Why don't you do
$result = mysql_query($query) or die(mysql_error());
or
$result = mysql_query($query);
echo mysql_error();
That way, instead of Query Failed you'll get something meaningful...
probably something that will solve the problem.
Justin French
on 26/08/02 11:55 PM, Chris Crane
Thank you. I will try that.
Justin French [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Why don't you do
$result = mysql_query($query) or die(mysql_error());
or
$result = mysql_query($query);
echo mysql_error();
That way, instead of Query Failed you'll
I got it working. It did not like the single quotes around the column names.
Chris Crane [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Thank you. I will try that.
Justin French [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Is there a way to find the time that mySQL took to perform a query.
like the one shown when you perform it on the console mode(0.09 sec or
so)
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Is there a way to find the time that mySQL took to perform a query.
like the one shown when you perform it on the console mode(0.09 sec or
so)
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Is there a way to find the time that mySQL took to perform a query.
like the one shown when you perform it on the console mode(0.09
sec or
so)
No. You can use microtime() to get the time before and after the query,
subtract smaller from larger, and that's your time. It's not the actual
Chris Kay wrote:
The query does not error out it just does not give any records, and I
Know
What part of The query does not error out do you not understand.
Why are there so many people willing to say what is wrong with a code but when it
comes to
A solution that go silent.
I find
I have a rather longer query which I would like to get all records past todays date.
Here is my query
$ttwo = date(YmdGi);
$dbq = select(select detail.*, type.type_name, status.status_name, staff.staff_name,
source.source_long,
source.source_short from detail, type, status, staff,
source
This is a MySQL question and best directed to the MySQL mailing lists
available at:
http://www.mysql.com/documentation/lists.html
-Original Message-
From: Chris Kay [mailto:[EMAIL PROTECTED]]
Sent: Thursday, June 13, 2002 4:33 PM
To: PHP General List
Subject: [PHP] MySQL Query
;
$dbq = select($sql);
-Original Message-
From: Chris Kay [mailto:[EMAIL PROTECTED]]
Sent: Thursday, June 13, 2002 4:33 PM
To: PHP General List
Subject: [PHP] MySQL Query Help
I have a rather longer query which I would like to get all
records past todays date.
Here
: Chris Kay [mailto:[EMAIL PROTECTED]]
Sent: Thursday, June 13, 2002 7:33 PM
To: PHP General List
Subject: [PHP] MySQL Query Help
I have a rather longer query which I would like to get all records
past
todays date.
Here is my query
$ttwo = date(YmdGi);
$dbq = select(select detail
, 14 June 2002 1:26 PM
To: Chris Kay; 'PHP General List'
Subject: RE: [PHP] MySQL Query Help
Man, where do I start. There could be so many things wrong.
First of all, this is a PHP list, not MySQL. Second, use
MySQL_error() after you issue a query to see if an error was
returned
On Fri, 14 Jun 2002, Chris Kay wrote:
The query does not error out it just does not give any records, and
I
Know
What part of The query does not error out do you not understand.
Why are there so many people willing to say what is wrong with a
code
but when it comes to A solution
I have a query
select cust_fnn, cust_name, agroup_access.group_access_cust from cust,
agroup_access where
agroup_access.group_access_group='$id'
cust.cust_fnn!=agroup_access.group_access_cust order by cust.cust_name
The 2 tables are as follows
agroup_access
agroup_access_id
[snip]
select cust_fnn, cust_name, agroup_access.group_access_cust from cust,
agroup_access where
agroup_access.group_access_group='$id'
cust.cust_fnn!=agroup_access.group_access_cust order by cust.cust_name
[/snip]
try this (note syntactical differences);
select cust_fnn, cust_name,
Hi,
Can someone tell me if there is a way to execute multiple MySQL
statements by passing *one* query containing a number of individual
statements to MySQL e.g.
UPDATE sampcomp SET fg=N, pctd=69, maxpctd=69.1 WHERE
sampcompid=3;UPDATE sampcomp SET fg=N, pctd=69.2, maxpctd=69.3
WHERE
of mysql_query().
It's worth a shot though.
