I'm a beginner so don't quote me. I beleive you need something like:
Select hs_identifiers.hs_id_num from hs_identifiers,
where (accession_num LIKE (result of another select statement)%);
I beleive that should give you the first part and if there is anything after
it.
Respectfully,
Ligaya
PROTECTED]
Subject: Re: Strings and variables in select statements
I'm a beginner so don't quote me. I beleive you need something like:
Select hs_identifiers.hs_id_num from hs_identifiers,
where (accession_num LIKE (result of another select statement)%);
I beleive that should give you the first
