Hello Piotr,
> -Original Message-
> From: Piotr Wilkin [mailto:[EMAIL PROTECTED]
> Sent: Tuesday, December 28, 2004 5:46 AM
> To: php-db@lists.php.net
> Subject: [PHP-DB] 'Illegal mix of collations' with PHP 4.3.10 and MySQL
> 4.1.7
>
> I have noticed a very peculiar behavior when I upgr
On Mon 27 Dec 04, 8:48 PM, S Kumar <[EMAIL PROTECTED]> said:
> Hello Pete:
>
> However, in the case of checkboxes, I do not know how
> to make variables out of them depensing on what user
> selects. Say whatever user cheks in the checkbox,
> that variable has to be searched in TABLE-C and
> vari
Hello Pete:
It is a cancer patients for whom i have data on
preoperative and postoperative procedures and drugs
administered for that condition. my table looks like
this:
S. No Pat_age_group type_of cancer size_of_tumor
1 Old Prostate 5 cm
2 Young bre
Hola,
I think what you want would be like this:
Let's say your table has these fields: id, title, authorID, category
and article (which is the text).
so the first query might be - SELECT id, title, category FROM myTable
WHERE authorID = $myID
and you want to know how to present a list of h
I have noticed a very peculiar behavior when I upgraded my PHP
revision from 4.3.9 to 4.3.10 (I use Debian Linux). Suddenly,
the PHP MySQL client stopped accepting the default encoding / collation
when connecting to the server. When issuing any query containing text
field comparisons, I get the fol
On Mon 27 Dec 04, 9:22 PM, p said:
> >
> > Select age_group from patient_data where age_group =
> > young and old ;
> >
> >
> > I am truly stuck here. Can any one please help me out
> > to pass this situation.
> >
> > Thank you in advance.
> >
> > Kumar.
>
> PS- How can a single patient
On Mon 27 Dec 04, 5:22 PM, S Kumar <[EMAIL PROTECTED]> said:
> Dear group,
> I am a novice programmer started doing php to process
> a query form of my patients.
>
> I have a database and one table in it deals with my
> patient information. Depending on their condition I
> divided their age
Dear group,
I am a novice programmer started doing php to process
a query form of my patients.
I have a database and one table in it deals with my
patient information. Depending on their condition I
divided their age groups into 3 categories. In my
database a table patient_data has a column a
amol patil wrote:
entered information still not shown in table of database
is below code is right ?
form name and type values are 'submit' . then
what is wrong with this code,
if(isset($_POST['submit']))
{
$dbh=mysql_connect ("localhost", "root") or die ('I cannot connect to
the da
Sounds like pre-loading the addresses into javascript or something is also
going to be just as cumbersome and that's the only other method I can think of
to have the addresses auto-complete realtime. Yahoo has a little helper app
that works with Yahoo mail to auto-complete names from your emai
one thought might be to check thier data for Str, St etc... and have
it automatically replace with Street. Another would be to reload the
page and give them suggestions on what to use, if they do Rd, have a
drop down with Road, Street, Avenue etc.. so they can choose the
correct one.
--
Joseph
Hi all,
I made a toy database. Two tables are "students" (a collection of student
info) and "message" (private messages I want individual students to read).
The "message" table is indexed by a student's social security number.
student
last, first, ssn, address, city, state, zip, email
messag
aother option here might be to build a set of associative arrays together
that cover all the possibilities of the address endings ie
$addresses = array('Road' =>'Road','Rd', 'Street' =>"Street','Str','St');
etc and run thru a little checking code to convert those possbibities into
one defined f
Hi there!!!
This is one of my first postings to this list. I spend most of the time reading
the postings, but now I need to ask:
How to build a link dinamicly from an output of a query to a web page?
Much clearly. I need that certain user can upload a text content into the web
site. It doesn´t h
We have about 20,000 addresses in our database.
If my users are filling out a form that requires an address already in our
database I have to make sure they enter it in a format already in the db
(such as "West Road" not "West Rd."). I have to also allow for new
addresses.
Obviously having a d
>From what I see, the code is fine, you just haven't finished it.
mysql_query("INSERT INTO totalinfo (Username,Password) VALUES
('$loginusername','$loginpassword'),$dbh")or die (mysql_error());
}
Give that a bash
-Original Message-
From: John Hicks [mailto:[EMAIL PROTECTED]
Sent: Monda
amol patil wrote:
hallo ,
entered information still not shown in table of database
is below code is right ?
form name and type values are 'submit' . then
what is wrong with this code,
if(isset($_POST['submit']))
{
$dbh=mysql_connect ("localhost", "root") or die ('I cannot connect to
the dat
hallo ,
entered information still not shown in table of database
is below code is right ?
form name and type values are 'submit' . then
what is wrong with this code,
-
Do you Yahoo!?
Take Yahoo! Mail with you! Get it on your mobile ph
hallo,
clicking on submit entered info. is not entering in database.
how to set submit , so that query wll execute correctly.
?php
if($submit)
{
$dbh=mysql_connect ("localhost", "root") or die ('I cannot connect
to
the database because: ' . mysql_error());
mysql_select_db ("
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