Tyler Longren
Captain Jack Communications
www.captainjack.com
[EMAIL PROTECTED]
- Original Message -
From: Lee P Reilly [EMAIL PROTECTED]
To: PHP List [EMAIL PROTECTED]
Sent: Monday, April 22, 2002 3:07 PM
Subject: [PHP] MySQL query
Hi,
Can someone
Ok this could be the wrong place to ask this but there seems to be some
people in here that know mysql quite well.
My question is this; I have a database that looks like this.
galleries
gallery_id
gallery_name
1
3d
2
fractals
3
abstract
4
cats
5
cars
Images
image_id
gallery_id
Ok the formatting got lost on that I will try this again.
-Original Message-
From: Fifield, Mike [mailto:[EMAIL PROTECTED]]
Sent: Friday, April 19, 2002 8:57 AM
To: [EMAIL PROTECTED]
Subject: [PHP] MySql query
Ok this could be the wrong place to ask this but there seems to be some
Try:
SELECT gallery_name, image_id, image_name FROM galleries, Images WHERE
galleries.gallery_id = images.gallery_id
At 07:57 AM 4/19/2002 -0700, you wrote:
Ok this could be the wrong place to ask this but there seems to be some
people in here that know mysql quite well.
My question is this;
Hey... new to the list, but didn't have time to lurk and watch the traffic,
kind of in a bind here. I apologize in advance if I do something wrong...
Using this code:
?php
$link = mysql_connect()
or die(Could not connect);
In article [EMAIL PROTECTED], [EMAIL PROTECTED]
says...
Hey... new to the list, but didn't have time to lurk and watch the traffic,
kind of in a bind here. I apologize in advance if I do something wrong...
Using this code:
?php
$link = mysql_connect()
How can I tell whether anything was matched and changed after a
mysql_db_query?
If I'm in MySQL's console and I perform a query, it comes back and tells me
something like:
Query OK, 0 rows affected (0.00 sec)
Rows matched: 0 Changed: 0 Warnings: 0
And if something matched, 'Rows
$result = mysql_query(.)'
mysql_num_rows($result)
-Original Message-
From: Ashley M. Kirchner [mailto:[EMAIL PROTECTED]]
Sent: Friday, March 22, 2002 5:28 PM
To: PHP-General List
Subject: [PHP] MySQL query results
How can I tell whether anything was matched and changed after
Rick Emery wrote:
$result = mysql_query(.)'
mysql_num_rows($result)
Hrm, this is resulting in:
bWarning/b: Supplied argument is not a valid MySQL result resource in
b./index.php/b on line b16/bbr
Rows
The query does get executed, and the record does get changed.
The code
After a bit of research:
--
Rick Emery wrote:
$result = mysql_query(.)'
mysql_num_rows($result)
Hrm, this is resulting in:
bWarning/b: Supplied argument is not a valid MySQL result resource in
b./index.php/b on line b16/bbr
Rows
--
Rightfully so.
On 22 Mar 2002 at 16:41, Ashley M. Kirchner wrote:
Rick Emery wrote:
The query does get executed, and the record does get changed.
The code looks like this:
$conn = @MYSQL_CONNECT($host,$user,$password) ;
mysql_select_db($database, $conn);
$query = UPDATE clients SET
http://www.php.net/manual/en/function.mysql-affected-rows.php
On Fri, 22 Mar 2002, Ashley M. Kirchner wrote:
After a bit of research:
--
Rick Emery wrote:
$result = mysql_query(.)'
mysql_num_rows($result)
Hrm, this is resulting in:
bWarning/b: Supplied
oops. i see then my previous mail will not help in this case. wasn't
there something called 'affected_rows'? search the online manual for
'affected'.
On 22 Mar 2002 at 17:09, Ashley M. Kirchner wrote:
After a bit of research:
--
Rick Emery wrote:
$result =
Rasmus Lerdorf wrote:
http://www.php.net/manual/en/function.mysql-affected-rows.php
Thanks Rasmus. I did try that as well, same result. If I don't bother with the
$result, everything's fine. Like I said, the query runs, and gets executed. The DB
field gets changed as it should and all.
