using mssql_fetch_assoc worked out great. I had actually typed it in before
but the code formatting didn't change the color of the text like it normally
does for my mssql functions so I assumed it wasn't valid and deleted it.
Thanks to everyone for your help!
On 3/27/07, Jim Lucas <[EMAIL PROT
Dan Shirah wrote:
Okay, I thought this was VERY simple, but I cannot wrap my mind around what
I am doing wrong.
echo $_POST['max_id']; *The echo returns the correct result
*if($_POST['max_id'] ='') { *This is suppose to run the below query if
$_POST['max_id'] is not blank*
$max_id = $_POST['
2007. 03. 27, kedd keltezéssel 17.28-kor Dan Shirah ezt írta:
> Here are the results of my print_r
>
> Array ( [0] => 121 [1] => Y [2] => DS [3] => [4] => {03}
> [5] => 500 [6] => *** *[7] => John* [8] => Mark [9] => Doe [10] => 123 My
> Way [11] => 456 Your Place [12] => Smithvil
I would try an
echo $my_info[7];
[]s
Em Terça 27 Março 2007 18:28, Dan Shirah escreveu:
> Here are the results of my print_r
>
> Array ( [0] => 121 [1] => Y [2] => DS [3] => [4] => {03}
> [5] => 500 [6] => *** *[7] => John* [8] => Mark [9] => Doe [10] => 123 My
> Way [11] => 45
Dan Shirah wrote:
Here are the results of my print_r
Array ( [0] => 121 [1] => Y [2] => DS [3] => [4] =>
{03} [5] => 500 [6] => *** *[7] => John* [8] => Mark [9] => Doe [10]
=> 123 My Way [11] => 456 Your Place [12] => Smithville [13] => 12345
[14] => 5432 [15] => 123555
Here is the result from the Once again, bold and red is the
first_name field.
array(28) {
[0]=>
int(122)
[1]=>
string(1) "Y"
[2]=>
string(2) "DS"
[3]=>
string(16) ""
[4]=>
string(4) "{03}"
[5]=>
float(500)
[6]=>
string(4) "*** "
*[7]=>
string(4) "John"*
[8]=>
Here are the results of my print_r
Array ( [0] => 121 [1] => Y [2] => DS [3] => [4] => {03}
[5] => 500 [6] => *** *[7] => John* [8] => Mark [9] => Doe [10] => 123 My
Way [11] => 456 Your Place [12] => Smithville [13] => 12345 [14] => 5432
[15] => 123555 [16] => 1235550011 [17
2007. 03. 27, kedd keltezéssel 17.17-kor Dan Shirah ezt írta:
> echo $row_info['first_name']; returns nothing.
>
> However I have verified the correct spelling both in the database and
> in the PHP code and they are identical and when I print_r it shows
> that there is a value in the first_name
Have you tried use number instead name?
Something like:
echo $row_info[0];
On mysql, you've mysql_fetch_object... Does has anything like this on MS Sql
Server?
best regards...
Em Terça 27 Março 2007 18:17, Dan Shirah escreveu:
> echo $row_info['first_name']; returns nothing.
>
> However I ha
Send us the output of print_r($row_info)
feel free to mask out any data values you may wish.
Dan Shirah wrote:
echo $row_info['first_name']; returns nothing.
However I have verified the correct spelling both in the database and
in the
PHP code and they are identical and when I print_r it shows
echo $row_info['first_name']; returns nothing.
However I have verified the correct spelling both in the database and in the
PHP code and they are identical and when I print_r it shows that there is a
value in the first_name column of the record.
On 3/27/07, Zoltán Németh <[EMAIL PROTECTED]> wro
2007. 03. 27, kedd keltezéssel 16.56-kor Dan Shirah ezt írta:
> Sorry, had a typo.
>
> *$cc_first = $row_info['first_name'];
> echo "$cc_first";*
> this echo returns nothing.
and what does
echo $row_info['first_name'];
print out?
if still nothing, then probably
1) you misspelled the field name
2007. 03. 27, kedd keltezéssel 16.56-kor Dan Shirah ezt írta:
> print_r($row_info) display the entire column contents of the select id
>
> However,
>
> *$first = $row_info['first_name'];
> echo "$cc_first";*
>
> the above echo still returns nothing.
yeah because you assign that value to $first,
Sorry, had a typo.
*$cc_first = $row_info['first_name'];
echo "$cc_first";*
this echo returns nothing.
On 3/27/07, Dan Shirah <[EMAIL PROTECTED]> wrote:
print_r($row_info) display the entire column contents of the select id
However,
*$first = $row_info['first_name'];
echo "$cc_first";*
the
print_r($row_info) display the entire column contents of the select id
However,
*$first = $row_info['first_name'];
echo "$cc_first";*
the above echo still returns nothing.
