to fiddle with the paths, or am I going about this in completely
the wrong way?
Regards
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224
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A while ago, there was an exchange about alternative domain registration
organizations, ie other than Network Solutions. I intended to save the
messages but seemingly deleted them. Could someone remind me what the
alternatives are. Thanks (and sorry!)
Regards
Mick Lloyd
[EMAIL PROTECTED]
Tel
then protect the directories/scripts from anyone wanting to have a look
(not that they're worth much!).
Thanks
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224
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Gary
Thanks for the advice. I had checked the string length to make sure there
were no "hidden" spaces (which there aren't in the specific field I am
selecting) and have now tried trim() but to no avail. Still fiddling with
it!
Regards
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44
m primarycodes where Code = 'Biology';
\\returns Empty set
I'm no expert (obviously) but something seems odd here.
Regards
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224
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ve to be corrected on this by a PHP expert!
Regards
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224
- Original Message -
From: Mark Collin <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, March 20, 2001 9:44 PM
Subject: [PHP-DB] Transmitting Arrays
> I have
'$row[Primaryexpertise]'";
print $sql."\n";
\\Prints: select Primaryid from primarycodes where Code = 'Biology' \\which
seems OK
$resultp = mysql_query($sql) or die ("Failed"); \\This seems to work
$pcodeid = mysql_fetch_array($resultp) or die("No pcodeid&qu
where Code =
'".$row['Primaryexpertise']."'") or die (mysql_error());
$resultp = mysql_query("select Primaryid from primarycodes where Code like
'%$row[Primaryexpertise]%'") or die (mysql_error());
$pcodeid = mysql_fetch_array($resultp) or die(&qu
CC/Steve
Thanks for the advice. I managed to get the "... Code =
'".$row['Primaryexpertise']."'" option working but not the others. Thanks
again.
Regards
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224
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KE as follows:
$result = mysql_query("select Primaryid from primarycodes where Code like
'%$row[Primaryexpertise]%'")
but I need greater accuracy because some codes contain similar data. String
manipulation has me baffled most of the time!
Thanks.
Mick Lloyd
[EMA
ws";
$result=mysql_query("update $TA set P1description = load_file($cvfile)") or
die (mysql_error());
Output shows File exists 1 (which I assume menas True) and the table is
being read because $rows equals 2.
P1
Then I get the "You have an error in your SQL syntax near '(x
QL result
resource ..." error. I also get this when I click Back from either
sessionrows.phtml or sessionresultid.phtml. Again not sure why?
Any help gratefully received.
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224
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, Zend, etc but with little success.
Thanks
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224
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