Re: [SQL] help yourself by helping others

2003-07-13 Thread Rajesh Kumar Mallah
dear ali, something like select machine,date_part('day' , date) , sum(withdrawals) from Table where date_part('month' , date)='month in question' group by machine,date_part('day' , date) ; will give you agrregated withdrawals by machine and day, use the frontend language for formatting it. no

[SQL] help yourself by helping others

2003-07-09 Thread Ali Adams
Dear All,   I am new to Relational Databases and SQL and my background in ODBs is clouding my way to solving what seems to be a simple problem. I am sure many of you have met it many times.   OK, I have a table as follows:     ID Machine   Date Withdrawals 1  1  01/