Norland [EMAIL PROTECTED]
Reply-To: php-db@lists.php.net
To: php-db@lists.php.net
Subject: Re: [PHP-DB] Help. I am losing the plot...
Date: Tue, 05 Jul 2005 09:41:55 -0500
Ross Honniball wrote:
script1.php:
echo 'script 1 before';
require_once('script2.php');
echo 'script 1 after';
script2
Um. Anyone know of a good code editor?
I normally use vim, but on my windows box sometimes use
http://www.pnotepad.org/ when looking at log files and what not... (yes, I
know there's a windows version of vim)
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit:
zend is excellent, i use editpad at work, have engisite for php (also good)
phpedit, context
all depends on how much you want to spend and what features you want
bastien
From: Ross Honniball [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: Re: [PHP-DB] Help. I am losing the plot.. .
Date
In the second loop you do an array_shift($entry) which should be
array_shift($all).
Perhaps a foreach loop would be easier:
?php
foreach ($entry as $value) {
$update = UPDATE accounts SET ctime=NOW() WHERE id_sys=' . $value.
';
$results = mysql_query($update, $Prod) or
I apologize but I figured out my mistake.
Thanks
-Rich
-Original Message-
From: ReClMaples [mailto:[EMAIL PROTECTED]
Sent: Monday, April 25, 2005 10:05 PM
To: PHP
Subject: [PHP-DB] Help with PHP
I'm not sure if this is the correct distro to be sending this question to,
if it's not,
uncomment the mysqli library functions in the ini file and use those
functions instead...
bastien
From: zheng [EMAIL PROTECTED]
Reply-To: zheng [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] help wanted for install php with mysql support on windows
Date: Fri, 22 Apr 2005 18:10:10
Hello Ron,
I guess it would really help all of us helping you in giving any real
help if you post some code here. :)
Regards,
Samar M.
= Warning: Dates in Calendar are closer than they appear.
On Mon, 24 Jan 2005 23:18:33 +0800, ron [EMAIL PROTECTED] wrote:
Hi All,
What seems to be the
Hi
from php 5 onwards mysql is not enabled by default
http://www.php.net/manual/en/ref.mysql.php
Note: Windows users will need to enable php_mysql.dll inside of php.ini and
either copy libmysql.dll into the Windows system directory, or make it
available to the PATH.
from memory...
(To
Janet and Peter,
Thank you for your help. It worked and I was able to populate the database
through the next script that was in the book. I am on my way to learning PHP
and MySQL. I hope it also works on my web hosting servers in a few days time.
Thank you again.
My New Year is starting in
Novice Learner wrote:
I apologize if this is a very basic question.
I just started learing PHP and MySQL, I am reading PHP and MySQL by Larry Ullman, I also have access to PHP 5 by Julie Meloni. I reached Chapter 6 of Ullman's book and got stuck.
I have the following code:
?php
//This file
On Thu, 23 Dec 2004 10:57:55 -0500, Bastien Koert [EMAIL PROTECTED] wrote:
you have a mysql account with that particular user identification?
yes this connections works well when i query table user, in specified db.
bastien
From: Nayyar Ahmed [EMAIL PROTECTED]
Reply-To: Nayyar Ahmed
you have a mysql account with that particular user identification?
bastien
From: Nayyar Ahmed [EMAIL PROTECTED]
Reply-To: Nayyar Ahmed [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] help newbies :)
Date: Thu, 23 Dec 2004 20:54:23 +0500
Hello All,
I am developing attendence mangement
Nayyar Ahmed wrote:
Hello All,
I am developing attendence mangement system, its my first application
in PHP, I want to compaire the input text box value with table records
the follwing is the code
_index.htm___
..
form name = 'loginfrm' method = post action =
Have you set up a ODBC connection ?
You must set up a ODBC connection in the ODBC Sources that is usually in you
Control Panel or Administrator Tools.
You must put it as a System DNS and set up the connection, so your local system
know where to find the database.
Kind Regards
Arné
have you created a dsn for this connection?