Chris wrote:
The query does get executed, and the record does get changed.
seems there is something wrong with the query, can you either echo the query and
feed it directly to mysql, (e.g. in phpmyadmin) see what happens?
Nope, the query's fine. I can run it manually, and through
Chris wrote:
oops. i see then my previous mail will not help in this case. wasn't
there something called 'affected_rows'? search the online manual for
'affected'.
I did. Read my reply to Rasmus as well. :) At this rate, I may just say to heck
with the $result, and always assume
But did you read the documentation? It states:
int mysql_affected_rows ( [resource link_identifier])
That's an optional link identifier. You don't feed it a result resource.
Just call it without any arguments. The affected rows is tied to a
database connection, not a result set.
-Rasmus
On
Rasmus Lerdorf wrote:
But did you read the documentation? It states:
Yes. But, reading it, and my brain actually registering what I was reading, now
that's a different story. :) It _is_ Friday after all. Thanks!
--
H | Life is the art of drawing without an eraser. - John Gardner
FWIW, straight from my code, with a few snips:
?
$sql = SELECT * FROM news ORDER BY id DESC LIMIT $limit;
$result = @mysql_query($sql);
print mysql_error();
if (!$result)
{
echo No database found.;
}
elseif(mysql_num_rows($result) == 0)
{
echo No records found.;
}
else
{
Justin French wrote:
$sql = SELECT * FROM news ORDER BY id DESC LIMIT $limit;
You're forgetting (or just didn't read my code), I'm UPDATE-ing, not SELECT-ing.
mysql_num_rows() doesn't work on UPDATE.
Anyway, thanks to Rasmus for pointing out my error.
--
H | Life is the art of
OK, I need to know is there a place where i can find out how to pull
information(TEXT) from a MySQL DB table and print where i place a variable
in a php page?
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On Monday, March 4, 2002, at 02:26 PM, Jason Whitaker wrote:
OK, I need to know is there a place where i can find out how to pull
information(TEXT) from a MySQL DB table and print where i place a
variable
in a php page?
This tutorial was my introduction to the concept, but you can find
This tutorial was my introduction to the concept, but you can
find this
information in a hundred other places:
http://hotwiredlycoscom/webmonkey/programming/php/tutorials/tutorial4html
I'd recommend that tutorial only as a guideline for using mySQL and php Don't try to
use the
On Monday, March 4, 2002, at 03:29 PM, Matt Schroebel wrote:
I'd recommend that tutorial only as a guideline for using mySQL and
php. Don't try to use the obfuscated logic in the final example as a
good way to code an add/change/delete page. It's much easier if there
are radio buttons
I don't really remember the tutorial very well I thought it
did a fine job of explaining some of the basics I spent a few hours
with it and felt pretty good However, I agree that it's not a good
intro to PHP's basic features
I stumbled on php a few years ago, and that was my intro
Erik Price wrote:
I haven't seen yet a tutorial that teaches coding from the perspective
of using register_globals off, which I think is pretty important
(personal opinion) It's not that hard to pick up, though, once you've
gotten started Still, I think it makes alot more sense to do so
Okay, so when I INSERT a row of information into a MySQL database, I
don't want it to place it at the first empty row it findsI want it
to put it after the very last exsisting row.
One of the fields of the database is an AUTO_INCREMENT type, so Im
assuming Im gonna use that in the query.
If you are using a table with AUTO_INCREMENT set for one of the fields,
the default is for MySQL to assign any new row an AUTO_INCREMENT value
that is one higher than the currently highest value in that column. In
other words, MySQL by default does exactly what you say you are trying
to do.
]
Subject: [PHP] MySQL query question
Okay, so when I INSERT a row of information into a MySQL database, I
don't want it to place it at the first empty row it findsI want it
to put it after the very last exsisting row.
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I have the following query
$query = INSERT INTO acl ( username, password )
VALUES ( 'henri', ENCRYPT('diesel','henri') );
This is the error i get :
Column 'password' cannot be null
What is wrong with my query?
--
PHP General Mailing List (http://www.php.net/)
To
On Fri, 23 Nov 2001 16:17, De Necker Henri wrote:
I have the following query
$query = INSERT INTO acl ( username, password )
VALUES ( 'henri', ENCRYPT('diesel','henri') );
This is the error i get :
Column 'password' cannot be null
What is wrong with my query?
