On Wed, Mar 6, 2013 at 1:36 PM, Tobiah tshep...@rcsreg.com wrote:
I'm talking to the Membersuite SOAP api. They have a Get() method
and a Save() method for objects. I call Get(), and get an object
back representing an individual. I pass it back to Save() and I
get this:
Fatal error:
2007. 10. 25, csütörtök keltezéssel 09.15-kor Jeff Mckeon ezt írta:
I'm getting this error on a php based ticket system we have. I don't see
this on the old server running php4. This new server is running php5.
PHP_Fatal_error:__Cannot_use_object_of_type_PEAR_Error_as_array_in_/srv/www/
if (mysql_query($sqlInsertUser, $conn))
$messagesqlInsertUser = 'Success...';
else
$messagesqlInsertUser = 'Error: ' . mysql_error();
$result = mysql_query($sqlInsertUser);
I see this being executed twice. - mysql_query($sqlInsertUser); I
believe that is your problem. Change the
Do you have the Host field set to unique?
--
http://www.web-buddha.co.uk
http://www.projectkarma.co.uk
You can try Xdebug. http://www.xdebug.org/
Can you send some code to reproduce the error?
On Sunday 26 October 2003 10:24 am, Fabio Rotondo wrote:
Hi,
I am experiencing a strange error while using PHP 4.3.4RC2.
In the apache2 log, I read:
fatal: cannot realloc() 1937201923 bytes.
I do
Hi
Odd - I copy/paste the code below and run it against windows version of
php4.0.6 and it's okay
Maybe you've got a hidden char there somewhere?
Martin
-Original Message-
From: Sid [mailto:[EMAIL PROTECTED]
Sent: Wednesday, 17 September 2003 5:39 AM
To: [EMAIL PROTECTED]
Subject:
]; [EMAIL PROTECTED]
Sent: 16 September 2003 Tuesday 12:10 AM
Subject: RE: [PHP] Strange error
Hi
Odd - I copy/paste the code below and run it against windows version of
php4.0.6 and it's okay
Maybe you've got a hidden char there somewhere?
Martin
-Original Message-
From: Sid [mailto
Sid wrote:
You are probably right. I typed in the same code into a new file and it
started to work. Just for the record, I copied and pasted this code from
Opera in Windows. Anyone had similar problems?
Yes. There are sometimes hidden characters in code that you cut and
paste like that. It will
I have heard about a bug in this version that also included some first 4
characters loss. Try searching
Daniele Baroncelli wrote:
Hi guys,
I have very weird problem.
I have installed the PHP version 4.2.3 on the LINUX virtual server of my web
project.
Previously I had the PHP version 4.0.6.
From: Jesse Lawrence [mailto:[EMAIL PROTECTED]]
Sent: Monday, August 26, 2002 9:36 AM
To: [EMAIL PROTECTED]
Subject: [PHP] strange error message when trying to start apache
Everything appeared to go smoothly, except when
I try to start up Apache, I get the following error
message:
On Wed, 22 Aug 2001, Jeremy Morano wrote:
I get an error message which I can't figure out.
Its a Parse error: on line 142 which is the last line of the page containing
absolutly no code. The last line of code is simply /HTML..Did
anyone have a similar experience? Can anyone help me
At 03:12 PM 8/22/01 -0400, you wrote:
Hi,
I get an error message which I can't figure out.
Its a Parse error: on line 142 which is the last line of the page containing
absolutly no code. The last line of code is simply /HTML..Did
anyone have a similar experience? Can anyone help me out
Heya!
All adive given so far is good. You might also want to check for a
non-closed if { } statement.
If you've got something like:
-
html
? if(isset($foo)) {?
html 1
? } else { ?
html2
/html
-
You'll get an error in the last line, where the /html resides.
Hope this is a
How can the resource be invalid if I'm getting the results back? I'd
appreciate any explaination.
What results are you getting?...
$connection_id = @mysql_connect ('localhost', 'root') or die('No
connection.');
$database_id = @mysql_select_db ('cgcms', $connection_id) or die('No
In article 046401c0fee3$a6c789e0$6401a8c0@Lynchux100,
[EMAIL PROTECTED] (Richard Lynch) wrote:
$result_id = @mysql_query(DESC $table_name $field_name);
I don't think DESC $table_name $field_name is valid SQL, is it?...
DESC is DESCENDING in an ORDER BY clause...
Perhaps if you
dunno
but my it's just failing at the mysql_connect()
shouldn't you specify the password too?
[EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
The following code fragment works properly, in that I get the output I'm
expecting. However, if I don't disable
On Wed, 27 Jun 2001 06:31, [EMAIL PROTECTED] wrote:
The following code fragment works properly, in that I get the output
I'm expecting. However, if I don't disable error messages with @, I get
an error message from PHP saying: Warning: Supplied argument is not a
valid MySQL result resource in
- Original Message -
From: David Robley [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; PHP General [EMAIL PROTECTED]
Sent: Wednesday, June 27, 2001 8:47 AM
Subject: Re: [PHP] Strange error on mysql_fetch_array
On Wed, 27 Jun 2001 06:31, [EMAIL PROTECTED] wrote:
The following code fragment
From experience with oracle, desc only works in an sql prompt, not through
code. So use the more lengthy method
in mysql:
SHOW FIELDS FROM $table_name
in oracle:
SELECT c.column_name, c.data_type, c.data_length, c.data_precision,
c.data_scale, c.nullable FROM
It may not be responsible for the error, but you ought to move your fclose
to before your return(true) statement, as it never gets executed at all in
your code.
Cheers
--
Phil Driscoll
Dial Solutions
+44 (0)113 294 5112
http://www.dialsolutions.com
http://www.dtonline.org
--
PHP General
In article p04320407b6e35b98ce1b@[209.246.86.33],
[EMAIL PROTECTED] (Kristofer Widholm) wrote:
Warning: Bad escape sequence: \. in validate.inc.php on line 142
CODE:
Line 142: if (!eregi("index\.php",$PHP_SELF)) {
blah blah blah;
}
I didn't know there was any other escape sequence
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