On December 26, 2003 06:37 pm, Tom Lane wrote:
> accumulated roundoff in the monetary amounts. I think you will
> need to write a little function (in plpgsql or your language of
> choice) that performs the sequence of compounding steps, if you
> want to get an answer that a banker will like.
And
Definition of log (base n) is that log n(x) = y where n^y = x for all values
of x and y. n is the base.
So a base 10 log would be reversed by doing 10^x=y. If we know x, we use
the exponential operation; if we know y we use log(y) = x. For ln (natural
logs, base e, e is approx. 2.818), use e^x=
Dear Martin Marques and other kind people out their ,
In mathematics I would have written it something like
A = antilog (3·3234) = 2144
As I can understand, this is a 10 base log, so that what you want is
10^(3.3234)?
Though antilog did not solve my problem the link below helped me to
p
Sai Hertz And Control Systems <[EMAIL PROTECTED]> writes:
>> What is the mathematical operation that "antilog" is supposed to perform?
> Its going to calculate rate of intrest for an fixed deposit ,
This is not a mathematical operation, it is a financial issue
that has to conform to rules develo
rom: Martin Marques <[EMAIL PROTECTED]>
> To: [EMAIL PROTECTED],
> Sai Hertz And Control Systems <[EMAIL PROTECTED]>,
> [EMAIL PROTECTED]
> Cc: [EMAIL PROTECTED]
> Subject: Re: [SQL] Anti log in PostgreSQL
>
i> El Vie 26 Dic 2003 19:12, Sai Hertz And Control
Dear Wei Weng ,
Nope
select exp(3.3234) as a2144
Gives me
27.754555808589792
But the answer expected is some what near to 2144
The log tables show this
Regards,
Vishal Kashyap.
What is the mathematical operation that "antilog" is supposed to perform?
Its going to calculate rate of intrest for an
El Vie 26 Dic 2003 19:46, Sai Hertz And Control Systems escribió:
> Dear Martin Marques ,
>
> >>In mathematics I would have written it something like
> >>
> >>A = antilog (3·3234) = 2144
> >>
> >>
> >
> >As I can understand, this is a 10 base log, so that what you want is
> >10^(3.3234)?
> >
Sai Hertz And Control Systems wrote:
Dear Martin Marques ,
In mathematics I would have written it something like
A = antilog (3·3234) = 2144
As I can understand, this is a 10 base log, so that what you want is
10^(3.3234)?
For that you have the exponential operator ^.
Nope
select exp(3
Dear Martin Marques ,
In mathematics I would have written it something like
A = antilog (3·3234) = 2144
As I can understand, this is a 10 base log, so that what you want is
10^(3.3234)?
For that you have the exponential operator ^.
Nope
select exp(3.3234) as a2144
Gives me
27.7545558085
El Vie 26 Dic 2003 19:12, Sai Hertz And Control Systems escribió:
> Dear all ,
>
> In one of our project I require to calculate antilog of (3.3234)
> But I could not find any functions in Documentation for the same.
>
> In mathematics I would have written it something like
>
> A = antilog (3·32
Dear all ,
In one of our project I require to calculate antilog of (3.3234)
But I could not find any functions in Documentation for the same.
In mathematics I would have written it something like
A = antilog (3·3234) = 2144
Any suggestions or links are most welcome .
Regards,
Vishal Kashyap.
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