On waht systems does encrypt() work on.In my Mysql client my query results
are null,so i dont have encrypt on my system!
-Original Message-
From: David Robley [mailto:[EMAIL PROTECTED]]
Sent: 23 November 2001 08:24
To: De Necker Henri; PHP-General (E-mail)
Subject: Re: [PHP] MySQL query
On Fri, 23 Nov 2001 17:05, De Necker Henri wrote:
-Original Message-
From: David Robley [mailto:[EMAIL PROTECTED]]
Sent: 23 November 2001 08:24
To: De Necker Henri; PHP-General (E-mail)
Subject: Re: [PHP] MySQL query problem!
On Fri, 23 Nov 2001 16:17, De Necker Henri wrote:
I
Hi all,
I'm looking at the following scenario: I have MySQL two tables with
usernames in both of them, I need to get usernames(A) - usernames(B)
In Oracle I would use:
SELECT username FROM user
MINUS
SELECT username FROM task_assignment
Since MySQL does not support MINUS, I tried using the
]
Subject: [PHP] MySQL query
Hi all,
I'm looking at the following scenario: I have MySQL two tables with
usernames in both of them, I need to get usernames(A) - usernames(B)
In Oracle I would use:
SELECT username FROM user
MINUS
SELECT username FROM task_assignment
Since MySQL does not support MINUS
This is kindof a weird question so bear with me as I try to explain.
I have a session table that gets updated when a user logs in/out. If they
don't logout, some info is left unchanged. I have a cron script that takes
care of the stray sessions so that's all good. In the sessions table,
there's
[mailto:[EMAIL PROTECTED]]
Sent: martedì 2 ottobre 2001 6.04
To: [EMAIL PROTECTED]
Subject: [PHP] mysql query for current id-1
This is kindof a weird question so bear with me as I try to explain.
I have a session table that gets updated when a user logs in/out. If
they don't logout, some info
Hi,
The reason probably is that you're limiting from the
2nd row, instead of the first, 0 is the row starting
point (I think).
So :
$sql=select id,agent,host, DATE_FORMAT(time_in, '%M
%d, %Y, %l:%i') AS
unixdate from logged_in WHERE userid='$current_user'
ORDER BY id DESC LIMIT 0, 1;
=
)
[mailto:[EMAIL PROTECTED]]
Sent: October 2, 2001 12:14 AM
To: 'Jason Dulberg'; [EMAIL PROTECTED]
Subject: RE: [PHP] mysql query for current id-1
What about this:
$sql=select id,agent,host, DATE_FORMAT(time_in, '%M %d, %Y, %l:%i') AS
unixdate from logged_in WHERE userid='$current_user' ORDER
]
Subject: RE: [PHP] mysql query for current id-1
Thank you for your lightning fast response!!
I tried your query but it appears to be coming up with the current id
rather than the users last login.
__
Jason Dulberg
Extreme MTB
http://extreme.nas.net
-Original Message-
From
: RE: [PHP] mysql query for current id-1
... DESC LIMIT 1,1
As you wrote yourself.
Sorry, haven't taken in consideration ;-)
Maxim Maletsky
www.PHPBeginner.com
-Original Message-
From: Jason Dulberg [mailto:[EMAIL PROTECTED]]
Sent: martedì 2 ottobre 2001 6.59
To: Maxim
Code:
?
$Query = UPDATE feRegUsers SET Constructor='2001-09-17',
Enertec='2001-09-17', Seatec='2001-09-17' WHERE ID LIKE '288';
mysql_quory($Query);
print mysql_error();
?
That results
You have an error in your SQL syntax near 'Constructor='2001-09-17',
Enertec='2001-09-17', Seatec='2001-09-17''
On Mon, Sep 10, 2001 at 03:59:36PM -0500, Sheridan Saint-Michel wrote:
Well, I played with this a little more and it seems to be acting oddly when
you first
call this select unless you set the variable first. So if the below doesn't
work try
actually doing this
$query=set @count=NULL;
I'm trying to make a query that will number it's own output rows. e.g. when
listing all the entries in a table that are related to a specific invoice,
there will be a column with a monotonically increasing integer value (1-x
where x is the number of matching entries).
