Subject: RE: ( OT ) Convert mA to Watts
Am I the only one who remembers ELI the ICE man? Voltage (e) leads current (i)
in an inductor (L) and current (i) leads voltage (e) in a capacitor (C). Must
have been the old Navy guy teaching electronics in high school.
http://www.electronicstheory.com/html
: Thursday, November 03, 2011 8:04 PM
To: NT System Admin Issues
Subject: RE: ( OT ) Convert mA to Watts
Am I the only one who remembers ELI the ICE man? Voltage (e) leads current (i)
in an inductor (L) and current (i) leads voltage (e) in a capacitor (C). Must
have been the old Navy guy teaching
| Systems Analyst, Information Technology | Crane
Aerospace Electronics
From: Ken Cornetet [mailto:ken.corne...@kimball.com]
Sent: Thursday, October 20, 2011 1:09 PM
To: NT System Admin Issues
Subject: RE: ( OT ) Convert mA to Watts
Power factor is a bit difficult to explain, but here goes
On Thu, Oct 20, 2011 at 4:09 PM, Ken Cornetet ken.corne...@kimball.com wrote:
1. A nonlinear load (like something with rectifiers) will present a
resistance that appears to vary with the instantaneous voltage. For a
sinusoidal alternating voltage, this leads to a non-sinusoidal current,
You mean the Politicians were serious? How funny is that.
Jon
On Tue, Oct 18, 2011 at 6:12 PM, Ben Scott mailvor...@gmail.com wrote:
On Tue, Oct 18, 2011 at 1:27 PM, Stefan Jafs stefan.j...@gmail.com
wrote:
No I'm trying to figure out how much more energy efficient our new 7 LCD
display
Sorry wrong thread.
Jon
On Thu, Oct 20, 2011 at 9:36 PM, Jon Harris jk.har...@gmail.com wrote:
You mean the Politicians were serious? How funny is that.
Jon
On Tue, Oct 18, 2011 at 6:12 PM, Ben Scott mailvor...@gmail.com wrote:
On Tue, Oct 18, 2011 at 1:27 PM, Stefan Jafs
People always amuse me, it turned out that the technician measured the DC
current AFTER the power supply. Ones we plugged in the energy meter, we got
the “real” current draw and watts reading, BTW the PF is 100%. Turns out
that the readings are almost identical or around 11 watts, with $0.15 per
You lost me at factor.
On Tue, Oct 18, 2011 at 12:37 PM, Ben Scott mailvor...@gmail.com wrote:
On Tue, Oct 18, 2011 at 12:15 PM, Stefan Jafs stefan.j...@gmail.com
wrote:
I guess the big unknown is the PF, I assumed 60% (based on Googeling),
the
is a power supply, would it not be higher
Issues
Subject: Re: ( OT ) Convert mA to Watts
You lost me at factor.
On Tue, Oct 18, 2011 at 12:37 PM, Ben Scott
mailvor...@gmail.commailto:mailvor...@gmail.com wrote:
On Tue, Oct 18, 2011 at 12:15 PM, Stefan Jafs
stefan.j...@gmail.commailto:stefan.j...@gmail.com wrote:
I guess the big unknown
I'm, trying to figure out how much it cost to run some of our Medical Gas
Alarm, current draw is 290 mA at 120 Volts, any ideas?
This are my guess after some searches:
.290 * 120 = 34.8 VA * 60% (PF) = 20.9 Watts I think that's correct but how
do I get to kWh?
--
Stefan Jafs
~ Finally,
I'm unsure of the conversion, but leave it to msft to have a tool that works
Google Microsoft Mathematics
From: Stefan Jafs [mailto:stefan.j...@gmail.com]
Sent: Tuesday, October 18, 2011 11:38 AM
To: NT System Admin Issues
Subject: ( OT ) Convert mA to Watts
I'm, trying to figure out how much
1 watt = .001 kw so 20.9 watts = .029 kwh
I *think*
On Tue, Oct 18, 2011 at 11:37 AM, Stefan Jafs stefan.j...@gmail.com wrote:
I'm, trying to figure out how much it cost to run some of our Medical Gas
Alarm, current draw is 290 mA at 120 Volts, any ideas?
This are my guess after some
I guess the big unknown is the PF, I assumed 60% (based on Googeling), the
is a power supply, would it not be higher for a transformer load?
Stefan
On Tue, Oct 18, 2011 at 12:06 PM, Ben Scott mailvor...@gmail.com wrote:
On Tue, Oct 18, 2011 at 11:37 AM, Stefan Jafs stefan.j...@gmail.com
kWh=kW * h
So kWh = W/1000 * H
H= hours of operation over a billing cycle.
20W left on 24x7 is likely in the neighborhood of $1/month.
Carl
From: Stefan Jafs [mailto:stefan.j...@gmail.com]
Sent: Tuesday, October 18, 2011 11:38 AM
To: NT System Admin Issues
Subject: ( OT ) Convert
On Tue, Oct 18, 2011 at 11:37 AM, Stefan Jafs stefan.j...@gmail.com wrote:
I'm, trying to figure out how much it cost to run some of our Medical Gas
Alarm, current draw is 290 mA at 120 Volts, any ideas?
This are my guess after some searches:
.290 * 120 = 34.8 VA * 60% (PF) = 20.9 Watts I
On Tue, Oct 18, 2011 at 12:15 PM, Stefan Jafs stefan.j...@gmail.com wrote:
I guess the big unknown is the PF, I assumed 60% (based on Googeling), the
is a power supply, would it not be higher for a transformer load?
To continue the water analogy, power factor is like a big reserve
tank right
: Tuesday, October 18, 2011 12:15 PM
To: NT System Admin Issues
Subject: Re: ( OT ) Convert mA to Watts
I guess the big unknown is the PF, I assumed 60% (based on Googeling), the
is a power supply, would it not be higher for a transformer load?
Stefan
On Tue, Oct 18, 2011 at 12:06 PM, Ben Scott
On Tue, Oct 18, 2011 at 12:49 PM, Carl Houseman c.house...@gmail.com wrote:
If you’re really this concerned over accuracy, get/buy a Kill-A-Watt and
plug one into it, that will give you the actual W used by the device.
Nameplate or specification current ratings are generally higher than actual
No I'm trying to figure out how much more energy efficient our new 7 LCD
display alarm is to our old LED version, and based upon an PF of .6, the
difference is $25 / year.
Marketing is trying to capitalize on the Energy efficiency.
Thanks everybody for the input.
Stefan
On Tue, Oct 18, 2011 at
, October 18, 2011 1:28 PM
To: NT System Admin Issues
Subject: Re: ( OT ) Convert mA to Watts
No I'm trying to figure out how much more energy efficient our new 7 LCD
display alarm is to our old LED version, and based upon an PF of .6, the
difference is $25 / year.
Marketing is trying to capitalize
On Tue, Oct 18, 2011 at 1:27 PM, Stefan Jafs stefan.j...@gmail.com wrote:
No I'm trying to figure out how much more energy efficient our new 7 LCD
display alarm is to our old LED version, and based upon an PF of .6, the
difference is $25 / year.
Too bad you've now spent a few $1000 in time
Anyhow I picked up a small energy meter for less than $30 so tomorrow the
can plug in the Alarms and get the true reading, where marketing will take
after that is any ones guess.
Stefan
On Tue, Oct 18, 2011 at 6:12 PM, Ben Scott mailvor...@gmail.com wrote:
On Tue, Oct 18, 2011 at 1:27 PM,
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