Bastien
From: Petrus Ali Saputra [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Help me please
Date: Mon, 08 Nov 2004 10:55:45 +0700
Can anyone here help me how to connect to an ODBC data?
Here is my code: $odbc = odbc_connect(Ta Fara,,);
And
Arné klopper wrote:
Have you set up a ODBC connection ?
You must set up a ODBC connection in the ODBC Sources that is usually in you Control Panel or Administrator Tools.
You must put it as a System DNS and set up the connection, so your local system know where to find the database.
I
Bastien Koert wrote:
have you created a dsn for this connection?
Bastien
From: Petrus Ali Saputra [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Help me please
Date: Mon, 08 Nov 2004 10:55:45 +0700
Can anyone here help me how to connect to an ODBC data?
Here is my code: $odbc =
Stuart Felenstein wrote:
If you see the code I have the begin , then the $query
follows. With both statements present, only the
second one does the insert. If I // or remove the
second, the first one takes.
Am I missing something here ?
Yep... you're missing a mysql_query() call for each
That made a world of difference! :) Thank you.
But - I want to confirm, am I still using transactions
even though I'm issuing individual query calls for
each insert.
And, if I can ask another question to the list :
In this line (from the second insert)
VALUES (null, LAST_INSERT_ID(), ..);
John,
Big thank you! for your help. I had been trying out
the mysql_insert_id and was not having luck. It's
working great (with just a few more bumps to get
over).
--- John Holmes [EMAIL PROTECTED] wrote:
Stuart Felenstein wrote:
But - I want to confirm, am I still using
transactions
Here is my situation , not sure how I should handle
it.
I have this multi page form, at the end I use mysql
transaction to get the data into all the tables.
All the tables are innodb with the exception of one.
The last page has one field which takes a copy/paste
of a document, so it's a text
Hi Stu
1. why not check it on every page, then if it fails the user won't need to
make it to the end and then have to go back to the beginning to fix
something minor.
2. You could use hidden fields to pass the data back and for or just use a
session, otherwise the variables expire on that page
See interspersed:
--- Bastien Koert [EMAIL PROTECTED] wrote:
Hi Stu
1. why not check it on every page, then if it fails
the user won't need to
make it to the end and then have to go back to the
beginning to fix
something minor.
2. You could use hidden fields to pass the data back
Warning: session_start(): Cannot send session cookie -
headers already sent by (output started at
/home/lurkkcom/public_html/Multi2Return.php:2) in
/home/lurkkcom/public_html/Multi2Return.php on line 3
read a little more about sessions.
session_start is trying to set a cookie but output has
://www.planetthoughtful.org
Building a thoughtful planet,
One quirky comment at a time.
-Original Message-
From: Stuart Felenstein [mailto:[EMAIL PROTECTED]
Sent: Saturday, 9 October 2004 1:57 AM
To: Bastien Koert; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Help: First Time Form with Sessions
See
-
From: Stuart Felenstein [mailto:[EMAIL PROTECTED]
Sent: Saturday, 9 October 2004 1:57 AM
To: Bastien Koert; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Help: First Time Form with
Sessions
See interspersed:
--- Bastien Koert [EMAIL PROTECTED] wrote:
Hi Stu
1. why not check it on every
see interspered again ;)
From: Stuart Felenstein [EMAIL PROTECTED]
To: Bastien Koert [EMAIL PROTECTED], [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Help: First Time Form with Sessions
Date: Fri, 8 Oct 2004 08:56:48 -0700 (PDT)
See interspersed:
--- Bastien Koert [EMAIL PROTECTED] wrote:
Hi Stu
1
Well I guess too much success at once is a bad thing.
For some unapparent reason, the variables here are not
carrying over. Anyone see anything wrong here ?
Page1 (Somewhat snipped)
?php
session_start();
if ( empty( $_SESSION['l_education'] ) ) {
$_SESSION['l_education']=array();
}
if (
Figured it out. Page 2 had to have the field name in
the $SESSION parameters, not the holder from the Page1
array register.
Stuart
--- Stuart Felenstein [EMAIL PROTECTED] wrote:
Well I guess too much success at once is a bad
thing.
