you have to change the Content-Type header or something (text/html) but the
easiest way is to use a pre-packed class (unless you really want to do it
yourself). Check out hotscripts or just do a google for "php mail class" or
similar :)
HTH
Beau
// -Original Message-
// From: CrossWalkC
How can I use the Mail function to send html data.
I have like a welcome letter I am working on and when the user signs up for
such services I want this to be sent to them.
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Thanx... it worked using double quotes around the variable name
({$HTTP_POST_VARS["varname"]}
- Original Message -
From: "Marcelo Leitner" <[EMAIL PROTECTED]>
To: "César L. Aracena @hellfire.leitner.homeip.net"
<[EMAIL PROTECTED]@hellfire.leitner.homeip.net,>
Cc: "PHP DB List" <[EMAIL PRO
Hi Dave,
Load the data from the text file into a variable (eg, $fileContents)
Then split the file into an array and run every sql statement.
The following code should work...
Adam
$arrSQL = explode(";",$fileContents);
for ($i=0;$i
that function doest exist!
"Peter" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Windows Bitmap = BMP file
> a WBMP is a wireless bitmap image and is designed for display on mobile
> phones. A lot of software doesn't understand the format.
>
> You need to use
Windows Bitmap = BMP file
a WBMP is a wireless bitmap image and is designed for display on mobile
phones. A lot of software doesn't understand the format.
You need to use createfrombmp() not createfromwbmp()
"Georgie Casey" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PRO
i'm getting an error message saying my BMP file i'm trying to convert isnt a
valid WBMP file? is dere a difference between BMP and WBMP? I just opened my
GIF file into PSP7 and and saved as a windows bmp.
why isnt it working?
"Peter" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[E
Hi all,
I have a 3-page form input, where the variables are passed from one page to another
using HTTP_POST_VARS and stored in the next one in HIDDEN fields (just to make sure).
At the end of the 3rd page, is another one where I thank the visitor and proccess all
the data.
The data proccess c
";
print "";
?>
you get the idea
I think PHP does have other funtions for file uplading though.
"Georgie Casey" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Rite, when you see a web form, you know you can simulate the submit by
> filling in the values in th
Rite, when you see a web form, you know you can simulate the submit by
filling in the values in the address field, just like a GET method, and it
usually works the exact same. But how do you do it when one of the fields in
the form is a file upload?!?!?!
For the record, its a GIF file you've to u
Ok craked it... yes me i craked it:-)
All you need to do is create an array from your sql like this:
1st place your dumped sql statement into a varibale.
2nd create an array from your sql like this
if(isset($your_execution_va
> I think it an issue with including multiple sql commands in one var...
Yup, you can't do that. Simply separate them and do them one at a time.
-Rasmus
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Hi Rasmus
I think it an issue with including multiple sql commands in one
var...
as i see it...:
the drop table bit is one coomand and the create table is one
command.
When i run these with or with the seperating ;
$sql= ".
you forgot the " :)
Thanks,
- Original Message -
From: "Dave Carrera" <[EMAIL PROTECTED]>
To: "php List" <[EMAIL PROTECTED]>
Sent: Sunday, May 26, 2002 11:01 AM
Subject: [PHP-DB] db sql issue from var
Hi All
I have found the problem from my last post and need to know how
Ah, there is the issue. You cannot issue 2 SQL queries in a single
mysql_query() call. You have to do them one at a time without the ;
-Rasmus
On Sun, 26 May 2002, Janet Valade wrote:
> Can't you do what you want to do without using two SQL statements?
>
> CREATE TABLE IF NOT EXISTS.
>
> Janet
Well, where is your ';'? At the end of the statement? You don't
terminate queries with semi colons when talking directly to the database.
Just remove it.
-Rasmus
On Sun, 26 May 2002, Dave Carrera wrote:
> Hi All
>
> I have found the problem from my last post and need to know how to solve it.
Can't you do what you want to do without using two SQL statements?
CREATE TABLE IF NOT EXISTS.
Janet
- Original Message -
From: "Dave Carrera" <[EMAIL PROTECTED]>
To: "php List" <[EMAIL PROTECTED]>
Sent: Sunday, May 26, 2002 8:01 AM
Subject: [PHP-DB] db sql issue from var
Hi All
I h
Hi All
I have found the problem from my last post and need to know how to solve it.
Example sql var:
$sql = "DROP TABLE IF EXISTS test; CREATE TABLE test ...";
When i run the script i get
Mysql error near ';' create table..
So how do i run this command from my script to i
Hi All
I have a working mysql statement that i would like to load from a file using
my php script
It first drops table if excists
then creates table
then loads sample data
I have tried many different ways but no success :-(
Any help or ideas would be most appreciated
I have a
Hi All
I am trying to load a mysql statement which i have tested and know to work
from a var in my script.
It is a create table statement.
I have a good connection as a table list shows tables.
I tried to echo my var but no joy
Any ideas?
Thanks in Advance
Dave C
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