Please post the code you are trying to use so that we can try to find the
problem. Without data, we can't tell you where things went wrong.
Edward Dudlik
Becoming Digital
www.becomingdigital.com
- Original Message -
From: "Ramesh PAtel " <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent:
Hi All
Hi i install PHP4.3 and apache2 now i create one page for PHP Info
i use
i show all info on web page .
But Problem is here
When i create one page for Connect Database on PostgreSQL.it not work.
mean Postgresql work well i test it. i thing PHP Command problem.
Please help where is Probl
RE: [PHP-DB] Calling Stored Procedures of Oracle in phpYou did not get it. Actually
the procedure name means Any procedure Name say "getName". It was just an example :-)
- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED] ; [EMAIL PROTECTED]
Sent: Friday, June 06,
Thanks, Gürhan, but I think I needed to explain things better. As is generally
a good idea, the categories are referenced in the product table by ID, not name.
Additionally, this is something along the lines of what I already had. I was
trying to use only one query and make PHP do the remaining w
On Fri, 2003-06-06 at 21:49, Becoming Digital wrote:
> I'm wearing the stupid hat today, so please pardon this. I know I must be
> overlooking something.
>
> I have a small catalogue with two tables (categories, products) from which I'm
> trying to display items. I'm trying to print the contents
I'm wearing the stupid hat today, so please pardon this. I know I must be
overlooking something.
I have a small catalogue with two tables (categories, products) from which I'm
trying to display items. I'm trying to print the contents as below without
using two queries, but I'm having a difficult
Entries from what? Do you have a code example of what you're working with now?
Believe it or not, most of us would rather read through it than guess what
you're trying to accomplish.
Edward Dudlik
Becoming Digital
www.becomingdigital.com
- Original Message -
From: "André Sannerholt" <[E
Ok, the thing I accually want to do is to keep all the entries in one
specific selection-option-box after the form has been submitted. I hope that
is enough of explanation, because I cannot expect from you to go through my
whole project...
Regards, André
--
PHP Database Mailing List (http://ww
hello,
i am installing Apache 2.0.40 and Php 4.3.1 and Interbase 7 and for some
reason i have problem when my code try to select from a database if the
query is update or insert delete etc. all works well until i try a select.
if i install interbase 6 or lower version then everything is ok.
also
$last_id = mysql_insert_id();
Check out this page for details.
http://www.php.net/manual/en/function.mysql-insert-id.php
On Fri, 6 Jun 2003 17:16:01 -0400, Chris Payne wrote:
> Hi there everyone,
>
> I'm creating a new entry using the following:
>
> mysql_query ("INSERT INTO agents (agent_name
Hi there,
Thanks for your quick reply, very appreciated :-)
Chris
> hi
>
> you can easily do this by using
>
> mysql_insert_id();
>
> see
> http://www.php.net/manual/en/function.mysql-insert-id.php
>
> .ma
>
> e: [EMAIL PROTECTED]
> w: http://www.abendstille.at
> /***/
> life wo
hi
you can easily do this by using
mysql_insert_id();
see
http://www.php.net/manual/en/function.mysql-insert-id.php
.ma
e: [EMAIL PROTECTED]
w: http://www.abendstille.at
/***/
life would be easier if i knew the source code.
Am Freitag, 06.06.03 um 23:16 Uhr schrieb Chris Payne:
Hi
Hi there everyone,
I'm creating a new entry using the following:
mysql_query ("INSERT INTO agents (agent_name)
VALUES ('$agentname')
but I need to find out the ID value it created, how can I do this easily?
Thanks
Chris
The following link may be of assistance:
http://www.mysql.com/doc/en/Upgrading-from-3.23.html
> -Original Message-
> From: .ma [mailto:[EMAIL PROTECTED]
> Sent: Friday, June 06, 2003 3:40 PM
> To: PHP-DB
> Subject: Re: [PHP-DB] Is it worth upgrading Mysql on linux?
>
>
> hi!
