I have no idea what I was thinking. For some reason I was thinking
Distinct wouldn't work, must have been temporarily brain dead. Thanks
for the wake up call.
Gerald L. Clark wrote:
Chris W wrote:
I have two tables, one is a list of users and the other is a list of
events for each user. It
Chris W wrote:
I have two tables, one is a list of users and the other is a list of
events for each user. It is a one to many relationship. The event
table is pretty simple just an event type and a the date and time of the
event in a datetime field.
I need a query that shows all events of a c
> Dear all,
>
> I have two tables,let's call then a and b:
>
> Table a:
>
> CUI1|CUI2
> C001|C002
> C002|C003
> C003|C055
> C004|C002
> ...
>
> Table b:
> CUI|STY
> C001|T001
> C002|T002
> C003|T003
> C004|T004
> C005|T006
> C055|T061
> ..
>
> And the join table should be:
> T001|T002
> T002|T003
http://dev.mysql.com/doc/refman/4.1/en/example-maximum-column-group-row.html
I'd translate it to your example, but it's bed-time here in England!
HTH,
James Harvard
At 11:42 pm + 5/1/06, Terry Spencer wrote:
>I have a question for clearer brains than mine. I would like to join two
>tables,.
On Thu, 3 Jun 2004 15:22:36 -0500
Josh Trutwin <[EMAIL PROTECTED]> wrote:
> Or in preferable INNER JOIN syntax which makes it easier to forget a
> JOIN condition:
Oops - I meant "harder to forget" not "easier to forget". Doh.
>
> SELECT c.cst_SiteID, c.cst_IDC, a.asset_ID, o.offer_ID,
> o.o
On Thu, 3 Jun 2004 13:06:54 -0700
"Chris Dietzler" <[EMAIL PROTECTED]> wrote:
> Running 4.0.18
>
> I am trying to run a query where the query gets the offer_ID of a
> certain customer from the offer table and displays in the results
> the offer_Name associated with the offer_ID. Right now the way
Message -
From: Anthony Ward
To: [EMAIL PROTECTED]
Sent: Thursday, June 05, 2003 1:53 PM
Subject: Re: Join question
Hi,
what is the difference between your way and Mike Hillyer way?? (I can see
the INNER join).
But thanx to both of you.
Anthony
--
MySQL General Mai
: [EMAIL PROTECTED]
Subject: Re: Join question
Hi,
what is the difference between your way and Mike Hillyer way?? (I can
see
the INNER join).
But thanx to both of you.
Anthony
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MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:http://lists.mysql.com
Hi,
what is the difference between your way and Mike Hillyer way?? (I can see
the INNER join).
But thanx to both of you.
Anthony
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Anthony,
Do you mean this (not tested)?
Select table1.id from table1
INNER JOIN table2 USING (id)
INNER JOIN table3 USING (id)
WHERE table1.cl1 = 1 and table1.cle2=5 AND table1.cl3 IN(1,2,5,8)
AND table2.cl1 = 4 and table2.cle2 IN(10,12,81) AND table2.cl3 IN(3,7)
AND table3.distan
SELECT table1.id FROM table1, table2, table3 WHERE table1.cl1 = 1 AND
table1.cle2=5 AND table1.cl3
IN(1,2,5,8) AND table2.cl1 = 4 AND table2.cle2 IN (10,12,81) AND
table2.cl3 IN (3,7) AND table3.distance BETWEEN 1 AND 99 AND table1.id =
table2.id AND table2.id = table3.id;
That should do what you
alx wrote:
On Fri, 2003-03-28 at 01:39, Bruce Feist wrote:
Usually it's best to work with normalized tables, which would make this
trivial. tbl_reports isn't normalized, since it has a simulated array
of persons in it. Could it be split into two tables:
i'm interested on how to normaliz
On Fri, 2003-03-28 at 01:39, Bruce Feist wrote:
> Usually it's best to work with normalized tables, which would make this
> trivial. tbl_reports isn't normalized, since it has a simulated array
> of persons in it. Could it be split into two tables:
i'm interested on how to normalize a table... c
Usually it's best to work with normalized tables, which would make this
trivial. tbl_reports isn't normalized, since it has a simulated array
of persons in it. Could it be split into two tables:
tbl_reports, with fields:
rep_id (primary key) and other report-specific information you didn't
menti
r 'rootid' and then one
more self join to get the name for 'parentid'.
