Sent: Thursday, January 27, 2005 11:50
To: [EMAIL PROTECTED]
Cc: Dirk Bremer; perl-win32-users@listserv.ActiveState.com;
[EMAIL PROTECTED]
Subject: RE: Regex Help
The reason that "200412" matches in your first regex is that the first
four characters match the pattern (as expected) but ther
To: <[EMAIL PROTECTED]>,
cc:
Subject: RE: Regex Help
Dirk,
I'm not a regex pro, but this worked for me: /^\d{4}(-\d{2}){0,2}$/
I tested it with this:
@test = qw( 2004 200412 20041201 2004-12 2004-12-01 );
foreach $test (@test) {
Title: RE: Regex Help
Okay, this is amazingly cloddish, but it does work and may point out where some of your regexes are going wrong. Whenever I have difficulty, I try to simplify it down and then analyze.
@strings = qw/ 2004 200412 20041201 2004-12 2004-12-01/;
for (@strings){
if
Dirk,
I'm not a regex pro, but this worked for me: /^\d{4}(-\d{2}){0,2}$/
I tested it with this:
@test = qw( 2004 200412 20041201 2004-12 2004-12-01 );
foreach $test (@test) {
print "$test : " . ($test =~ /^\d{4}(-\d{2}){0,2}$/ ? "TRUE" : "FALSE")
. "\n";
}
Regards,
Mike
-O
[EMAIL PROTECTED] <> wrote:
: I wrote a RegEx to let me know if a line of text has exactly
: 36 commas in it (the comma is the separator) and I came up
: with this. I don't think it is quite right. I could use a
: little pointing in the right direction. Any thoughts?
You could use tr/// to co
Any thoughts?
> >
> >
> >$lines[0] =~/^(.*?,){36}.*?$/
>
>
> $lines[0] =~ /^[^,](?:*,[^,]*){36}$/
I like Joe's answer, but if you must use a regex this one works:
print scalar(my @commas = $lines[0] =~ /(,)/g);
- Mark.
___
Perl-Win32-Users mailing l
There's a fun little idiom using tr/// to count the number of
occurances of a character in a string:
perl -le '$str = "a,b,c,d,e"; $count = ($str =~ tr/,/,/); print "$count"'
will output "4", the number of commas in "a,b,c,d,e".
--Kester
> Jeff Williams wrote, on Tue 12/14/2004 11:23
> :
at 09:23 AM 12/14/2004, Jeff Williams wrote:
I wrote a RegEx to let me know if a line of text has exactly 36 commas in
it (the comma is the separator) and I came up with this. I don't think it
is quite right. I could use a little pointing in the right direction. Any
thoughts?
$lines[0] =~/^(.*?,){3
Title: RegEx help
Jeff Williams wrote, on Tue 12/14/2004
11:23: I wrote a RegEx to let me know if a line of text
has exactly 36 commas init (the comma is the separator) and I came up with
this. I don't think itis quite right. I could use a little pointing in the
right direction. Anythough
$Bill wrote:
> ... and \1 is deprecated for $1.
I believe that should read [thanks Greg!] "...and \1 is deprecated on the
right
side of s///". On the left side (as in any regexp), \1 and $1 differ. But
as a holdover from sed, \1 means the same as
$1 on the right side of the subst.
\1 isn't the
Ganesh Babu Nallamothu, Integra-India wrote:
> Hi,
>
> Your Find patter is wrong.
> Use the following Pattern:
>
> s/([\t]\d{2}[:]\d{2}[\s])/\1/;
\t, \s and : do not need to be in a character class and \1 is deprecated for $1.
This should be equivalent:
s/(\t\d{2}:\d{2}\s)/$1/;
You s
Hi,
Your Find patter is wrong.
Use the following Pattern:
s/([\t]\d{2}[:]\d{2}[\s])/\1/;
Regards,
Gopal.R
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of
Malcolm Mill
Sent: Wednesday, November 03, 2004 2:41 AM
To: [EMAIL PROTECTED]
Subject: regex help
Ne
Title: RE: regex help
Assuming your dates are always in the same format, this would work:
print "$1\n" while ($_ =~ /(\d{1,2}\:\d{2} [ap]m)/gi);
-Pete
> -Original Message-
> From: Malcolm Mill [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, November 02, 2004 4
Jamie Murray wrote:
> Hi Glenn,
> I have worked on this further and looked at some of the previous posts.
