On 10/9/18 5:42 AM, Fernando Santagata wrote:
The answer Laurent Roseenfeld gave you works for read and readchars as well.
Save the following lines in a file and run it (try and change .read into
.readchars too); it will output a series of 10-byte long Buf[uint8]s,
until it reaches the end of fi
Le mar. 9 oct. 2018 à 14:49, ToddAndMargo via perl6-users
mailto:perl6-users@perl.org>> a écrit :
On 10/9/18 5:42 AM, Fernando Santagata wrote:
> The answer Laurent Roseenfeld gave you works for read and
readchars as well.
> Save the following lines in a file and run it (try an
On 10/9/18 6:22 AM, Curt Tilmes wrote:
On Tue, Oct 9, 2018 at 8:49 AM ToddAndMargo via perl6-users
mailto:perl6-users@perl.org>> wrote:
I am not getting anywhere with `.lines`. Read the whole thing in the
first line.
$ p6 'my $fh=open "/home/linuxutil/WhoIsMySub.pl6", :r; whil
On 10/9/18 4:36 PM, ToddAndMargo via perl6-users wrote:
$ p6 'my $fh=open "/home/linuxutil/WhoIsMySub.pl6", :r; my Buf $f =
$fh.read(100); $fh.close; say "<" ~ $f.decode("utf-8") ~ ">";'
I changed `$f.decode("utf-8")` to `$f.decode("utf8-c8")` as
you never know what a web page will have on it
On 10/9/18 6:26 AM, Curt Tilmes wrote:
On Tue, Oct 9, 2018 at 9:21 AM ToddAndMargo via perl6-users
mailto:perl6-users@perl.org>> wrote:
Yes, I know there are other ways to read a file. I
have a specific reason for using `read`.
How do I properly turn a Buf into a Str (all the
100% thanks a lot. :)
On Tue, 9 Oct 2018 at 16:31, Timo Paulssen wrote:
> --output is for the compiler's compilation stages
>
> for example:
>
> timo@schmand ~> perl6 --output=/tmp/outputtest --target=mbc -e 'say "hi"'
> timo@schmand ~> moar --dump /tmp/outputtest | head
>
> MoarVM dump of binar
--output is for the compiler's compilation stages
for example:
> timo@schmand ~> perl6 --output=/tmp/outputtest --target=mbc -e 'say "hi"'
> timo@schmand ~> moar --dump /tmp/outputtest | head
>
> MoarVM dump of binary compilation unit:
>
> SC_0 : B1DFAD9164F11E967B354508CC458ABAB8DEDC27
> SC_
That isn't the syntax for a loop local variable in Perl 6.
You are trying to use the Perl 5 syntax, which is not going to work in Perl 6
This is the Perl 5 code you are trying to write
while( my $f = readline $fh ){ say "$f\n"}
Which actually would turn into the following by Perl 5 compiler
It feels like a bug. I more wanted to know if anyone knew anything about it
for the talk.
Thanks
On Tue, 9 Oct 2018, 14:49 Brad Gilbert, wrote:
> My guess is that this is a bug.
>
> You can work around it by adding
>
> my $*OUT = q[test].IO.open(:w);
>
> in front of the code.
> On Tue, Oct
My guess is that this is a bug.
You can work around it by adding
my $*OUT = q[test].IO.open(:w);
in front of the code.
On Tue, Oct 9, 2018 at 8:18 AM Simon Proctor wrote:
>
> So... I'm working through some notes for a talk on Thursday and I am trying
> to work out how the --output flag is
On Tue, Oct 9, 2018 at 8:31 AM Curt Tilmes wrote:
>
> On Tue, Oct 9, 2018 at 9:27 AM Laurent Rosenfeld via perl6-users
> wrote:
>>
>> This:
>> my $f = $fh.lines;
>> will slurp all the lines into $f (but you can still access the individual
>> items with something like $f[4]).
>
>
> Is that true?
Yes, you're right, it is a Seq. I was trying to be pedagogical, but
probably wasn't very accurate. It is a Seq, and the "slurping" will be lazy.
Le mar. 9 oct. 2018 à 15:30, Curt Tilmes a écrit :
> On Tue, Oct 9, 2018 at 9:27 AM Laurent Rosenfeld via perl6-users <
> perl6-users@perl.org> wrote
On Tue, Oct 9, 2018 at 9:27 AM Laurent Rosenfeld via perl6-users <
perl6-users@perl.org> wrote:
> This:
> my $f = $fh.lines;
> will slurp all the lines into $f (but you can still access the individual
> items with something like $f[4]).
