RE: Supplied argument is not a valid MySQL result resource!!

2002-08-16 Thread Roger Davis
ry is returning something. -Original Message- From: Anil Garg [mailto:[EMAIL PROTECTED]] Sent: Thursday, August 15, 2002 05:34 PM To: SteveH; [EMAIL PROTECTED] Subject: Re: Supplied argument is not a valid MySQL result resource!! hi, m sorry i dint mention that its just a part of code. i am able t

Re: Supplied argument is not a valid MySQL result resource!!

2002-08-15 Thread Pekka Saarinen
At 8/16/2002, you wrote: >Hi, >in the piece of code given below >--- >$qid = mysql_query(" > SELECT * > FROM 1_nodedata > WHERE id = $edit_id > "); > $frm = mysql_fetch_array($qid); >--- >i get the follownig error: > >Warning: Supplied argument is not a valid MySQL result reso

Re: Supplied argument is not a valid MySQL result resource!!

2002-08-15 Thread Anil Garg
can u plz tell me how can i check that? regards anil - Original Message - From: "Dan Nelson" <[EMAIL PROTECTED]> To: "Anil Garg" <[EMAIL PROTECTED]> Cc: "SteveH" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]> Sent: Thursday, August 15, 2002

Re: Supplied argument is not a valid MySQL result resource!!

2002-08-15 Thread Jocelyn Fournier
quot; <[EMAIL PROTECTED]> > To: "Anil Garg" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]> > Sent: Thursday, August 15, 2002 5:40 PM > Subject: Re: Supplied argument is not a valid MySQL result resource!! > > > > Hi, > > > > try : > > >

Re: Supplied argument is not a valid MySQL result resource!!

2002-08-15 Thread Anil Garg
0 PM Subject: Re: Supplied argument is not a valid MySQL result resource!! > Hi, > > try : > > > $qid = mysql_query(" > > SELECT * > > FROM 1_nodedata > > WHERE id = '$edit_id' > > "); > > $frm = mysql_fetch_array($qid)

Re: Supplied argument is not a valid MySQL result resource!!

2002-08-15 Thread Dan Nelson
In the last episode (Aug 15), Anil Garg said: > > Thursday, August 15, 2002, 1:12:21 PM, you wrote: > > > > > Hi, > > > in the piece of code given below > > > --- > > > $qid = mysql_query(" > > > SELECT * > > > FROM 1_nodedata > > > WHERE id = $edit_id > > > "); > > > $frm = mysql_fet

Re: Supplied argument is not a valid MySQL result resource!!

2002-08-15 Thread Jocelyn Fournier
Hi, try : > $qid = mysql_query(" > SELECT * > FROM 1_nodedata > WHERE id = '$edit_id' > "); > $frm = mysql_fetch_array($qid); (what does echo "edit_id : $edit_id"; display ?) Regards, Jocelyn - Original Message - From: "Anil Garg" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent

Re: Supplied argument is not a valid MySQL result resource!!

2002-08-15 Thread Anil Garg
IL PROTECTED]> Sent: Thursday, August 15, 2002 4:50 PM Subject: Re: Supplied argument is not a valid MySQL result resource!! > Anil, > > You never created a connection. > mysql_connect() > > > Regards. > > > > > > Thursday, August 15, 2002, 1:12:21

Re: Supplied argument is not a valid MySQL result resource!!

2002-08-15 Thread SteveH
Anil, You never created a connection. mysql_connect() Regards. Thursday, August 15, 2002, 1:12:21 PM, you wrote: > Hi, > in the piece of code given below > --- > $qid = mysql_query(" > SELECT * > FROM 1_nodedata > WHERE id = $edit_id > "); > $frm = mysql_fetch_array($qid); >