> I have tried this with all different combinations of ip address and this has
> worked.
> Of course I got the idea from a previous post from Alex and Mark Thomas.
> Please understand I could
ced clarity.
Happy learning.
- Original Message - From: "Glenn Linderman" <[EMAIL PROTECTED]>
To: "Jamie Murray" <[EMAIL PROTECTED]>
Cc: "$Bill Luebkert" <[EMAIL PROTECTED]>;
<[EMAIL PROTECTED]>
Sent: Tuesday, January 13, 2004 6:24 PM
Subjec
Thanks for the discussion,clear explanation and advice Glenn.
- Original Message -
From: "Glenn Linderman" <[EMAIL PROTECTED]>
To: "Jamie Murray" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Wednesday, January 14, 2004 12:48 AM
Subject: Re:
t removes the complex redundancy, and can be expressed
in half the lines even with the enhanced clarity.
Happy learning.
- Original Message -
From: "Glenn Linderman" <[EMAIL PROTECTED]>
To: "Jamie Murray" <[EMAIL PROTECTED]>
Cc: "$Bill Luebkert" &
.$octet\.$octet\.$octet$/o;
print "yes" if $ip =~ $valid_ip;
- Original Message -
From: "Glenn Linderman" <[EMAIL PROTECTED]>
To: "Jamie Murray" <[EMAIL PROTECTED]>
Cc: "$Bill Luebkert" <[EMAIL PROTECTED]>;
<[EMAIL PROTECT
;
<[EMAIL PROTECTED]>
Sent: Tuesday, January 13, 2004 9:40 AM
Subject: Re: REGEX help!
BiLL,
If you check my second post I made the correction but I'm still correct in
my example and method.
Actually the e-mail from Raul Davletshin pretty much verifys what I had
also stated and he&#x
correct"
I'm all for learning and am just trying my best.
Thanks!
- Original Message -
From: "$Bill Luebkert" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, January 13, 2004 5:07 AM
Subject: Re: REGEX help!
> Jamie Murray wrote:
>
>
Jamie Murray wrote:
> Hey Alex,
> I jumped a little quick there, the previous post does work but I had a doh
> moment and forgot your upper range match could only be 254 at most.
> Sorry about that.
>
> if($num =~
> /^[0-2][0-5][0-4]\.[0-2][0-5][0-4]\.[0-2][0-5][0-4]\.[0-2][0-5][0-4]$/)
^^^
On approximately 1/12/2004 8:36 PM, came the following characters from
the keyboard of Jamie Murray:
Hey Alex,
I jumped a little quick there, the previous post does work but I had a doh
moment and forgot your upper range match could only be 254 at most.
Sorry about that.
if($num =~
/^[0-2][0-5][0-4
f ($ip =~ /^\d[0-254]\.\d[0-254]\.\d[0-254]\.\d[0-254]$/)
incorect way of matching ip address, it will work fore "61.14.95.02",
but will not work for "66.18.99.07". The problem here you just trying to
match 2 digital number instead of 3 digits. For example using "[]" [aDc]
true for "a" but not f
Hey Alex,
I jumped a little quick there, the previous post does work but I had a doh
moment and forgot your upper range match could only be 254 at most.
Sorry about that.
if($num =~
/^[0-2][0-5][0-4]\.[0-2][0-5][0-4]\.[0-2][0-5][0-4]\.[0-2][0-5][0-4]$/)
after each class [] use {num,num} to adjust
alex p wrote:
> Hello all,
> I have been trying to find a regex to validate IP ranges and found the
> following:
>
> m{
>^ ( \d | [01]?\d\d | 2[0-4]\d | 25[0-5] )
> \. ( \d | [01]?\d\d | 2[0-4]\d | 25[0-5] )
> \. ( \d | [01]?\d\d | 2[0-4]\d | 25[0-5] )
> \. ( \d | [0
just a stab
starts with
any digit(s) = any number of digits or
= 0 or 1 or none(?=can be none but at most 1) followed by any 2 numbers
= 2 followed by number between 0 and 4 followed by any number
= 25 followed by any number between 0 and 5
followed by "."
the rest is repeat (I think that cookbo
how
about sorting the letters first:
$var="meqgvn";
$sortedvar=join("", sort(split("",
$var)));
if
($sortedvar eq "egmnqv") { print
"yes!\n";}
--ken
-Original Message-From: Dax T. Games
[mailto:[EMAIL PROTECTED]Sent: Tuesday, September 02, 2003
12:26 PMTo: Perl UsersS
$Bill Luebkert wrote:
> Dax T. Games wrote:
>
>
>>I have a list of characters. I need to get a list of all possble
>>sequences of these characters for example.
