like this:
$digit = 122;
$digits = sprintf ("%08d", $digit);
print $digits;
Greets,
Edward
- Original Message -
From: "Jeff Sheltren" <[EMAIL PROTECTED]>
To: "Andy" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Saturday, February 02,
Why is it that you want to represent an int with leading 0's? Is it just
to print it out that way? If that is the case, then you can use the printf
function for formatted printing.
Jeff
At 10:53 AM 2/2/2002 +0100, Andy wrote:
>Hi guys,
>
>I am trying to force a int to be 8 digits. If it is
Hi guys,
I am trying to force a int to be 8 digits. If it is only 3 dig filling the
first ones with 0.
Anyhow I tryed it with type casting, but it does not matter what I try, I
always get an addition.
E.g:
$member_id is: 136
should be: 0136
Here is the code, which is still returning 1
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