[PHP-DB] Putting a string into a variable.

2003-03-28 Thread Info_Best-IT
I am having problems putting an html string into a variable to create an array of strings. something like this: $stringarray[] = array(); $i = 0; while ( $i < 6 ){ $stringarray[$i] = "".$this->differentarray[0] [0].""; } When I echo $stringarray[1] it comes up empty... Is there a special

RE: [PHP-DB] Putting a string into a variable.

2003-03-28 Thread Jennifer Goodie
The part where $i is never equal to 1 might be the problem. You might want to try incrementing your sentinel when using loops. -Original Message- From: Info_Best-IT [mailto:[EMAIL PROTECTED] Sent: Friday, March 28, 2003 11:13 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Putting a string

RE: [PHP-DB] Putting a string into a variable.

2003-03-28 Thread Hutchins, Richard
PROTECTED] > Sent: Friday, March 28, 2003 2:13 PM > To: [EMAIL PROTECTED] > Subject: [PHP-DB] Putting a string into a variable. > > > I am having problems putting an html string into a variable > to create an array of > strings. > > something like this: > &

RE: [PHP-DB] Putting a string into a variable.

2003-03-28 Thread Hutchins, Richard
t I was thinking of. > -Original Message- > From: Hutchins, Richard [mailto:[EMAIL PROTECTED] > Sent: Friday, March 28, 2003 2:22 PM > To: 'Info_Best-IT'; [EMAIL PROTECTED] > Subject: RE: [PHP-DB] Putting a string into a variable. > > > You might be getti

Re: [PHP-DB] Putting a string into a variable.

2003-03-28 Thread Ronan Chilvers
Hi Tim Comments inline... > > $stringarray[] = array(); > $i = 0; > > while ( $i < 6 ){ > $stringarray[$i] = "".$this->differentarray[0] > [0].""; > } > > > When I echo $stringarray[1] it comes up empty... Is there a special trick to get a You're not incrementing $i. You need $i++ in your