>>
>>I have a string that consists of '-mevqgn' I need to pattern match any
>>combination of 'mevqgn' with a preceding - or --.
>>
>
At 01:26 PM 9/2/2003, Dax T. Games wrote:
I have a
list of characters. I need to get a list of all possble sequences
of these characters for example.
I have a string that consists of '-mevqgn' I
need to pattern match any combination of 'mevqgn' with a preceding - or
--.
Right now this is w
Equally dirty, but possibly more flexible:
$_='aSdFgHjk'; # Letters to look
for.
$alpha1=lc(join('',sort(split(//;
$LS_Val=shift;
$LS_Val=~s/^-//g; # Drop preceding dashes
$alpha2=lc(join('',sort(split(//,$LS_Val;
if
($alpha1 eq $alpha2) {print "Pattern found!\n";}
It looks like you may be doing standard command line option
parsing (or almost standard as the '--' prefix is reserved
for long option names). If this is so, look at GetOpt::Std .
For a subroutine that does what you specified (tested):
sub is_DTG_Option ($)
{
my $opt = shift;
return 0
Wow... looks like some good replies to this one. Here's a less
elegant, recursive approach (until I learn map :-)
#!perl -w
# print all 720 permutations using letters: e m v q g n
use strict;
sub mutate {
my ($in) = @_;
if (length($in) == 6) {
print "$in\n";
$in = '';
} else {
On Tue, 2 Sep 2003, Dax T. Games wrote:
> I have a list of characters. I need to get a list of all possble sequences of these
> characters for example.
>
> I have a string that consists of '-mevqgn' I need to pattern match any combination
> of 'mevqgn' with a preceding - or --.
>
> Right now th
Here
is another variation...
#!/usr/bin/perl
check('-mevqgn');check('-memqgn');check('-ngmevq');check('--meqvgn');
sub check{ my $LS_Val = shift;
if ($LS_Val =~ /-{1,2}([mevqgn]{6})/ and
unique_chars($1)) { print "Ding
Ding! $LS_Val is good!\n"; } else
{ pr
Have you tried playing around with character sets? Something like
$target = 'mevqgn';
$length_target = length $target;
if ( $LS_Val =~ /-{1,2}[$target]{$length_target}/ ) {
#do something
}
Whether the above would work for you would depend on whether the code
can ignore positive matches on $LS_
I wanted to use tr but was uanble to accomplish the
task that way. So I used regex like the following:
use strict;
my %MCTWW = qw(m -1 e -1 v -1 q -1 g -1 n -1);my $MyCharsToWorkWith =
\%MCTWW;
$_ = '--mepqgn ';
if ( ! /-{1,2}(\S+)/ ) { printf "Expecting a hyphen
or two floowed
Dax T. Games wrote:
> I have a list of characters. I need to get a list of all possble
> sequences of these characters for example.
>
> I have a string that consists of '-mevqgn' I need to pattern match any
> combination of 'mevqgn' with a preceding - or --.
>
> Right now this is what I am d
> I'm trying to match a string which would start with http://,
> then a character string where there is one one or more
> instances of "%", followed by one instance of ".com", i.e.
> http://www.%55.com
>
> Here is my current pattern:
> http://.*%+.*(\.com)
>
> However, if there are tw
Bullock, Howard A. wrote:
You could cheat a little instead of trying to do it with just a RE, use
an embeded tr/// or s///:
my $text = 'axxxccvvvacasdcxaswrefajjawerasdcxaswrefajhhaasera';
$text =~ s#(.*?)# my $x = $1; $x =~ tr/a/8/; sprintf '%s', $x
#eg;
Your two little dashes make my client
You could cheat a little instead of trying to do it with just a RE, use
an embeded tr/// or s///:
my $text = 'axxxccvvvacasdcxaswrefajjawerasdcxaswrefajhhaasera';
$text =~ s#(.*?)# my $x = $1; $x =~ tr/a/8/; sprintf '%s', $x
#eg;
--
Thanks. The main problem I was having was I couldn't find th
Bullock, Howard A. wrote:
I want to alter some characters in a text variable, but only those
between two markers.
