Well actually, all 80 fields (not records) that I'm displaying out of the
row (matched by phone number) have to be displayed on the page.
Non-Editable. Just displayed for viewing.
I am certainly using the query to search dbase and display the results. So
technically nothing that I'm doing is
Ave,
code:
$db = dbase_open(osm.dbf, 0);
if ($db) {
$record_numbers = dbase_numrecords($db);
for ($i = 1; $i = $record_numbers; $i++) {
$row = dbase_get_record_with_names($db, $i);
if ($row['PHONE'] == $thekey) {
echo ³found²;
}
else {
echo ³not found²;
}
}
Usen this:
echo ³not found²;
break;
Rahul S. Johari [EMAIL PROTECTED] escreveu na mensagem
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Ave,
code:
$db = dbase_open(osm.dbf, 0);
if ($db) {
$record_numbers = dbase_numrecords($db);
for ($i = 1; $i = $record_numbers; $i++) {
$row =
Rahul S. Johari wrote:
Ave,
code:
$db = dbase_open(osm.dbf, 0);
if ($db) {
$record_numbers = dbase_numrecords($db);
for ($i = 1; $i = $record_numbers; $i++) {
$row = dbase_get_record_with_names($db, $i);
if ($row['PHONE'] == $thekey) {
echo ³found²;
}
Just tried, isn't working! It's doing the same thing that exit; does.
Both
else {
echo Not Found;
break;
}
And
else {
echo Not Found;
exit;
}
Do the exact same thing. It will print not found (because it checks the
first row, and if the
Works like a charm!! I was trying something out with having a variable go
completely out of the functions loops and print the not found message,
but I wasn't hitting it. You did!
// ^^^--- now tested ;)
On 10/6/06 1:52 PM, Jochem Maas [EMAIL PROTECTED] wrote:
$msg = 'cannot open database!';
Why not check if $thekey is in the $db, then else echo not found?
seems all to much to do so little.
On Friday 06 October 2006 18:35, Rahul S. Johari wrote:
Ave,
code:
$db = dbase_open(osm.dbf, 0);
if ($db) {
$record_numbers = dbase_numrecords($db);
for ($i = 1; $i = $record_numbers;
Well, the actual script doesn't just print found number if the number
exists... It displays all the data from the database of that record, also
gives an interactive form to update the data and more.
On 10/6/06 3:25 PM, Børge Holen [EMAIL PROTECTED] wrote:
Why not check if $thekey is in the
On Friday 06 October 2006 21:45, Rahul S. Johari wrote:
Well, the actual script doesn't just print found number if the number
exists... It displays all the data from the database of that record, also
gives an interactive form to update the data and more.
Yes, and my point is still valid. need
I'm not sure if I understand your point then! I have about 80 fields in that
database that are fetched and displayed on the page using this code. If
there's a simpler way to do this, and have it work the if() else() error as
well, I would love to know about it...
On 10/6/06 3:47 PM, Børge Holen
On Fri, October 6, 2006 11:35 am, Rahul S. Johari wrote:
$db = dbase_open(osm.dbf, 0);
if ($db) {
$record_numbers = dbase_numrecords($db);
$found = false;
for ($i = 1; $i = $record_numbers; $i++) {
$row = dbase_get_record_with_names($db, $i);
if ($row['PHONE'] == $thekey) {
On Fri, October 6, 2006 2:45 pm, Rahul S. Johari wrote:
Well, the actual script doesn't just print found number if the
number
exists... It displays all the data from the database of that record,
also
gives an interactive form to update the data and more.
None of which is a Good Reason to
On Fri, October 6, 2006 2:59 pm, Rahul S. Johari wrote:
I'm not sure if I understand your point then! I have about 80 fields
in that
database that are fetched and displayed on the page using this code.
If
there's a simpler way to do this, and have it work the if() else()
error as
well, I
On Friday 06 October 2006 21:59, Rahul S. Johari wrote:
I'm not sure if I understand your point then! I have about 80 fields in
that database that are fetched and displayed on the page using this code.
If there's a simpler way to do this, and have it work the if() else() error
as well, I would
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