On Fri, Jun 24, 2011 at 14:38, srean wrote:
> A valiant exercise in hope:
>
> Is this possible to do it without a loop or extra copying. What I have is an
> iterator that yields a fixed with string on every call to next(). Now I want
> to create a numpy array of ints out of the last 4 chars of tha
A valiant exercise in hope:
Is this possible to do it without a loop or extra copying. What I have is an
iterator that yields a fixed with string on every call to next(). Now I want
to create a numpy array of ints out of the last 4 chars of that string.
My plan was to pass the iterator through a
On Fri, Jun 24, 2011 at 9:12 AM, Robert Kern wrote:
> On Fri, Jun 24, 2011 at 04:03, srean wrote:
> > To answer my own question, I guess I can keep appending to a
> array.array()
> > object and get a numpy.array from its buffer if possible. Is that the
> > efficient way.
>
> It's one of the mos
On Fri, Jun 24, 2011 at 04:03, srean wrote:
> To answer my own question, I guess I can keep appending to a array.array()
> object and get a numpy.array from its buffer if possible. Is that the
> efficient way.
It's one of the most efficient ways to do it, yes, especially for 1D arrays.
--
Robe
To answer my own question, I guess I can keep appending to a array.array()
object and get a numpy.array from its buffer if possible. Is that the
efficient way.
On Fri, Jun 24, 2011 at 2:35 AM, srean wrote:
> Hi,
>
> I have an iterator that yields a complex object. I want to make an array
> out
Hi,
I have a iterator that yields a complex object. I want to make an array out
of a numerical attribute that the yielded object possesses and that too very
efficiently.
My initial plan was to keep writing the numbers to a StringIO object and
when done generate the numpy array using StringIO's bu