$text = 'axxxccvvvacasdcxaswrefajjawerasdcxaswrefajhhaasera';
I want to specify the start and the end and only change the a's
to 8's between the markers. How do I accomplish this
* Stephen Patterson ([EMAIL PROTECTED]) wrote:
> I have a scalar, $doc, which contains a plain ascii file, and which
> I'll be storing on a database (for searching).
>
(...)
>
> Can anyone help?
There's a module called Whitespace on CPAN, would that work for you?
Additionnally, there's also a S
Joseph P. Discenza wrote:
> Stephen Patterson wrote, on
> : To minimise the space needed to store this file, I'd like to remove
> : all non-word characters and punctuation (except whitespace), and
> : replace multiple whitespaces with single whitespaces.
> :
> : For efficiency, I'd like to do it
Nice. Really!
Wags ;)
-Original Message-
From: dolljunkie [mailto:[EMAIL PROTECTED]]
Sent: Thursday, January 10, 2002 11:09
To: [EMAIL PROTECTED]
Subject: Re: Regex Help Please!
A less elegant (perhaps) solution, but effective, no matter how many rows /
values:
while
A less elegant (perhaps) solution, but effective, no matter how many rows /
values:
while(<>) {
s/\r//g; # I hate that carriage return
chomp;
next if(!/^.*<\!--/); # skip non-matching lines
my @values;
my $ts = $1 if(s/<\!--\s*(.*?)\s*-->//);
my($ts1,$ts2) = split(/\s*
:: -Original Message-
:: From: Gordon Brandt [mailto:[EMAIL PROTECTED]]
:: Sent: Thursday, January 10, 2002 12:17 PM
:: To: [EMAIL PROTECTED]
:: Subject: Regex Help Please!
::
:: [-snip-]
::
:: Input file:
:: |
::
:: (misc header information I want to delete)
::
:: #Thi
7;; [EMAIL PROTECTED]
Subject: RE: Regex Help Please!
Works but not if you have more or fewer than 2 values in a row.
Do you?
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED]]On Behalf Of
> Wagner-David
> Sent: Thursday, January 10, 2002 1:31 PM
>
Works but not if you have more or fewer than 2 values in a row.
Do you?
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED]]On Behalf Of
> Wagner-David
> Sent: Thursday, January 10, 2002 1:31 PM
> To: 'Gordon Brandt'; [EMAIL PROTECTE
Here is a simplistic approach. May want more edits, but is a starting place.
Placing the data for testing under DATA:
while ( ) {
chomp;
next if ( /^\s*$/ ); # bypass blank lines
if ( /^ (.+) <\/v> (.+) <\/v><\/row>/ ) {
printf "%-s, %-s, %-s, %-s\n", $1, $2, $
"perl-win32-users" <[EMAIL PROTECTED]>
> Sent: Tuesday, March 27, 2001 4:05 PM
> Subject: Re: Regex Help
>
>
> >
> >
> > Try using this:
> >
> > use File::Basename; # fo
Dirk Bremer wrote:
>
> I want to build a regular expression that will separate a filename string into the
>root name, filename, and extension name, placing
> the results in $1, $2, $3.
[remainder snipped]
Why not just use File::Basename? It does just what you want, if I read
your question corr
;[EMAIL PROTECTED]>
>To: "Dirk Bremer" <[EMAIL PROTECTED]>
>Cc: "perl-win32-users" <[EMAIL PROTECTED]>
>Sent: Tuesday, March 27, 2001 4:05 PM
>Subject: Re: Regex Help
>
>
> >
> >
> > Try using this:
> >
I tried this and it seemed to work:
my $InputLine = '(! SUBSTR(DB.USER1,2,5)="9") .AND.
(LEFT(DB.USER1,1)<"1") .AND. (ALLTRIM(DB.OUNCEWT)>"2")';
my $InputLine1 = '(! SUjSTR(DB.USER1,2,5)="9") .AND.
(LEFT(DB.USER1,1)<"1") .AND. (ALLTRIM(DB.OUNCEWT)>"2")';
my $Str = '(! SUBSTR(DB.USER1,2,5)
"Bullock, Howard A." wrote:
>
> Is there a way to get the following text to match? If the '\' in '1\V' is
> changed, the regex matches. I would like to maintain the RAW text if
> possible.
>
> $c = 'JUA_APPS01\VOL1:\APPS';
> $d = 'JUA_APPS01\VOL';
> if ($c =~ /$d/)
> {
> print "matched\n
54 matches
Mail list logo