I know I can easily do
:
set @count=Null;
between the selects =P
Sheridan Saint-Michel
Website Administrator
FoxJet, an ITW Company
www.foxjet.com
- Original Message -
From: Michael George [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, September 10, 2001 2:20 PM
Subject: [PHP] MySQL query help
I'm
www.foxjet.com
- Original Message -
From: Sheridan Saint-Michel [EMAIL PROTECTED]
To: Michael George [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Monday, September 10, 2001 3:29 PM
Subject: Re: [PHP] MySQL query help
See if this does what you are shooting for:
select tableName.*,if(@count=1
i have two tables here, i want to insert the customername from the Username table and
insert it into the Classification table.
is the below query correct cause i can't seem to get it to work.
$query = INSERT INTO Classification (Customername)
(SELECT Customername)
FROM Username
WHERE
Can it cause any problems if mySQL query is very long? I have to compare
many words to many fields in my DB and I've done it like
Field LIKE '%searchword%' || Field LIKE '%searchword%' || Field LIKE
'%searchword%'.. Query is build by a function, so I don't know the
exact length but it is
]]
Sent: Tuesday, August 28, 2001 8:51 AM
To: Php-General
Subject: [PHP] MySQL query length
Can it cause any problems if mySQL query is very long? I have to compare
many words to many fields in my DB and I've done it like
Field LIKE '%searchword%' || Field LIKE '%searchword%' || Field
Guys, why isn't this working? :)
SELECT * FROM links WHERE name LIKE %te% OR description LIKE %te% OR url LIKE
%te% AND approved=1 LIMIT 5
I am using a PHP script to add items to the database and a small search file to grab
them. Thing is, I want the above to grab ONLY ones that have
Yes, there is a problem.
--
SELECT *
FROM links
WHERE 1=1
and ( name LIKE %te%
OR description LIKE %te%
OR url LIKE %te% )
AND approved=1 LIMIT 5;
--
--- Jeff Lewis [EMAIL PROTECTED] wrote:
Guys, why isn't this working? :)
SELECT * FROM links WHERE name LIKE %te% OR description
LIKE
What I need to do is to compare if one field matches a value from a huge
list of values.
Do I need to query like
SELECT * FROM table WHERE field LIKE '%value1%' || field LIKE '%value2%'
or can I do it something like this
SELECT * FROM table WHERE field LIKE ('%value1%' || '%value2%')?
Niklas
Hi all,
newbie to MySQL...
I get this error:
Supplied argument is not a valid MySQL result resource in /usr/local/
blah blah blah
From this query:
$username = juddy2;
$sql = SELECT * FROM staff WHERE id=.$username;
$result = mysql_query($sql);
However, this works okay:
$username = juddy2;
Justin -
there's an error in your query. I think it should be:
$sql = SELECT * FROM staff WHERE id='$username';
Anyway, to see which is the problem just
?
print mysql_error();
?
after $result = mysql_query($sql);
HTH
Gianluca
JF newbie to MySQL...
JF I get this error:
JF Supplied
You wrote:
I have a table that looks like
Name | Type | X | Y
Foo| Ship | 9 | 29
Bar| Base | 9 | 29
Is there any way I can write a query that selects
everything with Type = Base, and X and Y = Foo's X and Y?
ie
Select * from table where type = Base and X = {Foo:X} and Y =
Thanks! That's exactly what I was looking for = 3 )
- Original Message -
From: Morten Winkler Jørgensen [EMAIL PROTECTED]
To: Sheridan Saint-Michel [EMAIL PROTECTED]
Sent: Thursday, July 19, 2001 2:56 AM
Subject: Re: [PHP] MySQL Query
Hi Sheridan,
You wrote:
SSM I have a table
Ok, using PHP and mySQL have two tables that look something like this;
Table 1 (users):
userID
location
Table 2 (resumes):
resumeID
userID
I am trying to form a query to pull all the locations and list them on the page.