>
> if you
hi!
if you upgrade i'd say upgrade to 4.1 which provides the IN()-method
which allows komplex subselects. But may be this is not a very good
idea cause 4.1 is only alpha afaik
.ma
e: [EMAIL PROTECTED]
w: http://www.abendstille.at
Life would be easier if i knew the source c
Hi there everyone,
I run a server from a great company which gives everything you need from $99 a month
(450 gigs bandwidth, PHP, MySQL, SSL etc ...)
Anyway, I currently run one of the latest builds of PHP but MySQL is only version
3.23.56 (Or something similar) - does anyone see any advantages
I know there is another mailing list for installation questions, but
I am hoping for some help here. I get enough mail from this list alone
without having to join another. Anyway, while attempting to compile version
4.3.2 I am running into the following error during the configure...
che
We all might benefit from an explanation of what you're trying to do here.
Where does the data in your variables come from?
If the variables are not part of the form itself, what _are_ they part of?
What will be done with the data (e.g., used as query parameters, page
display parameters, etc.)?
Ha
I'm not sure if its get/post I need, beacause the variables are not a part
of the form itself!
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Hi,
Is there any body who have experience with the flags in mysql_connect() in
php >= 4.3 . Especially the MYSQL_CLIENT_COMPRESS flag.
Give it sense, to use this feature if both, apache/php and the mysql server
reside on the same machine?
Thanks,
Armand
--
PHP Database Mailing List (http://w
Here is the code (acct # blurred for obvious reason):
##begin paste##
##end paste##
Here is the result:
##being paste##
Warning: SQL error: [Simba Technologies Inc.][SimbaEngine C/S ODBC
Driver][SimbaClient][SimbaClient LNA]Client RPC error. Error = (103) Error
sending message. Trap = (111) Error
> I am a bit confused. I have built a web site from dynamic pages using
PHP
> &
> Mysql. When a user selects an item from a drop down list that takes
then
> to
> a detail page. When they click back on the browser button they get a
> message about the page has expired.
>
> Is this an issue of se
on 6/6/03 5:52 pm, André Sannerholt at [EMAIL PROTECTED] wrote:
> I'm wondering how to transfer variables in a php-document to the same script
> after the form has been submitted!?
if ($_POST['submit']) {
//stuff
} else {
// form stuff
}
HTH
--
Mike Karthauser
Managing Director - Brights
Hi everybody!
I'm wondering how to transfer variables in a php-document to the same script
after the form has been submitted!?
Thanks.
André
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
I am a bit confused. I have built a web site from dynamic pages using PHP &
Mysql. When a user selects an item from a drop down list that takes then to
a detail page. When they click back on the browser button they get a
message about the page has expired.
Is this an issue of session or cookie?
> I am now getting a completely different error that I cannot
figure
> out how it is related. I have passed the $td variable into the
function
> and
> then get it back as a POST variable from a hidden field within the
> function.
> Here is the error I am now seeing;
>
> Unknown column 'sn42
If this is a cut-n-paste of the code, check the line below for spelling:
"begin prcoedurename('[EMAIL PROTECTED]','3');end;";
^^^
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
"Pay It Forward"
mailto:[EMAIL PROTECTED]
http://accessingram.com
> -Original Mes
Hi,
I want to call a oracle stored procedure from php and retrieve the values.
My procedure has 2 parameters which i have to pass and based on that it will
return values. I am using the below code. I am getting errors like wrong
arguements passed. Can anybody tell me the reason?
$conn = ora_logo
Hi!
Thanks! But I got a problem with the code:
The PHP file as it is with the code pasted into it will i'll past at the end
of this post. The problem is I get the error:
Warning: Invalid argument supplied for foreach() in
/home/amotor/www/list_ingresser_artikler.php on line 43
If I put a // in
done
you can find the files at
www.alcatorda.com/jcp/test/files.html
and try it at
www.alctorda.com/jcp/test/enregistrer.php
I am sure it is full of bad codding but it works.
I just have to make it nice now.
Philippe
Le Jeudi 5 Juin 2003 06:15, Peter Beckman a écrit :
> 1. Search the arc
> > It's an issue of using POST instead of GET and has nothing to do
with
> > PHP. Most browsers won't "re-post" POST data for you for security
> > reasons. GET, however, is just a URL with a query string, so it
simply
> > requests it.
