Hi Peter,
Just a shot in the dark, but make sure that everything is correct
case-sensitive wise. I know this has caused me grief in the past.
J. Wharton
"Peter Roescher" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]...
> I have a mysql query like this
>
&g
Does anyone know of any built-in functions (either in PHP or MySQL) that can
search for duplicates in a table according to 2 fields (id and year)?
Thanks in advance,
J. Wharton
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I encountered something similar. Here is a snippet of code:
$tdate=date("Y\\-m\\-d");
$time=date("G\\:i\\:s");
$query="insert into trackinginfo (IP_Address, username, date, Time,
Processed, CommentFlag)
values ('$REMOTE_ADDR', '$username', '$tdate', '$time', 'N',
'$commentExists')";
mysql_quer
...
> Well, that looks like a problem within the findLoginType()
> call. Since it's not been included, it's hard to help you. :)
>
> 'Luck
>
> -Szii
>
>
> - Original Message -
> From: "J. Wharton" <[EMAIL PROTECTED]>
> To: <
I am having a problem where from certain browsers, a user gets the superuser
access, but from mine, she gets normal access. Help!
Here is a snippet of my code:
//findLoginType returns a single character code stored in the user table for
each user.
//variable $username=$REMOTE_USER as previously