For some unapparent reason, the variables here are
not
K ..my problem seems to be combining echo on the menu
values with the print array. If I echo $array[0];
that seems to work fine !?
Stuart
--- Stuart Felenstein [EMAIL PROTECTED] wrote:
Back again , sorry :)
I had my form set up with 7 multi selects , on the
return page, all 7 arrays were
Check to see if your register_globals is set to off in php.ini. If so
(likely, since it defaults to that value) you'll need to access your
POST and GET variables like this:
GET vars:
$var = $_GET['var'];
POST vars:
$var = $_POST['var'];
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
Micah,
Your right! I regretted this post after I hit send.
The code generator is actually okay. I'm learning
more about PHP, and what the code actually means, in
the event it needs to be modded / edited.
Sorry again for the post and thanks for the reply!
Stuart
--- Micah Stevens [EMAIL
I'm thinking you should either get a better code generator, or learn more
about php.. :)
-Micah
On Monday 13 September 2004 02:49 pm, Stuart Felenstein wrote:
Thanks to help here I was able to overcome some ivalid
query errors.
Now I'm back, (probably the same mistake)
It's coming off
Hi
php runs as the same user as apache. Depending on any other security/system
issues you could set apache to run as postgres.
Otherwise why not connect to postgres using the php functions and write the
text file using php?
You might also be able to su to postgres.
HTH
Peter
-Original
Hi Peter,
Thank you for your answer.
php runs as the same user as apache. Depending on any other security/system
issues you could set apache to run as postgres.
Unfortunately, i can't. There's too much variables involved :(
Otherwise why not connect to postgres using the php functions and write
This is my favourite.
How can i execute this query:
$myresult2 = pg_query($pgsql_conn, SELECT url_negado from urls_negados
/tmp/urls_negados.txt);
from inside a PHP file as user postgres ?
cant you do this...?
select url_negado into outfile '/tmp/urls_negados.txt' from urls_negados
--
PHP
This isn't really a database question, so I'm not sure why it went to a
database-related list.
Have you checked your Apache configuration to make sure it's set to
handle the PHP extensions? Check the PHP manual on how to set this (I
believe relevant instructions are under Installation).
--
Gotta recompile php with the --with-mysql option (or something like that).
Try running configure --help
You can see what options you compiled with by grepping for CONFIGURE in your
Makefile. Here's what I got:
[EMAIL PROTECTED] php-5.0.0b4 # grep CONFIGURE Makefile
CONFIGURE_COMMAND =
://www.macromedia.com/devnet/mx/dreamweaver/articles/php_iis.html)
-Jeff
- Original Message -
From: Jeffrey Moss [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, August 17, 2004 12:08 PM
Subject: Re: [PHP-DB] help with mySQL- Fatal error: Call to undefined
function mysql_connect()...
Gotta
I use PHP to check the search form's input fields then add them to the SQL
statement if they contain data. And if you want the search to return all
records from the table (let's hope there's not many then) if no search terms
are provided then make the WHERE part of your SQL query an option based
Hello Ross,
why don't use: explain select .
and you'll see what mysql is thinking... ;)
--
Best regards,
Pablo
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PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
On Saturday 17 July 2004 09:31, Ross Honniball wrote:
Attention all Sql gurus,
Is there a way to FORCE mysql resolve specific conditions within a query
before wasting it's time trying to resolve other conditions?
www.mysql.com
--
Jason Wong - Gremlins Associates - www.gremlins.biz
Open
[snip]
The IP's (for example 192.168.1.1) are all in a single field.
[/snip]
If it is a possiblity, I would store each IP in its own row, with a
column in that row being some kind of flag, like: is_issued as a logical
column.
Can you change you db layout or is it set in stone?
--
PHP Database
Hello redhat,
Hey... look at this:
CREATE TABLE `testip` (
`id` int(10) unsigned NOT NULL auto_increment,
`theip` varchar(100) NOT NULL default '',
PRIMARY KEY (`id`),
UNIQUE KEY `theip` (`theip`)
) TYPE=MyISAM AUTO_INCREMENT=7 ;
SELECT theip, SUBSTRING_INDEX( theip, ., 1
Hi the Third,
have you considered dumping the table into a text file?
