Hi Marek,
m1 has binary data, not string.
This data may have embeded 0x00 (look at your output above) and strcat
can not copy data in good place (to bytes before end instead of end of md1).
Use memcpy, does not relay of strlen() on such data too.
I check for the output and the inner hash
Hi Marek,
I arrived to do inner/outer hash with success.
Next step: store binary result into char static :)
Best regards
On Mon, Apr 14, 2008 at 5:42 PM, Badra [EMAIL PROTECTED] wrote:
Hi Marek,
m1 has binary data, not string.
This data may have embeded 0x00 (look at your output above)
From: [EMAIL PROTECTED] On Behalf Of Badra
Sent: Friday, 11 April, 2008 09:57
static char *login=login;
static char *password=password;
static char *label=label;
These could better be pointers to const char, since you shouldn't
and don't try to modify the strings pointed to.
const
Hi Marek,
I do the following:
static char *login=login;
static char *password=password;
static char *label=label;
const unsigned char *buf=NULL;
strcat(buf, login); strcat(buf, password); strcat(buf, label);
unsigned char *m1[20];
unsigned char *m2[20];
SHA1(buf, strlen(buf), m1); // The
Hello,
[EMAIL PROTECTED] wrote on 04/11/2008 03:56:45 PM:
Hi Marek,
I do the following:
static char *login=login;
static char *password=password;
static char *label=label;
const unsigned char *buf=NULL;
strcat(buf, login); strcat(buf, password); strcat(buf, label);
You should
Dear all,
I need to call the hash function two times, in which the output of the
first call is used as an input for the second (result = hash[hash(A
+B) + C]
The first call is ok, but when I concatenate its output to the C, I
don't get the expected output.
Did I miss something?
Best regards,
Hello,
[EMAIL PROTECTED] wrote on 04/11/2008 03:51:18 AM:
Dear all,
I need to call the hash function two times, in which the output of the
first call is used as an input for the second (result = hash[hash(A
+B) + C]
The first call is ok, but when I concatenate its output to the C, I