While I could only just select from the users one I do want to be able
: [PHP] PHP/mySQL Query
Ok, using PHP and mySQL have two tables that look something like this;
Table 1 (users):
userID
location
Table 2 (resumes):
resumeID
userID
I am trying to form a query to pull all the locations and list them on
the
page. While I could only just select from the users one I
Yes but for the first query all I want to do is list the locations and not
multiple times
Jeff
- Original Message -
From: King, Justin [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, July 19, 2001 1:46 PM
Subject: RE: [PHP] PHP/mySQL Query
I'm assuming you're trying
Whoops.. do SELECT DISTINCT
-Justin
-Original Message-
From: Jeff Lewis [EMAIL PROTECTED]
Sent: Thursday, July 19, 2001 1:08 PM
To: King, Justin; [EMAIL PROTECTED]
Subject: Re: [PHP] PHP/mySQL Query
Yes but for the first query all I want to do is list the locations
the statement should look like this:
$result = mysql_query(select * from table where type = 'Base' and x = 'x' and
y = 'y');
Ryan Fischer [EMAIL PROTECTED] wrote in message
01d901c1101e$9cd43220$80c93fd0@ryan">news:01d901c1101e$9cd43220$80c93fd0@ryan...
You wrote:
I have a table that looks
You wrote:
Ryan Fischer [EMAIL PROTECTED] wrote in message
01d901c1101e$9cd43220$80c93fd0@ryan">news:01d901c1101e$9cd43220$80c93fd0@ryan...
You wrote:
I have a table that looks like
Name | Type | X | Y
Foo| Ship | 9 | 29
Bar| Base | 9 | 29
Is there any way I can write a
: Thursday, July 19, 2001 09:25
Subject: Re: [PHP] MySQL Query.
Thanks but it is not working!
My problem goes like this:
Frankly speaking I am trying to make web based accounting package for my
organization.
I have talbes:
Voucher
Sales
Cash
Bank
Income
Expenses, etc.
All
I have a table that looks like
Name | Type | X | Y
Foo| Ship | 9 | 29
Bar| Base | 9 | 29
Is there any way I can write a query that selects
everything with Type = Base, and X and Y = Foo's X and Y?
ie
Select * from table where type = Base and X = {Foo:X} and Y = {Foo:Y};
Anyway,
Greetings !
I have following tables in MySQL:
TableItem
idlist
1 Banana
2 Orange
3 Mango
Other tables are:
Banana, Orange, Mango
Instead of selecting Table Banana directly I need to select it as select
$TableItem.list where id=1 or something like that for editing or deleting
Try,
select '$TableItem'.list where id = 1;
py
- Original Message -
From: Deependra B. Tandukar [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, July 18, 2001 12:14 AM
Subject: [PHP] MySQL Query.
Greetings !
I have following tables in MySQL:
TableItem
idlist
1
:11 PM
Subject: [PHP] Missing first record in PHP/Mysql query
Excuse me if this is too newbie...but I'm writing a simple script to
query a database and loop through the reuslts, echoing them on the page.
When I enter the query at the mysql command line, I get the correct
results. But the same
Excuse me if this is too newbie...but I'm writing a simple script to
query a database and loop through the reuslts, echoing them on the page.
When I enter the query at the mysql command line, I get the correct
results. But the same query run through PHP renders all results except
the first one.
At 7:11 PM -0700 7/5/01, Rory O'Connor wrote:
Excuse me if this is too newbie...but I'm writing a simple script to
query a database and loop through the reuslts, echoing them on the page.
