> so 6% is 'popular' - I think not.
I agree with you here. In fact, I've said myself in another thread that the
reason why there aren't many viruses for PalmOS is because it is not popular
enough environment to attract the attention of the virus writers.
Regards,
Vesselin
--
For information on
so 6% is 'popular' - I think not.
"Majority" means "more than the others" (or "more than the half" in some contexts). In
that aspect, the majority of computer users are Windows users. "Popular" means that there is a large enough
population of users - even though other OSes might have even more us
> Exactly what you deserve when you download a virus load it onto
> your PDA and run it
You might think so but the ethical principles of my profession dictate that I
avoid such "blame the victim" attitudes. Our job is to protect the user - not
to explain him how stupid he has been to do the idio
>> What are you referring to - the Phage virus? Yep, once you run it,
all applications
>> that are in the RAM just stop working
Exactly what you deserve when you download a virus load it onto your PDA
and run it, there are an awful lot of steps to getting a virus on your
PDA, plus it's not exa
> Wow, that's really going to cripple your system isn't it.
What are you referring to - the Phage virus? Yep, once you run it, all
applications that are in the RAM just stop working - because it overwrites them
all. That's one of the reasons why it never became widespread - a virus that
immedia
Wow, that's really going to cripple your system isn't it.
I think your flogging a dead horse, the PalmOS is dying whatever we like
to think about it. MS is gaining ground and PalmOne have failed to
release anything good in a long time. Look at the latest PPC models
which have WiFi, Bluetooth, m
On 2005-05-03, Ben Combee <[EMAIL PROTECTED]> wrote:
> At 11:03 AM 5/3/2005, you wrote:
>> > It has to do with the locking of the code 1 resource into memory.
>> > The memory manager can move unlocked resources around to compact
>> > the storage heap.i So the launch code looks up the code 1
>> > re
Thanks, Ben! I understand it now.
Regards,
Vesselin
P.S. Slight correction - the Phage virus copies its data 0, code 1 *and* code 0
resources to the applications it infects - I just looked at the code and that's
what it does explicitly. Its descriptions at the various anti-virus sites are
slig
At 11:03 AM 5/3/2005, you wrote:
> It has to do with the locking of the code 1 resource into memory.
> The memory manager can move unlocked resources around to compact
> the storage heap.i So the launch code looks up the code 1
> resource, pushes its start address on the stack and jumps to it
> wit
> Quicker than non existent PalmOS viruses :-)
PalmOS viruses are not "non existent". There is a whole one of them. :-) See,
for instance, this:
http://www.f-secure.com/v-descs/phage.shtml
(The first picture on that page is a bit misleading, BTW. The Phage virus
doesn't have an icon that looks
> It has to do with the locking of the code 1 resource into memory.
> The memory manager can move unlocked resources around to compact
> the storage heap.i So the launch code looks up the code 1
> resource, pushes its start address on the stack and jumps to it
> with RTS.
Sorry, I still don't unde
Smoking kills you slowly. But, I guess, you're not in a hurry. :-)
Quicker than non existent PalmOS viruses :-)
Chris Brooks.
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> Your original Question. "there is some startup code that calls
> PilotMain"
That's not a question - it's a statement. Please refer to my original message
at the beginning of this thread. It contained only one question and that
question was "How to determine the location of the first instru
At 06:39 AM 5/3/2005, you wrote:
When an executable application is loaded by PalmOS, where is the point
that receives control first? No, it is not PilotMain - it's much before
that; there is some startup code that calls PilotMain. How to determine
the location of the first instruction that will
On 2005-05-03, Dr. Vesselin Bontchev <[EMAIL PROTECTED]> wrote:
>> The execution starts at the first instruction of the code 1
>> resource.
>
> Thanks. Are you sure about this? That was one of the places I thought of
> checking and the code there didn't make much sense to me. It looks
> something l
Your original Question. "there is some startup code that calls PilotMain"
and my answer was correct. so it *was* your question
"The position of the entry point in the code 1 resource is probably also
compiler-dependent"
No, it would not be, the *name* could be different, the position could
> The execution starts at the first instruction of the code 1
> resource.
Thanks. Are you sure about this? That was one of the places I thought of
checking and the code there didn't make much sense to me. It looks something
like this:
ORI.B #1,D0 ; Set the lowest bit of D0 to 1? What for?
PEA $
> I believe it's called __startup__
How it is called depends on the compiler. But that wasn't my question. The
position of the entry point in the code 1 resource is probably also
compiler-dependent. My question was how does the *OS* find the first machine
language instruction in the application
On 2005-05-03, Chris Brooks <[EMAIL PROTECTED]> wrote:
> Yeah, I was right... it's declared like this:-
>
> UInt32 __Startup__ ( void )
> {
> }
>
>
> Dr. Vesselin Bontchev wrote:
>
>>Hello folks,
>>
>>When an executable application is loaded by PalmOS, where is the point that
>>receives control fir
Yeah, I was right... it's declared like this:-
UInt32 __Startup__ ( void )
{
}
Dr. Vesselin Bontchev wrote:
Hello folks,
When an executable application is loaded by PalmOS, where is the point that
receives control first? No, it is not PilotMain - it's much before that; there
is some startup code
I believe it's called __startup__
Chris Brooks
Dr. Vesselin Bontchev wrote:
Hello folks,
When an executable application is loaded by PalmOS, where is the point that
receives control first? No, it is not PilotMain - it's much before that; there
is some startup code that calls PilotMain. How to det
Hello folks,
When an executable application is loaded by PalmOS, where is the point that
receives control first? No, it is not PilotMain - it's much before that; there
is some startup code that calls PilotMain. How to determine the location of the
first instruction that will get executed in the
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