RE: [PHP] $_SESSIONS and printing off..

2003-02-18 Thread Rich Gray
Er... well I've seen a lot worse code than that but maybe you could use ... if (isset($_SESSION['username']) !empty($_SESSION['username'])) { echo 'Welcome '.$_SESSION['username'].', you are still logged in.'; } else { header... etc etc } Rich -Original Message- From:

Re: [PHP] $_SESSIONS and printing off..

2003-02-18 Thread Frank Keessen
$_SESSION['level'] to 2 but how can i check that with the above line? Thanks for your help, Frank - Original Message - From: Rich Gray [EMAIL PROTECTED] To: Frank Keessen [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Tuesday, February 18, 2003 11:53 AM Subject: RE: [PHP] $_SESSIONS and printing

RE: [PHP] $_SESSIONS and printing off..

2003-02-18 Thread Rich Gray
]] Sent: 18 February 2003 12:15 To: Rich Gray; [EMAIL PROTECTED] Subject: Re: [PHP] $_SESSIONS and printing off.. Thanks, But then another question; if (isset($_SESSION['username']) !empty($_SESSION['username'])) { echo 'Welcome '.$_SESSION['username'].', you are still logged in.'; I

Re: [PHP] $_SESSIONS and printing off..

2003-02-18 Thread Frank Keessen
: Rich Gray [EMAIL PROTECTED] To: Frank Keessen [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Tuesday, February 18, 2003 1:25 PM Subject: RE: [PHP] $_SESSIONS and printing off.. Um... how about... echo 'Welcome '.$_SESSION['username'].', you are still logged in and your authentication level

Re: [PHP] $_SESSIONS and printing off..

2003-02-18 Thread Ernest E Vogelsinger
At 13:33 18.02.2003, Frank Keessen said: [snip] This is working fine. But i've set $_SESSION['level'] to value 2 (that's done in the php file that calls this one). Now i want the above code to check for the level and if is not equal to two than go to the