>
> Assuming you can't re-write the POST inputs as GETs, is th
> It's an issue of using POST instead of GET and has nothing to do with
> PHP. Most browsers won't "re-post" POST data for you for security
> reasons. GET, however, is just a URL with a query string, so it simply
> requests it.
Assuming you can't re-write the POST inputs as GETs, is there a way a
Thanks for all you wonderful help. With a little tweaking, and a new
debugging program, I have been able to get the results I want. Now I'm
going to begin adding some security features. Again, thanks for you help.
Yours in Service,
Jason Britton
Scar's Legion
http://st.fulco.net
[EMAIL PROTECTE
> -Original Message-
> From: A. Lyse [mailto:[EMAIL PROTECTED]
> Sent: 06 June 2003 11:34
This was sent privately to me, but I'm redirecting the response back to the list in
case it helps anyone else.
> Feeling kinda stupid. hehe. sorry I didnt label the lines.
Probably no more stupid t
> -Original Message-
> From: A. Lyse [mailto:[EMAIL PROTECTED]
> Sent: 05 June 2003 21:21
>
> Thanks! But I got a problem with the code:
>
> The PHP file as it is with the code pasted into it will i'll
> past at the end
> of this post. The problem is I get the error:
>
> Warning: Invali
Thought I was on track, but stumped again...
I am now getting a completely different error that I cannot figure
out how it is related. I have passed the $td variable into the function and
then get it back as a POST variable from a hidden field within the function.
Here is the erro
To add to this message:
We are having problems with people using IE 6.0. They appear to sign-in and
then are returned to the sign-in screen over and over. This doesnt happen
to all that use the site.
Thanks in advance
-Original Message-
From: Marie Osypian [mailto:[EMAIL PROTECTED]
Sen
Hi,
Thanks all for your answers.
What I mean by I am not a coder is that it will take me 3 month to do it while
doing only that, because I code in PHP once a month. And since I help an
association I cannot really spend my time doing this.
What I can do is to take bits of code and put them tog
I just responded to a separate but similar suggestion. The form
elements, including the buttons, are all generated in a separate function.
I am currently passing about 5 variables into this function and I am a
little hesitant to pass any others. I am not sure about complexity,
performance
Not sure exactly how I would implement this. Currently the reload URL
is being provided via the "$PHP_SELF" variable. I like using this, but
suppose I could change this if truly necessary. Also, the $td is not
currently being passed into the function that generates the two buttons and
hence
OK. I guess the next question would be what is the best option for
performance? This portion of the app currently doesn't have any session
functionality built in. I would be setting up the session for this sole
purpose. I haven't worked with cookies yet. I suppose the URL method might
Hey thanks Mike
that surly made a difference.
Earl
'
- Original Message -
From: "Ford, Mike [LSS]" <[EMAIL PROTECTED]>
To: "'Earl'" <[EMAIL PROTECTED]>; "PHP-DB" <[EMAIL PROTECTED]>
Sent: Thursday, June 05, 2003 6:13 AM
Subject: RE: [PHP-DB] while - if - problem
> > -Original Message
"John W. Holmes" <[EMAIL PROTECTED]> wrote on 06/04/2003 05:24:22
PM:
> > Thanks to everyone for the suggestions. Got it fixed. Just added a
> couple
> > lines of code -
> > $sql1 = "select * from endusers where name like '$name'";
> >$result1 = mysql_query($sql1);
> > $count1 = mysq
> I have actually discovered that the $td value is blank. The reason
> appears to be that the page is reloading when a button is pushed, and that
> is when the $td value is being lost. My question now is, how do I keep
the
> $td value after the page is reloaded? I would rather keep the value fro
We are having complaints on our site about users not being able to log-in
and we feel it maybe related to the setting of cookie. Here is the code
used. Can anyone give me insight.
/* some standard var's or other things like srand */
srand((double)microtime() * 100);
$includes_root
I have actually discovered that the $td value is blank. The reason
appears to be that the page is reloading when a button is pushed, and that
is when the $td value is being lost. My question now is, how do I keep the
$td value after the page is reloaded? I would rather keep the value fro
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