>$sql = "select id, siteurl, sitename, from sitesats where validated = "$validated"";
>//
On Sun, Jun 10, 2001 at 07:13:01PM -0700, Vladimir Kravtsov wrote:
> $sql = "select id, siteurl, sitename, from sitesats where validated = "$validated"";
>// Line 8
Actually, using '$validated' might work better - one or the other.
Whit
-
On Sun, Jun 10, 2001 at 07:13:01PM -0700, Vladimir Kravtsov wrote:
> $sql = "select id, siteurl, sitename, from sitesats where validated = "$validated"";
>// Line 8
> What's wrong here?
Try \"$validated\" - you need to escape the quoted quotes.
Whit
---
On 11-Jun-01 Vladimir Kravtsov wrote:
>
>
>
> connectdb();
> mysql_select_db(xtopsites);
> $validated=1;
> $sql = "select id, siteurl, sitename, from sitesats where validated =
> "$validated""; // Line 8
^ ^ - escape your quotes, \"$validated\";
change to sin
You have a problem with "...
" is reserved word, put \ before it...
try this:
$sql = "select id, siteurl, sitename, from sitesats where validated =
\"$validated\"";
regards,
Augusto
On Sun, 10 Jun 2001, Vladimir Kravtsov wrote:
>
>
>
> connectdb();
> mysql_select_db(xtopsites);
> $valid