Juerd wrote:
No, again, please do not make the mistake of thinking VALUES have
identity. VARIABLES (containers) do. A reference points to a container,
never to a value directly.
I don't consider it a mistake. So, you dany identity to fat values
like database connections or GUI objects?
This is
Thomas Sandlaß skribis 2005-05-10 19:02 (+0200):
Juerd wrote:
No, again, please do not make the mistake of thinking VALUES have
identity. VARIABLES (containers) do. A reference points to a container,
never to a value directly.
I don't consider it a mistake.
That is a problem.
So, you
On May 4, 2005, at 2:38 PM, Thomas Sandlaß wrote:
Aaron Sherman wrote:
If we agree that the first say should print 7, then we must conclude
that either we've changed the value of undef to 7, or we've created a
circular reference.
In my view of refs 7 is printed, indeed. But I've difficulty to
Autrijus Tang skribis 2005-05-04 21:13 (+0800):
What should this do, if not infinite loop?
my ($x, $y); $x = \$y; $y = \$x; $x[0] = 1;
I'm still against any explict scalar dereferencing, so: fail,
complaining about $x not being an arrayreference (not knowing how
to handle postcircumfix:[
Juerd skribis 2005-05-04 15:18 (+0200):
I'm still against any explict scalar dereferencing, so: fail,
complaining about $x not being an arrayreference (not knowing how
to handle postcircumfix:[ ]).
Ehm :)
s/explicit/implicit/
Juerd
--
http://convolution.nl/maak_juerd_blij.html
On Wed, May 04, 2005 at 03:18:29PM +0200, Juerd wrote:
: Autrijus Tang skribis 2005-05-04 21:13 (+0800):
: What should this do, if not infinite loop?
: my ($x, $y); $x = \$y; $y = \$x; $x[0] = 1;
:
: I'm still against any explict scalar dereferencing, so: fail,
: complaining about $x not
On Wed, May 04, 2005 at 09:38:58PM +0800, Autrijus Tang wrote:
: On Wed, May 04, 2005 at 06:24:34AM -0700, Larry Wall wrote:
: Yes, it doesn't immediately deref as an array, so it fails.
:
: Oh. So autodereference is only one level? I got it all wrong
: in Pugs, then. I wonder where I got
Autrijus Tang wrote:
What should this do, if not infinite loop?
my ($x, $y); $x = \$y; $y = \$x; $x[0] = 1;
Hmm, after the my both $x and $y store an undef.
Then $x stores a ref to undef. Then $y stores
a ref to ref of undef. I see no circle.
Now let's look at $x = 1. I think it goes down
to
On Wed, May 04, 2005 at 05:30:48PM +0200, Thomas Sandla wrote:
Autrijus Tang wrote:
What should this do, if not infinite loop?
my ($x, $y); $x = \$y; $y = \$x; $x[0] = 1;
Hmm, after the my both $x and $y store an undef.
Then $x stores a ref to undef. Then $y stores
a ref to ref of
Autrijus Tang wrote:
If the reference semantics changed drastically, please
reflect it prominiently in the relevant Synopsis. :)
Unfortunately I don't feel entitled to do so. I'm
just an interessted bystander, not a member of the
design team.
Sorry.
--
TSa (Thomas Sandlaß)
Thomas Sandlaß skribis 2005-05-04 17:30 (+0200):
my ($x, $y); $x = \$y; $y = \$x; $x[0] = 1;
Hmm, after the my both $x and $y store an undef.
Then $x stores a ref to undef. Then $y stores
a ref to ref of undef. I see no circle.
No, again, please do not make the mistake of thinking VALUES
On Wed, 2005-05-04 at 11:30, Thomas Sandlaß wrote:
Autrijus Tang wrote:
What should this do, if not infinite loop?
my ($x, $y); $x = \$y; $y = \$x; $x[0] = 1;
Hmm, after the my both $x and $y store an undef.
Then $x stores a ref to undef. Then $y stores
a ref to ref of undef. I
Aaron Sherman wrote:
Squint harder ;-)
I'm trying!
If we agree that the first say should print 7, then we must conclude
that either we've changed the value of undef to 7, or we've created a
circular reference.
In my view of refs 7 is printed, indeed. But I've difficulty to understand
what you
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