Pete Lomax wrote:
Leo clarified this as a problem with backward branch circa 3/12/03:
Sorry to be a pain in the butt, but I need to be told that there has
been no improvement in the last two months on this ;-(
..sub _main
goto L1
test:
$I1 = 1
ret
L1:
$I2 = 2
Pete Lomax [EMAIL PROTECTED] wrote:
Leo clarified this as a problem with backward branch circa 3/12/03:
Surely it can't just be me that thinks this is rather fundamental?
How fundamental *is* the problem, can it *ever* be fixed?
It can be fixed. It'll take a lot of overhead. Following all
[EMAIL PROTECTED] (Leopold Toetsch) writes:
It can be fixed. It'll take a lot of overhead. Following all branches in
spaghetti code is a PITA.
Just don't do that. Separate your subs in distinct compilation units.
And then you don't need to worry about the fact that Parrot running
At 1:12 AM + 2/3/04, Pete Lomax wrote:
Leo clarified this as a problem with backward branch circa 3/12/03:
Sorry to be a pain in the butt, but I need to be told that there has
been no improvement in the last two months on this ;-(
Short answer: Don't do that.
Longer answer: IMCC ought to
Dan Sugalski wrote:
Your code is fine. It *should* work. That it doesn't is a bug, which
needs fixing. For now you're going to have to work around it.
I would have swore the code was wrong. Am I being naive thinking that a
call to a sub is different than what looked like a call to a label. On
Leo clarified this as a problem with backward branch circa 3/12/03:
Sorry to be a pain in the butt, but I need to be told that there has
been no improvement in the last two months on this ;-(
.sub _main
goto L1
test:
$I1 = 1
ret
L1:
$I2 = 2
call test
On Tue, 3 Feb 2004, Pete Lomax wrote:
.sub _main
goto L1
test:
$I1 = 1
ret
L1:
$I2 = 2
call test
print $I2 # prints 1, not 2
end
.end
...
Again, sorry to be a pain, but I'd like the truth/an update, please!
Or some hints... file
On Mon, 2 Feb 2004 20:51:21 -0500 (EST), Michal Wallace
[EMAIL PROTECTED] wrote:
On Tue, 3 Feb 2004, Pete Lomax wrote:
.sub _main
goto L1
test:
$I1 = 1
ret
L1:
$I2 = 2
call test
print $I2 # prints 1, not 2
end
.end
Huh. That is pretty
