On Wednesday 31 January 2001 16:03, Boget, Chris wrote:
Now, say I have a function where one of the arguments
is passed by reference and is modified within the function.
I can call this function on one line
myFunc( $modifiedVariable );
and print out the value (if any) of $modifiedVariable
What about using normal pass-by-value and returning the result?
function MyFunc ($SomeVal) {
$SomeVal += 42;
return $SomeVal;
}
echo MyFunc ($StrangeVal);
I'm already using the return value for something else.
Anyway - functions that get their parameters by reference and
modify
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