SELECT *
FROM mytable
INTO OUTFILE c:/...
this (AFAI) does not cause memory issues
Ignatius
_
- Original Message -
From: Leo G. Divinagracia III [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent:
would be nice... but since this is a hosted site and no shell access or
anything, i thought i would write the php script to dump the file to my
web path...
Ignatius Reilly wrote:
Hi the Third,
have you considered dumping the table into a text file?
SELECT *
FROM mytable
INTO OUTFILE c:/...
I agree to use mysqldump to export the data to a text file. If you want to
save time, you could write a php script to ftp the text file from the dead
host to the new host. Then load the data back into the new database.
I guess if you have broadband connection, then you might not be saving
From: Adrian Donoiu [EMAIL PROTECTED]
I need information about how can I get the table name from this query :
select * from test_table as t
when I use :
$field=mysql_fetch_field($result, $i);
$field-table return the name of the table as t but I need the real
name of the table
Go to http://hotscripts.com
-Original Message-
From: redhat [mailto:[EMAIL PROTECTED]
Sent: Tuesday, April 06, 2004 1:21 PM
To: phplist; fedoralist
Subject: [PHP-DB] help desk software
Anybody out there familiar with some helpdesk software? I found some
called teacup that runs as a
Hi,
You can use LEFT OUTER JOIN
Table1 : software list
Table2 : installed ones
$res=mysql_query(select table1.software_name, table2.software_name from
table1 left outer join table2 on
table1.software_name=table2.software_name);
Check if there is not a matching record on table 2
Sorry for accidentally posting twice:
I wanted to point out a typo.
At the bottom I meant advancing the array not table in regards to next()
On Wed, 25 Feb 2004 11:12:10 -0600
PHELPS, SCOTT [EMAIL PROTECTED] wrote:
Thanks in advance for reading this:
I am trying to take a query based on
On Thursday 26 February 2004 01:04, PHELPS, SCOTT wrote:
The problem is that it only prints one name. Also next() doesn't seem to
be advancing the table so I am getting duplicates of the one name it does
print to the table
For starters, you're using next() incorrectly. It returns a value.
UPDATE table
SET column = CONCAT(
MID( column, 2, LENGTH( column ) - 1 ),
MID( column, 1, 1 )
)
WHERE column LIKE 'M%'
HTH
Ignatius
_
- Original Message -
From: Shaun [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, February 10, 2004 14:15
Subject:
Presuming you have the date in your PHP code you could simply add 172800
(seconds in 2 days) to the current value and insert it in the same way
as you are doing with your current dates.
If you post how you're inserting your dates, what format you're using
and stuff like that then you'll
[Forwarded for Paxson Jr. because this was only sent to me.]
you can also easily use the mysql date functions
http://www.mysql.com/doc/en/Date_and_time_functions.html
On 05. Feb 2004, at 11:23 Uhr, Stuart Gilbert wrote:
Presuming you have the date in your PHP code you could simply add
172800
I have (among others) two DATE columns in a table; Booking_Date and
Booking_Completion_Date. How can I run a query that updates
Booking_Completion_Date to be 2 days after Booking_Date where
Booking_Completion_Date is NULL?
UPDATE table SET Booking_Completion_Date = Booking_Date + INTERVAL
Thanks for your reply,
but that only tells me how many complete Bookings there are. I need to know
how many Areas are complete i.e. for each Area where Bookings take place,
all of those Bookings have been completed.
Any ideas?
Oòvn?Oòs is [EMAIL PROTECTED] wrote in message
news:[EMAIL
SELECT COUNT(WMS_Area.Area_ID) AS complete_areas FROM WMS_Area, WMS_Bookings
WHERE WMS_Area.Area_ID = WMS_Bookings.Area_ID
AND MIN(WMS_Bookings.Booking_Status) = 2
GROUP BY WMS_Area.Area_ID
Or something like that.. there's probably a better way to do it..
On Fri January 23 2004 1:05 pm,
your post is abit vague, give more details or code then we can try help. Its
kinda like you saying, help my car wont go.
