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> -----Original Message-
> From: Mark Gordon [mailto:[EMAIL PROTECT
s code, but perhaps there's
> something else there.
>
>
> -Original Message-
> From: Ben Bleything [mailto:[EMAIL PROTECTED]]
> Sent: Sunday, July 08, 2001 8:13 PM
> To: 'Matthew Loff'; 'Mark Gordon'; [EMAIL PROTECTED]
> Subjec
, July 08, 2001 8:13 PM
To: 'Matthew Loff'; 'Mark Gordon'; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Dynamic SQL + result resource error
Guess I'm just a big dumbass then, aren't I =P
Oops.
I suppose that would cause it to fail then, wouldn't it?
=> Ben
--
n'; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Dynamic SQL + result resource error
The code you're referencing is my modification of his original post. :)
-Original Message-
From: Ben Bleything [mailto:[EMAIL PROTECTED]]
Sent: Sunday, July 08, 2001 8:04 PM
To: 'Matthew Lof
The code you're referencing is my modification of his original post. :)
-Original Message-
From: Ben Bleything [mailto:[EMAIL PROTECTED]]
Sent: Sunday, July 08, 2001 8:04 PM
To: 'Matthew Loff'; 'Mark Gordon'; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Dynamic SQ
Sure he is. Right here:
$queryResult = mysql_query($sql);
what exact error is occurring?
-Original Message-
From: Matthew Loff [mailto:[EMAIL PROTECTED]]
Sent: Sunday, July 08, 2001 5:00 PM
To: 'Mark Gordon'; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Dynamic SQL + result reso
($wordsarray);
$sql=$sql."$word)";
$i++;
}
print "$sql";
$queryResult = mysql_query($sql);
while ($myrow=mysql_fetch_row($queryResult))
{
print "$myrow[0],";
}
-Original Message-
From: Mark Gordon [mailto:[EMAIL PROTECTED]]
Sent: Sunday, July 08, 2001 7
Why is this code generating an error when it outputs a
valid SQL statement? (there are no parse errors)
//$find is text box input
$wordsarray = explode(" ",$find);
$sql = "SELECT bandname FROM bands WHERE (bandname
LIKE ";
$i = 0;
while ($i < count($wordsarray))
{
$word = current($wordsar
