> >
> >
> > Gary Every
> > Sr. UNIX Administrator
> > Ingram Entertainment
> > (615) 287-4876
> > "Pay It Forward"
> > mailto:[EMAIL PROTECTED]
> > http://accessingram.com
> >
> >
> > > -Original Message-
> &
ram Entertainment
> (615) 287-4876
> "Pay It Forward"
> mailto:[EMAIL PROTECTED]
> http://accessingram.com
>
>
> > -Original Message-
> > From: Greg Hetrick [mailto:[EMAIL PROTECTED]
> > Sent: Wednesday, July 09, 2003 12:31 PM
> > To: [E
ne. 99% of the time, this error
> means your query
> > failed. if it works on another serverare the fields
> the same, the
> > dbname, the tablename?
> >
> > hth
> > jeff
> >
> >
> >
> > "Greg He
Query is correct appears to be a problem connecting to the db -- I can
comment out the mysql_select line and I get no change.
"Terry Riley" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> As far as I know, that error means that the query that was supposed to
> produce $result did not
h
> jeff
>
>
>
> "Greg Hetrick"
> <[EMAIL PROTECTED]To:
[EMAIL PROTECTED]
> net> cc:
>Subject: [PHP-DB]
mysql_fetch_array issues.
>
As far as I know, that error means that the query that was supposed to
produce $result did not run because of errors in the SQL (or the
database).
Suggest you check your query in myPHPAdmin or MySQLfront or whatever to be
sure that it has no errors.
Terry
--Original Message-
[EMAIL PROTECTED]
net> cc:
Subject: [PHP-DB]
I am getting the following error when attempting to pull data out of a mysql
DB
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in /home/pffl/public_html/pffl/webpage/html/dataentry.php on line
125
I can take this same code to a different web server and it is
