Hi
I wonder if anyone can help or point me in the right direction for this
problem.
Warning: Supplied argument is not a valid MySQL result resource
I get this while running index.php, the site did work then suddenly stopped,
the index.php hasnt been changed.
Machine : Cobalt RAQ4
: mark horn [mailto:[EMAIL PROTECTED]]
Sent: 28 November 2002 22:41
To: [EMAIL PROTECTED]
Subject: Warning: Supplied argument is not a valid MySQL result resource
Hi
I wonder if anyone can help or point me in the right direction for this
problem.
Warning: Supplied argument is not a valid MySQL
Message-
From: Anil Garg [mailto:[EMAIL PROTECTED]]
Sent: Thursday, August 15, 2002 05:34 PM
To: SteveH; [EMAIL PROTECTED]
Subject: Re: Supplied argument is not a valid MySQL result resource!!
hi,
m sorry i dint mention that its just a part of code.
i am able to delete entries from the database
Hi,
in the piece of code given below
---
$qid = mysql_query(
SELECT *
FROM 1_nodedata
WHERE id = $edit_id
);
$frm = mysql_fetch_array($qid);
---
i get the follownig error:
Warning: Supplied argument is not a valid MySQL result resource in
/z/mercury/www/niksun/admin
);
---
i get the follownig error:
Warning: Supplied argument is not a valid MySQL result resource in
/z/mercury/www/niksun/admin/add_doc.php on line 107
element type:
What is it happening so!!
regards
anil
-
Before posting
, August 15, 2002 4:50 PM
Subject: Re: Supplied argument is not a valid MySQL result resource!!
Anil,
You never created a connection.
mysql_connect()
Regards.
Thursday, August 15, 2002, 1:12:21 PM, you wrote:
Hi,
in the piece of code given below
---
$qid = mysql_query
, August 15, 2002 11:12 PM
Subject: Supplied argument is not a valid MySQL result resource!!
Hi,
in the piece of code given below
---
$qid = mysql_query(
SELECT *
FROM 1_nodedata
WHERE id = $edit_id
);
$frm = mysql_fetch_array($qid);
---
i get the follownig error
In the last episode (Aug 15), Anil Garg said:
Thursday, August 15, 2002, 1:12:21 PM, you wrote:
Hi,
in the piece of code given below
---
$qid = mysql_query(
SELECT *
FROM 1_nodedata
WHERE id = $edit_id
);
$frm = mysql_fetch_array($qid);
hi,
m sorry
]
To: [EMAIL PROTECTED]
Sent: Thursday, August 15, 2002 11:12 PM
Subject: Supplied argument is not a valid MySQL result resource!!
Hi,
in the piece of code given below
---
$qid = mysql_query(
SELECT *
FROM 1_nodedata
WHERE id = $edit_id
);
$frm = mysql_fetch_array
PM
Subject: Re: Supplied argument is not a valid MySQL result resource!!
Hi,
try :
$qid = mysql_query(
SELECT *
FROM 1_nodedata
WHERE id = '$edit_id'
);
$frm = mysql_fetch_array($qid);
(what does echo edit_id : $edit_id; display ?)
Regards,
Jocelyn
can u plz tell me how can i check that?
regards
anil
- Original Message -
From: Dan Nelson [EMAIL PROTECTED]
To: Anil Garg [EMAIL PROTECTED]
Cc: SteveH [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Thursday, August 15, 2002 5:41 PM
Subject: Re: Supplied argument is not a valid MySQL result
At 8/16/2002, you wrote:
Hi,
in the piece of code given below
---
$qid = mysql_query(
SELECT *
FROM 1_nodedata
WHERE id = $edit_id
);
$frm = mysql_fetch_array($qid);
---
i get the follownig error:
Warning: Supplied argument is not a valid MySQL result resource in
/z
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