-Original Message-
From: Akmal [mailto:[EMAIL PROTECTED]
Sent: Saturday, December 06, 2003 5:43 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] HELP!
I'm trying to create
Hadi wrote:
Hi , please help this newbie , how to make my database view from
[1] [2] [3] [4] [5] [6] [7] [8]
to
1 2 34
Thanks very much
Hadi
***removed code***
You could convert the array into a string but why would you like to do
that?
Not a good way but a possible way
Return Receipt
Your Re: [PHP-DB] help newbie
document
Why don't you post the code you are trying to work with and we could
help you from that point on.
Akmal wrote:
I'm trying to create a guestbook and... I'm having trouble getting a certain
amount of entries per page. Please help, a snippet of a code would be nice.
Thanks!
-Akmal-
---
Outgoing
From: Douglas Freake [EMAIL PROTECTED]
I need to do a loop where the mysql query starts
at the bottom and goes up, as if the data was in
reverse order. This is for building a category/
sub_category menu.
Data structure: (cat_id, cat_sub, cat_name)
sample routine:
do {
$sql = SELECT *
you can do it at sql level by using ORDER BY ... DESC like:
SELECT * FROM categories
WHERE cat_id = '$cat'
ORDER BY cat_id DESC
and then proceed the returned recordset in 'normal' way (order)
--
Douglas Freake wrote:
Hi there,
I need to do a loop where the mysql query starts
at the bottom and
But do you have php compiled --with-curl?
check phpinfo();
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: Joseph Allard [mailto:[EMAIL PROTECTED]
Sent: Tuesday,
Could you be a little more explicit? I don't understand check phpinfo()?
Gary Every [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
But do you have php compiled --with-curl?
check phpinfo();
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
PROTECTED]
Reply-To: [EMAIL PROTECTED]
To: Bunmi Akinmboni [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Content-Type: text/plain
Message-Id: [EMAIL PROTECTED]
Mime-Version: 1.0
Date: 16 Oct 2003 15:12:38 +0200
Content-Transfer-Encoding: 7bit
Subject: Re: [PHP-DB] Help with file upload
On Thu, 2003-10-16
I used this code now:
if (is_uploaded_file($_FILES['ufile1']['tmp_name'])) {
move_uploaded_file($_FILES['ufile1']['tmp_name'],'./' .
$_FILES['ufile1']['name']);
This is the reply I got:
Warning: move_uploaded_file(./ayservenet.jpg): failed to open stream:
Permission denied in
For the message:
Warning: move_uploaded_file(./ayservenet.jpg): failed to open stream:
Permission denied in /home/ayserve/public_html/fu/fuprocess.php on line 6
you have to change the permissions of the file folder where you are copying
the file.
If you created it via FTP then you can't use
On Thu, 2003-10-16 at 07:14, John W. Holmes wrote:
Bunmi Akinmboni wrote:
Warning: move_uploaded_file(./ayservenet.jpg): failed to open stream:
Permission denied in /home/ayserve/public_html/fu/fuprocess.php on line 6
PHP runs as the web server and it does not have permission to write
I just changed the permission on fu folder to 777 but it gives me the
same problem. I'm writing this script so that I can use it to upload to
jpeg files. The code is hereby attached.
Gabriel Peugnet wrote:
For the message:
Warning: move_uploaded_file(./ayservenet.jpg): failed to open stream:
I just changed the permission on fu folder to 777 but it gives me the
same problem. I'm writing this script so that I can use it to upload to
jpeg files. The code is hereby attached.
Bunmi
Gabriel Peugnet wrote:
For the message:
Warning: move_uploaded_file(./ayservenet.jpg): failed to open
+0100
From: Bunmi Akinmboni [EMAIL PROTECTED]
MIME-Version: 1.0
Content-Type: text/plain; charset=us-ascii; format=flowed
Content-Transfer-Encoding: 7bit
Subject: Re: [PHP-DB] Help with file upload
I used this code now:
if (is_uploaded_file($_FILES['ufile1']['tmp_name'])) {
move_uploaded_file
: text/plain; charset=us-ascii; format=flowed
Content-Transfer-Encoding: 7bit
Subject: Re: [PHP-DB] Help with file upload
I used this code now:
if (is_uploaded_file($_FILES['ufile1']['tmp_name'])) {
move_uploaded_file($_FILES['ufile1']['tmp_name'],'./' .