>
Is that true? I supposed that it would hold the Seq as a
This:
my $f = $fh.lines;
will slurp all the lines into $f (but you can still access the individual
items with something like $f[4]).
So you don't want to use this in a while loop, since everything will be
consumed during the first loop iteration. Either use a for loop to process
the lines one by o
On Tue, Oct 9, 2018 at 9:21 AM ToddAndMargo via perl6-users <
perl6-users@perl.org> wrote:
>
> Yes, I know there are other ways to read a file. I
> have a specific reason for using `read`.
>
> How do I properly turn a Buf into a Str (all the bytes will
> have been tested to make sure they are pri
On Tue, Oct 9, 2018 at 8:49 AM ToddAndMargo via perl6-users <
perl6-users@perl.org> wrote:
>
> I am not getting anywhere with `.lines`. Read the whole thing in the
> first line.
>
> $ p6 'my $fh=open "/home/linuxutil/WhoIsMySub.pl6", :r; while my $f =
> $fh.lines { say "$f\n"}; $fh.close;'
>
.l
Hi All,
Yes, I know there are other ways to read a file. I
have a specific reason for using `read`.
How do I properly turn a Buf into a Str (all the bytes will
have been tested to make sure they are printable first)?
$ p6 'my $fh=open "/home/linuxutil/WhoIsMySub.pl6", :r; my Buf $f =
$fh.rea
So... I'm working through some notes for a talk on Thursday and I am trying
to work out how the --output flag is supposed to work.
I would expect this to create a file called test and print "Hi\n" in it :
perl6 --output=test -e 'say "Hi"'
But instead I got Hi printed to the command line and an e
On 10/9/18 5:42 AM, Fernando Santagata wrote:
The answer Laurent Roseenfeld gave you works for read and readchars as well.
Save the following lines in a file and run it (try and change .read into
.readchars too); it will output a series of 10-byte long Buf[uint8]s,
until it reaches the end of f
On 10/9/18 5:03 AM, ToddAndMargo via perl6-users wrote:
Le mar. 9 oct. 2018 à 10:03, ToddAndMargo via perl6-users
mailto:perl6-users@perl.org>> a écrit :
Hi All,
When reading a text file
https://docs.perl6.org/routine/lines
seems pretty straight forward.
Question: How do
The answer Laurent Roseenfeld gave you works for read and readchars as well.
Save the following lines in a file and run it (try and change .read into
.readchars too); it will output a series of 10-byte long Buf[uint8]s, until
it reaches the end of file.
#!/usr/bin/env perl6
given $*PROGRAM-NAME.IO
Le mar. 9 oct. 2018 à 10:03, ToddAndMargo via perl6-users
mailto:perl6-users@perl.org>> a écrit :
Hi All,
When reading a text file
https://docs.perl6.org/routine/lines
seems pretty straight forward.
Question: How do I tell when I when I have
reached the EOF (End Of Fil
On 10/7/18 1:25 AM, ToddAndMargo via perl6-users wrote:
Hi All,
I am going to possibly be writing binary code to my terminal.
This can really screw up your terminal. THe solution is
to enter
sane^j
on your keyboard. The ^ above is holding down your key.
I would like to be able to sen
The eof method of the IO::Handle class returns True if you exhausted the
contents of the handle, but you generally don't need to use that, since
something like:
for 'input.txt'.IO.lines -> $line {
# Do something with $line
}
will gracefully handle ends of files for you without you having to d
On 10/8/18 5:33 AM, Curt Tilmes wrote:
On Mon, Oct 8, 2018 at 7:53 AM ToddAndMargo via perl6-users
mailto:perl6-users@perl.org>> wrote:
I take it that `Buf` is a special type of array that the normal
rules do not apply to.
I would say rather than each of them (Buf and Array) are sp
On 10/9/18 1:02 AM, ToddAndMargo via perl6-users wrote:
Hi All,
When reading a text file
https://docs.perl6.org/routine/lines
seems pretty straight forward.
Question: How do I tell when I when I have
reached the EOF (End Of File)?
Many thanks,
-T
Please expand the question to include `
Hi All,
When reading a text file
https://docs.perl6.org/routine/lines
seems pretty straight forward.
Question: How do I tell when I when I have
reached the EOF (End Of File)?
Many thanks,
-T
27 matches
Mail list logo