Great, thanks!!
On Thu, 2003-08-21 at 22:20, Tom Rogers wrote:
> Hi,
>
> Friday, August 22, 2003, 12:55:37 PM, you wrote:
> JV> I want to create a function with an optional argument/parameter but have
> JV> never read a concrete answer on how to do it.
>
> JV> This is what I am assuming
>
> JV>
Hi,
Friday, August 22, 2003, 12:55:37 PM, you wrote:
JV> I want to create a function with an optional argument/parameter but have
JV> never read a concrete answer on how to do it.
JV> This is what I am assuming
JV> function test(arg1,arg2,arg3 = null)
JV> {
JV> arg3 will be optional
JV>
function test($arg1, $arg2, $arg3 = "")
{
if(isset($arg3))
{
// do whatever with $arg3
}
}
-Original Message-
From: Jonathan Villa [mailto:[EMAIL PROTECTED]
Sent: Thursday, August 21, 2003 7:56 PM
To: [EMAIL PROTECTED]
Subject: [PHP] How to make an argumen
I want to create a function with an optional argument/parameter but have
never read a concrete answer on how to do it.
This is what I am assuming
function test(arg1,arg2,arg3 = null)
{
arg3 will be optional
}
is this correct?
--
PHP General Mailing List (http://www.php.net/)
To unsubs
4 matches
Mail list logo