$_FILES['ufile1']['name
; format=flowed
Content-Transfer-Encoding: 7bit
Subject: Re: [PHP-DB] Help with file upload
I used this code now:
if (is_uploaded_file($_FILES['ufile1']['tmp_name'])) {
move_uploaded_file($_FILES['ufile1']['tmp_name'],'./' .
$_FILES['ufile1']['name']);
This is the reply I got:
Warning
permission is ok but it's got to be inside the home directory of web server,
which is /var/www by default for apache
Nitin
- Original Message -
From: Bunmi Akinmboni [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, October 16, 2003 1:28 PM
Subject: Re: [PHP-DB] Help with file
]
To: [EMAIL PROTECTED]
Sent: Thursday, October 16, 2003 1:28 PM
Subject: Re: [PHP-DB] Help with file upload
Thanks Neil. My ultimate aim to update my database with the details of
the upload after it uploads successfully, but I need to solve this
problem first.
The folder already has permission 777
, October 16, 2003 1:56 PM
Subject: Re: [PHP-DB] Help with file upload
HI Nitin,
Is that not dangerous as it will affect the entire server structure?
Bunmi
Nitin wrote:
permission is ok but it's got to be inside the home directory of web
server,
which is /var/www by default for apache
On Thu, 2003-10-16 at 09:58, Bunmi Akinmboni wrote:
Thanks Neil. My ultimate aim to update my database with the details of
the upload after it uploads successfully, but I need to solve this
problem first.
The folder already has permission 777.
Dateiname:
: 7bit
Subject: Re: [PHP-DB] Help with file upload
On Thu, 2003-10-16 at 09:58, Bunmi Akinmboni wrote:
Thanks Neil. My ultimate aim to update my database with the details of
the upload after it uploads successfully, but I need to solve this
problem first.
The folder already has permission 777.
Re
Bunmi Akinmboni wrote:
Pls Help.
I have done a lot of reading prior to this yet I just can't seem make it
work. I wrote an upload program as seen below but the response I got was:
Possible file upload attack. Filename: ayservenet.jpg Array ( [ufile1]
= Array ( [name] = ayservenet.jpg [type] =
His is the new code:
?php
if (is_uploaded_file($_FILES['ufile1']['tmp_name'])) {
copy($_FILES['ufile1']['tmp_name'], .);
echo $ufile1_name ;
echo DONE;
echo ;
print_r($_FILES);
} else {
echo Possible file upload attack. Filename: .
$_FILES['ufile1']['name'];
echo ;
Bunmi Akinmboni wrote:
His is the new code:
?php
if (is_uploaded_file($_FILES['ufile1']['tmp_name'])) {
copy($_FILES['ufile1']['tmp_name'], .);
You should be using move_uploaded_file() instead of copy(), first of all.
Next, the two arguments passed to either copy() or move_uploaded_file()
This in in the php manual
(http://www.php.net/manual/en/features.file-upload.php) but anyway...
The value contained in $_FILES['ufile1']['name'] is not the name of the
temporary file on the server. Try $_FILES['ufile1']['tmp_name'] instead
Hence the lines
if
This is reply I got:
Warning: move_uploaded_file(./ayservenet.jpg): failed to open stream:
Permission denied in /home/ayserve/public_html/fu/fuprocess.php on line 6
Warning: move_uploaded_file(): Unable to move '/tmp/phpfJyDSw' to
'./ayservenet.jpg' in
I used this code now:
if (is_uploaded_file($_FILES['ufile1']['tmp_name'])) {
move_uploaded_file($_FILES['ufile1']['tmp_name'],'./' .
