Re: RE: Count and group by problems

2002-08-17 Thread Egor Egorov
Menard, Friday, August 16, 2002, 8:44:38 PM, you wrote: M> Me again M> I found a work around to my problem: M> select country, count(distinct client_name, client_address, etc..) clients M> from addresses group by country M> But I still don't understand why the below would not work. I downloaded

RE: Count and group by problems

2002-08-16 Thread Menard, Inc. Information Systems
elp. Help. Thanks Jake -Original Message- From: Menard, Inc. Information Systems [mailto:[EMAIL PROTECTED]] Sent: Wednesday, August 14, 2002 5:26 PM To: David Kramer; [EMAIL PROTECTED]; [EMAIL PROTECTED] Subject: RE: Count and group by problems For an example let's say that I

RE: Count and group by problems

2002-08-14 Thread Menard, Inc. Information Systems
st 09, 2002 5:59 PM To: 'Menard, Inc. Information Systems'; [EMAIL PROTECTED] Subject: RE: Count and group by problems Im not sure I understand what it is that you are trying to do here??? Im assuming your using PERL/SomeScriptingLang on something on NT to connect to mysql using

Re: Count and group by problems

2002-08-12 Thread Francisco
Interesting a spooky. Try to use different cursor types. As you know, ADO, or better said, OLE DB behaves (or misbehaves) depending on the cursor. Have you tried a FORWARD and READ ONLY cursor. Good Luck --- "Menard, Inc. Information Systems" <[EMAIL PROTECTED]> wrote: > Evening > > I think I'm

RE: Count and group by problems

2002-08-09 Thread David Kramer
Im not sure I understand what it is that you are trying to do here??? Im assuming your using PERL/SomeScriptingLang on something on NT to connect to mysql using the ADO object... Within your Count(*) Group by are you trying to return a result set that contains a duplicate row count, i.e. Column=