On 3/27/07, Davi <[EMAIL PROTECTED]> wrote:
Em Terça 27 Março 2007 17:40, Dan Shirah escreveu:
> I have echoed somethin
Em Terça 27 Março 2007 17:40, Dan Shirah escreveu:
> I have echoed something out after virtually every line of code :)
>
> When I echo out my result ($result_info) it returns Resource id#2
> When I echo out my row ($row_info) it returns Array
>
> When I try to echo out a field from my array($my_inf
Echo $info where you hold you query, to make sure that is reasonable.
$result_info is the result set.
$row_info ...well you can use var_dump() on this to get its contents...
but if row_info prints out nothing, then there is probably a problem
with the query, or your query is returning nothing..
I have echoed something out after virtually every line of code :)
When I echo out my result ($result_info) it returns Resource id#2
When I echo out my row ($row_info) it returns Array
When I try to echo out a field from my array($my_info) it returns nothing at
all.
On 3/27/07, Brad Bonkoski <[
Dan Shirah wrote:
Should I use something besides mssql_fetch_row to get my result? No
matter
which method I use for determining if the value exists, I still get no
data
populated to my form.
Why not echo out your query before executing it, so you can run it
against the back end if you have it
2007. 03. 27, kedd keltezéssel 15.58-kor Dan Shirah ezt írta:
> Okay, I thought this was VERY simple, but I cannot wrap my mind around what
> I am doing wrong.
>
>
> echo $_POST['max_id']; *The echo returns the correct result
> *if($_POST['max_id'] ='') { *This is suppose to run the below query
Should I use something besides mssql_fetch_row to get my result? No matter
which method I use for determining if the value exists, I still get no data
populated to my form.
On 3/27/07, Tijnema ! <[EMAIL PROTECTED]> wrote:
On 3/27/07, Davi <[EMAIL PROTECTED]> wrote:
> Em Terça 27 Março 2007 17:
On 3/27/07, Davi <[EMAIL PROTECTED]> wrote:
Em Terça 27 Março 2007 17:02, Dave Goodchild escreveu:
> use: $_POST['max_id'] ==
>
> or even better:
>
> if (empty($_POST['max_id']))
Why not:
if (!(isset($_POST["max_id")))
?
If form is left empty, it is set, but it's stil empty. So if you
submit
Davi wrote:
Em Terça 27 Março 2007 17:02, Dave Goodchild escreveu:
use: $_POST['max_id'] ==
or even better:
if (empty($_POST['max_id']))
Why not:
if (!(isset($_POST["max_id")))
?
I think the poster *needs* the value to be set to something...
so if (isset(...)) {} would work
or
Because isset will return true if the variable is set, even if it is blank.
Empty will return true is the variable holds an empty string.
So I was dancing all around it by trying !== and = but did not try
!= /??? UGH!
On 3/27/07, Tijnema ! <[EMAIL PROTECTED]> wrote:
On 3/27/07, Dan Shirah <[EMAIL PROTECTED]> wrote:
> Okay, I thought this was VERY simple, but I cannot wrap my mind around
what
> I am doing wrong.
>
>
> ec
Em Terça 27 Março 2007 17:02, Dave Goodchild escreveu:
> use: $_POST['max_id'] ==
>
> or even better:
>
> if (empty($_POST['max_id']))
Why not:
if (!(isset($_POST["max_id")))
?
--
Davi Vidal
[EMAIL PROTECTED]
[EMAIL PROTECTED]
--
Agora com fortune:
"Around computers it is difficult to find th
Dan Shirah wrote:
Okay, I thought this was VERY simple, but I cannot wrap my mind around
what
I am doing wrong.
echo $_POST['max_id']; *The echo returns the correct result
*if($_POST['max_id'] ='') { *This is suppose to run the below query if
$_POST['max_id'] is not blank*
$max_id = $_POST[
On 3/27/07, Dan Shirah <[EMAIL PROTECTED]> wrote:
Okay, I thought this was VERY simple, but I cannot wrap my mind around what
I am doing wrong.
echo $_POST['max_id']; *The echo returns the correct result
*if($_POST['max_id'] ='') { *This is suppose to run the below query if
$_POST['max_id'] i
Em Terça 27 Março 2007 16:58, Dan Shirah escreveu:
> Okay, I thought this was VERY simple, but I cannot wrap my mind around what
> I am doing wrong.
>
>
> echo $_POST['max_id']; *The echo returns the correct result
> *if($_POST['max_id'] ='') { *This is suppose to run the below query if
> $_POST[
use: $_POST['max_id'] ==
or even better:
if (empty($_POST['max_id']))
Okay, I thought this was VERY simple, but I cannot wrap my mind around what
I am doing wrong.
echo $_POST['max_id']; *The echo returns the correct result
*if($_POST['max_id'] ='') { *This is suppose to run the below query if
$_POST['max_id'] is not blank*
$max_id = $_POST['max_id']; *Sets my
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