$_FILES['ufile1']['name']);
This is the reply I got:
Warning: move_uploaded_file(./ayservenet.jpg): failed to open stream:
Permission denied in
Bunmi Akinmboni wrote:
Warning: move_uploaded_file(./ayservenet.jpg): failed to open stream:
Permission denied in /home/ayserve/public_html/fu/fuprocess.php on line 6
PHP runs as the web server and it does not have permission to write to
the current directory. If you're using IIS, PHP runs as
So what could be the problem? I reaaly don't know.
Bunmi
John W. Holmes wrote:
Bunmi Akinmboni wrote:
Warning: move_uploaded_file(./ayservenet.jpg): failed to open stream:
Permission denied in /home/ayserve/public_html/fu/fuprocess.php on line 6
PHP runs as the web server and it does not have
and put it inside a transaction cos in case something goes wrong part of
the way through
pete
Jeff Shapiro wrote:
This should do it:
UPDATE Bookings
SET
Booking_Start_Date = CONCAT(DATE_FORMAT(Booking_Start_Date,
'%Y-%m-%d'), '09:00:00'),
Booking_End_Date =
This should do it:
UPDATE Bookings
SET
Booking_Start_Date = CONCAT(DATE_FORMAT(Booking_Start_Date,
'%Y-%m-%d'), '09:00:00'),
Booking_End_Date = CONCAT(DATE_FORMAT(Booking_End_Date, '%Y-%m-%d'),
'17:30:00');
If you are using version 4.1.1 or newer the DATE_FORMAT function could
be replaced
It all depends on what database server (and version) you are using. I'm
not really sure what you are asking, and could use a little more detail
about the tables and what are needing to do.
On Sat, 4 Oct 2003 13:45:56 +0100, Shaun spoke thusly about [PHP-DB]
Help With Another UPDATE Query
I am using mySQL 3.23
Each project has a work type associated with it, currently the Work Type
column of the Project table holds the work type name, however i have now
added a Work_Type_ID column to the Work_Type table and i would like Projects
to hold the Work_Type_ID as opposed to the Work Type
Jason Wong wrote:
On Wednesday 01 October 2003 01:39, Balazs Nemeth wrote:
cd /apache/apache-xxx
./configure --prefix=/www
cd /php/php-xxx
./configure --with-mysql --with-apache=/apache/apache-xxx
--enable-track-vars
make
make install
cd /apache/apache-xxx
./configure
On Wednesday 01 October 2003 01:39, Balazs Nemeth wrote:
cd /apache/apache-xxx
./configure --prefix=/www
cd /php/php-xxx
./configure --with-mysql --with-apache=/apache/apache-xxx
--enable-track-vars
make
make install
cd /apache/apache-xxx
./configure
-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Thursday, August 14, 2003 8:10 AM
To: Mike Klein
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Help needed with variable scoping? or mysql
problem
best way to tell is to place .'or die(mysql_error())' after any call to
mysql_query
Sounds like you're on the right track. in the select list, add --
onChange=document.form.submit() -- this will submit the form when the
user selected the an option from the list, then you could catch the
submitted variable and pass it to the second drop down list and third and
so on. Realizing
Well, as one of the last posts said, if you are displaying in a web
browser, via HTML, you need to insert br tags where you want the text to
go to the next line. HTML doesn't respond to /r/n pairs. So if that is
how the user types them in (with a enter key at the end of lines) you need
to
You guys thanks for the encouragement.
I finally solved it with this:
?php $text= preg_replace(/(\015\012)|(\015)|(\012)/,nbsp;br /,
$rsDailynewsDetail-Fields('newsfull')); echo $text; ?
Help came of course from the link Holmes gave.
Thanks.
Budelak wrote:
Yes. Itis with enter key. It will not
Yes. Itis with enter key. It will not be possible to pre-determine the
length as this field is supposed to be a news field.
I'm lost as to how to go about this as the enter key does not generate
chr(13) when saving. I'm really lost.
Holmes directed me to http://us2.php.net/nl2br. I'm
Budelak wrote:
Hello,
Can someone help with this problem I've been trying to solve but don't
how to.
I have a field of type longtext that contains text with paragraphs at
the time of entry.
But when I display this text content, the paragraphs are not shown.
Everything will just appear in one
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