Curt Zirzow wrote:
$this-{$this-fname}();
or (what it actually is doing.. )
$func = $this-fname;
$this-$func();
Curt
The point here is that the named function is outside the object. That
is, $this-foo() doesn't exist, so $this-{$this-fname}(), does not
work either.
But if you look at
Curt Zirzow wrote:
or for the oneline purists :)
${ ${$this-fname} = $this-fname }();
wow.. ${} is more powerful than i had originally though.
Thank you Curt,
With your suggestion, I finally re-wrote the example, and here it is:
?php
function foo() {
echo In foo()br /\n;
}
class a {
var
I need to record the names of functions, and then use them later.
Recently I found the following example within the on-line documentation:
?php
function foo() {
echo In foo()br /\n;
}
$func = 'foo';
$func();// This calls foo()
?
then I supposed that it was easy to extend this concept to
I'm just starting with PHP, and I've been browsing the whole manual to
find how to solve the following problem:
1. An integer number is internally represented in 4 bytes. Say, for
instance, number 65 is represented by 0x0041, that is the string
\0\0\0\0x41, and not the string 65.
2. How
**
It was supposed to output:
***65***
[EMAIL PROTECTED] wrote:
http://us4.php.net/manual/en/function.base64-decode.php
-Original Message-
From: Julio Sergio Santana [EMAIL PROTECTED]
Sent: Jul 8, 2004 9:44 AM
To: [EMAIL PROTECTED]
Subject: [PHP] How can I write/read encoded numbers into/from a file
the data into a var
$iAnswer = ord($sBuff{0}) | ord($sBuff{1}) 8 | ord($sBuff{2}) 16
| ord($sBuff{3}) 24;
// Get the numerical value of each byte, then shift the bytes to get the
4 byte number. (Little Endian)
Chris
Julio Sergio Santana wrote:
I'm just starting with PHP, and I've been
6 matches
Mail list logo
