[EMAIL PROTECTED] (Chris Wagner) graced perl with these words of
wisdom:
Just for fun I did a little test.
for (1 .. 1) {
my $fn = rand();
++$dup and next if exists $num{$fn};
$num{$fn} = 1;
}
print scalar keys %num, unique numbers. $dup duplicates produced\n;
At 10:53 AM 12/1/2005 -0500, Ted Schuerzinger wrote:
Just for fun, I changed one of the lines in that to
for (1 .. 100) {
When I ran the modified script, I got 32768 unique numbers, with 967232
duplicates! As 32768 is a power of 2, I'm wondering if there's a limit on
the number of keys
Wait, I screwed up that last email. The uniques is the number of hash keys.
At 10:53 AM 12/1/2005 -0500, Ted Schuerzinger wrote:
for (1 .. 1) {
my $fn = rand();
++$dup and next if exists $num{$fn};
$num{$fn} = 1;
}
print scalar keys %num, unique numbers. $dup
On Thu, 1 Dec 2005 12:05:11 -0800, you wrote:
[EMAIL PROTECTED] (Chris Wagner) graced perl with these words of
wisdom:
Just for fun I did a little test.
for (1 .. 1) {
my $fn = rand();
++$dup and next if exists $num{$fn};
$num{$fn} = 1;
}
print scalar keys %num,
- Original Message -
From: Ted Schuerzinger [EMAIL PROTECTED]
To: Perl-Win32-Users@listserv.ActiveState.com
Sent: Friday, December 02, 2005 2:53 AM
Subject: Hash limits? (Was: Re: rand() not so random)
[EMAIL PROTECTED] (Chris Wagner) graced perl with these words of
wisdom:
Just
On Thu, 01 Dec 2005, Ted Schuerzinger wrote:
Just for fun I did a little test.
for (1 .. 1) {
my $fn = rand();
++$dup and next if exists $num{$fn};
$num{$fn} = 1;
}
print scalar keys %num, unique numbers. $dup duplicates produced\n;
Just for fun, I changed