NJ> -joseph
NJ> -Original Message-
NJ> From: Victoria Reznichenko [mailto:[EMAIL PROTECTED]]
NJ> Sent: Thursday, December 05, 2002 9:01 AM
NJ> To: [EMAIL PROTECTED]
NJ> Subject: re: J
Michelle,
Thursday, December 05, 2002, 5:46:03 PM, you wrote:
MdB> I believe this question is solved by a join, but I
MdB> haven't really got a hang of it.
MdB> My table:
MdB> --
MdB> | uid | rootid | parentid | name |
MdB> -
Hi:
You might find these articles from O'Reilly Network will help clear the
water.
http://www.onlamp.com/pub/ct/19
Doug
On Thu, 5 Dec 2002 07:46:03 -0800 (PST), Michelle de Beer wrote:
>I believe this question is solved by a join, but I
>haven't really got a hang of it.
>
>My table:
>-
- Original Message -
From: "Michelle de Beer" <[EMAIL PROTECTED]>
> I believe this question is solved by a join, but I
> haven't really got a hang of it.
>
> My table:
> --
> | uid | rootid | parentid | name |
> -
* Michelle de Beer
> I believe this question is solved by a join, but I
> haven't really got a hang of it.
>
> My table:
> --
> | uid | rootid | parentid | name |
> --
> | 1 | 0 | 0| name1|
> | 2 | 1
Peter Stöcker" <[EMAIL PROTECTED]>
To: "Mikhail Entaltsev" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Thursday, September 19, 2002 11:56 AM
Subject: Re: Re: JOIN-Question
Hi Mikhail!
The query should be released automaticly and it shoulb be something like:
SELECT a.
Hi CH!
Thanks a lot! That's it!
I thought there is no differece between "ON (condition)" and "USING(field)", but there
is!
Thank you very much!
CU,
Peter
[EMAIL PROTECTED] schrieb am 19.09.02 12:02:58:
> Hi Peter,
>
> pls try this query. but its not tested.
>
> select t1.name, t1.f1, t1.f
Hi Mikhail!
The query should be released automaticly and it shoulb be something like:
SELECT a.*,b.*,c.* FROM ?? WHERE b.field3=5 OR c.field6=16
I want to have all entries wich fit to the condition. But at this time I don't know
weather there is a entry with name="test" or "test2" or not.
Peter,
If you would like to get such resultset
> namefield1 field2 field3field4 field5 field6
> -
> test 12 5 6 9 10
> test 12 5
;Boex,Matthew W.'; [EMAIL PROTECTED]
Subject: RE: JOIN question
How about:
mysql> select count(*) from usernames INNER
JOIN pictures ON usernames.user=pictures.user where state = "Delaware" order
by ask limit 25;
-Original Message-
From: Boex,Matthew W. [mailto:[EMAIL PRO
7;; [EMAIL PROTECTED]
Subject: RE: JOIN question
How about:
mysql> select count(*) from usernames INNER
JOIN pictures ON usernames.user=pictures.user where state = "Delaware" order
by ask limit 25;
-Original Message-
From: Boex,Matthew W. [mailto:[EMAIL PROTECTED]]
Sent: Friday, J
How about:
mysql> select count(*) from usernames INNER
JOIN pictures ON usernames.user=pictures.user where state = "Delaware" order
by ask limit 25;
-Original Message-
From: Boex,Matthew W. [mailto:[EMAIL PROTECTED]]
Sent: Friday, January 04, 2002 2:09 PM
To: [EMAIL PROTECTED]
Subject: J
Your two Title fields are not the same size.
This could prevent a match.
It will slow down joins in 3.22.
Carl Schrader wrote:
>
> I have 2 tables with a common field of Title.
>
> Table 1 defined as:
> Name;varchar(60)
> Title;varchar(60)
> Year;varchar(4)
> Other;varchar(30)
> Other2;varchar(
>What am I doing wrong?
>
>The goal is to count the number of entries which match the account
>preferences.
>
>The results are correct, but the times are so far off...
>
>mysql> select count(*) from STLOUIS left join ClientSTL
> -> on STLOUIS.Dwell=ClientSTL.Dwell where ClientSTL.account='prui
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