Am Mittwoch, 28. März 2007 00:17 schrieb Phillip Smith:
> Perhaps this...? It would work, but depending how many rows are in the
> table, it could become incredibly slow.
>
> ALTER TABLE table1 ADD CHECK (extension NOT IN (SELECT extension FROM
> table2));
Subqueries are not allowed in check const
Richards and List,
Now I find out the 'similar to' statement where I can do such search, but I
must still parse all substrings.
Here is my stage:
Select * from myAddressTable where address similar to ('%(ELMO|ST.|258)%')
But I still need to Separete all strings.
Could someone help me in thi
Subqueries are not allowed in check constraints.
I hadn't tried this yet but i'm sure i would have figured this out
quickly then =)
Thanks,
Jon
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> Select * from myAddressTable where address similar to ('%(ELMO|ST.|258)%')
>
> But I still need to Separete all strings.
What is it that you are trying to achieve? What string would you like to
seperate?
Regards,
Richard Broersma Jr.
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Hi dudes, i have the following question
i have 2 tables with the same format, and i want to know if is there a
possibility of using some sort of count(*) for achieving this result:
select a from table1 where (condition) union select a from table2 where
(condition), count(a) group by a
The idea
am Wed, dem 28.03.2007, um 11:04:29 -0300 mailte Gerardo Herzig folgendes:
> Hi dudes, i have the following question
> i have 2 tables with the same format, and i want to know if is there a
> possibility of using some sort of count(*) for achieving this result:
> select a from table1 where (condi
--- Gerardo Herzig <[EMAIL PROTECTED]> wrote:
> Hi dudes, i have the following question
> i have 2 tables with the same format, and i want to know if is there a
> possibility of using some sort of count(*) for achieving this result:
> select a from table1 where (condition) union select a from ta
Thanks! But now i have another problem related with count():
select page_id, word, word_position, count(page_id) from (select * from
search_word('word1', 'table1') union search_word('word2', 'table2')) foo
group by page_id;
and gives me "foo.word must appear in GROUP clause or be used in an
I have the following situation that I would appreciate your input on:
I have a table with a column that I use to uniquely identify its rows.
The table also has a rule on insert that stores the row identifier into
another table for reference at some other point.
The table is defined as
CREATE
Ray Madigan <[EMAIL PROTECTED]> writes:
> Does anyone have any suggestion?
Use a trigger to propagate the data to the other table. You can't make
this work reliably with a rule, because rules are macros and hence
inherently subject to double-evaluation problems when dealing with
volatile function
Gerardo Herzig <[EMAIL PROTECTED]> schrieb:
> Thanks! But now i have another problem related with count():
>
> select page_id, word, word_position, count(page_id) from (select * from
> search_word('word1', 'table1') union search_word('word2', 'table2')) foo
> group by page_id;
>
> and gives me
Below is a select statement that select incidents by month. I need a
function or a method to select differents views that will show the Month
columns is a different order. Say Apr - Mar for a fiscal year.
I need to do something like an if/then/else statement that selects the
correct view to us
Hi all,
I have ran a update query on a dataset which has about 48 million records
and the query is already running for the third dayim so tempted to the
kill this query nowis there a way to know if the query is running??
here is the query i've ran
UPDATE ma SET av=to_tsvector('default',c
On Wed, Mar 28, 2007 at 04:59:24PM -0400, Sumeet wrote:
> Hi all,
>
> I have ran a update query on a dataset which has about 48 million records
> and the query is already running for the third dayim so tempted to the
> kill this query nowis there a way to know if the query is running??
> h
Is that an 8.2 thing? I'm sure I've done it before, probably in 8.1
Maybe it was a trigger I did it in - I can't remember what I had for
breakfast, let alone a slow sub-query I did months ago :P
Cheers,
~p
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of
Hi all,
I'm trying to create a view of the query below, but I'm being barked at
about "rules on SELECT must have action INSTEAD SELECT". I don't have any
rules in my database, and I don't know how this query is trying to create
one. The query does work if I just run it interactively. Any help w
On Thu, Mar 29, 2007 at 03:35:52PM +1000, Phillip Smith wrote:
> I'm trying to create a view of the query below, but I'm being barked at
> about "rules on SELECT must have action INSTEAD SELECT". I don't have any
> rules in my database, and I don't know how this query is trying to create
> one.
ht
Thanks Michael - The 2 queries (sorry, should have said transaction) are a
simple way to identify duplicates in our mailing list. If there are
triplicates, the first query will return 6 rows into the temp table, 1 for
each of the 2 duplicates), but I only need to show the 3 triplicates once
each, n
Phillip Smith wrote:
I'm trying to create a view of the query below, but I'm being barked at
about "rules on SELECT must have action INSTEAD SELECT". I don't have any
rules in my database, and I don't know how this query is trying to create
one. The query does work if I just run it interactively
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