When I enter the query at the mysql command line, I get the correct
results. But the same query run
I fought the urge to post this here but have to :(
I have two tables named like this:
owners
-ownerID
-teamname
-more fields
teampages
-ownerID
-bio
Anyway, I'm doing a select on the database like this: select ownerID,
last_update FROM teampages ORDER BY last_update DESC LIMIT 10
The thing
Message -
From: Jeff Lewis [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, July 05, 2001 6:59 PM
Subject: [PHP] PHP/mySQL Query
I fought the urge to post this here but have to :(
I have two tables named like this:
owners
-ownerID
-teamname
-more fields
teampages
-ownerID
-bio
On Thu, 5 Jul 2001, Jeff Lewis wrote:
owners
-ownerID
-teamname
-more fields
teampages
-ownerID
-bio
Anyway, I'm doing a select on the database like this: select ownerID,
last_update FROM teampages ORDER BY last_update DESC LIMIT 10
The thing is, I want to get the team name from the
SELECT t.ownerID, t.last_update, o.teamname
FROM teampages t, owners o
WHERE t.ownerID = o.ownerID
ORDER BY t.last_update DESC LIMIT 10
-Original Message-
From: Jeff Lewis [mailto:[EMAIL PROTECTED]]
Sent: Thursday, July 05, 2001 5:00 PM
To: [EMAIL PROTECTED]
Subject: [PHP] PHP/mySQL
Jeff Lewis [EMAIL PROTECTED] wrote:
I fought the urge to post this here but have to :(
owners
-ownerID
-teamname
-more fields
teampages
-ownerID
-bio
Anyway, I'm doing a select on the database like this: select ownerID,
last_update FROM teampages ORDER BY last_update DESC LIMIT 10
On 09-May-01 Jon Haworth wrote:
snip
be sure to check for the NULL :
if (isset($amyrow[date])) {
if ($amyrow[date] == -00-00 00:00:00) {
echo no date;
} else {
echo $amyrow[date];
}
} else {
Hello,
I pull some data from mysql with the php code below.
On the date field if there is no date on mysql it displays : -00-00
00:00:00
I would like to change this -00-00 00:00:00 to no date for example..
Or if the cel is empty to (because otherwise the tableborders are messed
up)
[date];
}
echo /td;
}
}
HTH
Jon
-Original Message-
From: Andras Kende [mailto:[EMAIL PROTECTED]]
Sent: 28 April 2001 17:01
To: [EMAIL PROTECTED]
Subject: [PHP] PHP Mysql query data conversion newbie
Hello,
I pull some data from mysql with the php code
On Sat, 28 Apr 2001, Andras Kende wrote:
Hello,
I pull some data from mysql with the php code below.
On the date field if there is no date on mysql it displays : -00-00
00:00:00
I would like to change this -00-00 00:00:00 to no date for example..
hmm... mysql can do this, works
Hi,
I have a couple questions... first, is there a notable MySQL General List
like this one?
Second, how do you write this query properly, or can it be done?
select concat(date_format(date, "%W, %e %M %Y")," ",time) as date from TABLE
order by date DESC;
Thanks!
Jeff
--
PHP General Mailing
In article [EMAIL PROTECTED],
[EMAIL PROTECTED] ("Jeff Holzfaster") wrote:
I have a couple questions... first, is there a notable MySQL General List
like this one?
Yes. The list on mysql.com is quite active and, like this one, it's common
to get responses directly from one of the
The MySQL manual has a chapter on date/time factions. Or is it
the 'order
by' clause that's giving you trouble...? I assume that 'date' is a
reserved word, so it may be confusing mysql. In which case, try using a
different alias, like 'f_date".
This works: select date_format(date,
In article [EMAIL PROTECTED],
[EMAIL PROTECTED] ("Jeff Holzfaster") wrote:
This works: select date_format(date, "%W, %e %M %Y") as date from table
This doesn't: select concat(date_format(date, "%W, %e %M %Y")," ",time) as
time_of_day
I'm wondering if it is possible to use concat in this
Hi,
I have a MySQL statement, namely:
SELECT COUNT(*) AS Count FROM images i LEFT JOIN categories c ON
i.cat_id=c.id LEFT JOIN subcategories s ON i.subcat_id=s.id
I want to change the LEFT JOINs to INNER JOINs like so:
SELECT COUNT(*) AS Count FROM images i INNER JOIN categories c ON
No, that is exactly as the PHPLib Debug function is returning... :|
-Original Message-
From: Samantha Savvakis [mailto:[EMAIL PROTECTED]]
Sent: Monday, 22 January 2001 3:21 PM
To: Matt Stone
Subject: RE: [PHP] MySQL Query Error
I'm not sure why are getting that error.
Is the statement
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