PROTECTED]>
Sent: Wednesday, June 20, 2001 8:37 AM
Subject: RE: [PHP] inserting a variable into a variable
> you so totally could use an assoc. array right now:
>
> $cat_adt = "x";
> $rm = "y";
>
> $a[ $cat_adt ] = "whatever";
> $a[ "$rm&qu
-of-variables and trying to get
$rm_$cat_adt == $rm_x
just use a hash... that's what it's there for ;)
> -Original Message-
> From: Tom Carter [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, June 20, 2001 5:24 AM
> To: Hasan Niyaz; [EMAIL PROTECTED]
> Subject: Re: [PHP]
Michi,
Yours did the trick...
thank you and everyone else who contributed.
Hasan
- Original Message -
From: <[EMAIL PROTECTED]>
To: "Hasan Niyaz" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Wednesday, June 20, 2001 11:46 AM
Subject: Re: [PHP] insertin
> I have come to a situation where i am having a variable inside another
variable.
> for example.
>
> $rm_$cat_adt
PHP would read this as trying to prepend the variable $cat_adt to the
variable $rm_
You seem to be trying to insert the variable $cat into the middle of a
variable.. possible, but
ginal Message-
From: Hasan Niyaz [mailto:[EMAIL PROTECTED]]
Sent: 20 June 2001 04:07
To: [EMAIL PROTECTED]
Subject: [PHP] inserting a variable into a variable
Hello all,
I have come to a situation where i am having a variable inside another
variable. for example.
$rm_$cat_adt
The above
> I have come to a situation where i am having a variable inside another
> variable.
> for example.
>
> $rm_$cat_adt
This works for me:
\n";
echo '"abc_def_ghi" = '.$abc_def_ghi."\n";
?>
michi
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Machen Sie I
why don't you do something like
$var = $foo && $baa;
?
-Original Message-
From: Hasan Niyaz [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, June 20, 2001 12:07 PM
To: [EMAIL PROTECTED]
Subject: [PHP] inserting a variable into a variable
Hello all,
I h
Hello all,
I have come to a situation where i am having a variable inside another variable.
for example.
$rm_$cat_adt
The above is a variable and $cat is again another variable
This does not work..
Need some help!
Thanks,
Hasan
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