Re: [PHP] Variable problem?

2007-07-24 Thread Richard Lynch
On Tue, July 24, 2007 3:33 pm, Luc wrote: > if (empty($_POST['altura'])){ > $contacter_form_error[] = 'favor preencher altura'; > } > if (empty($_POST['largura'])){ > $contacter_form_error[] = 'favor preencher largura'; > } >

Re: [PHP] Variable problem?

2007-07-24 Thread Luc
Good evening Daniel, It was foretold that on 24/7/2007 @ 17:47:46 GMT-0400 (which was 18:47:46 where I live) Daniel Brown would write: > You're not defining $contato_name. > Do this: > $contato_name = $_POST['contato_name']; Yes!! Oh so simple for a non-newbie lol

Re: [PHP] Variable problem?

2007-07-24 Thread Daniel Brown
[ For those of you who are going to get pissed for top-posting, find something better to bitch about. I'm in a rush, but trying to help. ;-P ] Luc, You're not defining $contato_name. Do this: $contato_name = $_POST['contato_name']; On 7/24/07, Luc <[EMAIL PROTECTED]> wrote:

Re: Re: RE: [PHP] Variable Problem

2003-02-06 Thread Jason Wong
On Thursday 06 February 2003 22:50, Sunfire wrote: > no that doesnt work either what you get when you do that one in the edit > box is: > using: > > > or any different with echo in the value field gives me in the box: > }> > ...rest of the script outside the box Spot the difference between your co

Re: Re: RE: [PHP] Variable Problem

2003-02-06 Thread Sunfire
t;[EMAIL PROTECTED]> Sent: Thursday, February 06, 2003 12:25 AM Subject: Re: Re: RE: [PHP] Variable Problem > On Thursday 06 February 2003 07:48, Sunfire wrote: > > on any server i ever dealt with if i put: > > > > > in the edit box for the value i always always end up wi

Re: Re: RE: [PHP] Variable Problem

2003-02-05 Thread Jason Wong
On Thursday 06 February 2003 07:48, Sunfire wrote: > on any server i ever dealt with if i put: > > > in the edit box for the value i always always end up with what $sent stands for..the only way i found it to work is with echo <<< but > maybe im missing something With the above you should end up

Re: Re: RE: [PHP] Variable Problem

2003-02-05 Thread Chris Shiflett
--- Sunfire <[EMAIL PROTECTED]> wrote: > on any server i ever dealt with if i put: > > > in the edit box for the value i always always end up > with way i found it to work is with echo <<< but maybe im > missing something You are "missing" correct PHP syntax and correct HTML syntax, so I guess th

Re: Re: RE: [PHP] Variable Problem

2003-02-05 Thread Sunfire
on any server i ever dealt with if i put: > in the edit box for the value i always always end up with To: "Sunfire" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]> Sent: Wednesday, February 05, 2003 5:44 PM Subject: Spam: Re: RE: [PHP] Variable Problem > --- Sunfire <[E

Re: RE: [PHP] Variable Problem

2003-02-05 Thread Chris Shiflett
--- Sunfire <[EMAIL PROTECTED]> wrote: > you can do: > echo << //any valid html code here > > BLOCK; No, he needed to output $sent, which is dynamic. Also, it is a lot cleaner (and likely faster) just to use to switch in/out of PHP as needed. If you're writing a bunch of static HTML, there's no

Re: RE: [PHP] Variable Problem

2003-02-05 Thread Sunfire
0 lines of code a block... - Original Message - From: "Leonard Burton" <[EMAIL PROTECTED]> To: "Sierra Times.com" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]> Sent: Wednesday, February 05, 2003 4:16 PM Subject: Spam: RE: [PHP] Variable Problem > You

Re: Re: [PHP] Variable Problem

2003-02-05 Thread Sunfire
if you want to get variables into a form by value= do something like this: and so on - Original Message - From: "Jason Wong" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Wednesday, February 05, 2003 3:59 PM Subject: Spam: Re: [PHP] Variable Problem >

RE: [PHP] Variable Problem

2003-02-05 Thread Leonard Burton
You need to put quotes around the vars. If I were you I would do this: print ""; print ""; You need the quotes. Leonard. www.phpna.com -Original Message- From: Sierra Times.com [mailto:[EMAIL PROTECTED]] Sent: Wednesday, February 05, 2003 3:41 PM To: [EMAIL PROTECTED] Subject: [PHP] V

Re: [PHP] Variable Problem

2003-02-05 Thread Jason Wong
On Thursday 06 February 2003 04:41, Sierra Times.com wrote: > I have a variable that get's chopped off at the %20 character. > > In the form page I have: > From: > E-mail address: > > > $sent and $name shows up fine, but immedieately I added (for testing) > > > > > > > this statemen

RE: [PHP] Variable problem

2002-03-22 Thread Chris
On 22 Mar 2002 at 17:27, Rick Emery wrote: > ${varable}ABC in quotes you can help php with {$(varabl)}ABC > > > -Original Message- > From: Leif K-Brooks [mailto:[EMAIL PROTECTED]] > Sent: Friday, March 22, 2002 5:21 PM > To: Rick Emery > Subject: Re

RE: [PHP] Variable problem

2002-03-22 Thread Rick Emery
${varable}ABC -Original Message- From: Leif K-Brooks [mailto:[EMAIL PROTECTED]] Sent: Friday, March 22, 2002 5:21 PM To: Rick Emery Subject: Re: [PHP] Variable problem on 3/22/02 6:18 PM, Rick Emery at [EMAIL PROTECTED] wrote: show your code -Original Message- From

RE: [PHP] Variable problem

2002-03-22 Thread Rick Emery
show your code -Original Message- From: Leif K-Brooks [mailto:[EMAIL PROTECTED]] Sent: Friday, March 22, 2002 5:18 PM To: [EMAIL PROTECTED] Subject: [PHP] Variable problem I have a variable name in a print <<< END and then some text after it. The thing is, php thinks that the text is p

Re: [PHP] Variable problem

2002-02-04 Thread Randy Johnson
nt: Friday, January 18, 2002 2:26 PM Subject: RE: [PHP] Variable problem > Use an array !?, I mean : > > $result[$i] = "test"; > > > How do I combine the following so it is treated as one variable > > > > $i=10 > > > > $result$i="tes

RE: [PHP] Variable Problem

2002-01-19 Thread Philip Olson
> > Well, I'll try the technique you mentioned. > > Your offering is very appreciated. > > Thank you! > > :-] > > > > ps. > > execute me for my english... > > > > --- > > K.Tomono > > > > >

RE: [PHP] Variable Problem

2002-01-18 Thread Steven Maroney
ecute me for my english... > > --- > K.Tomono > > > > -----Original Message- > > From: Philip Olson [mailto:[EMAIL PROTECTED]] > > Sent: Saturday, January 19, 2002 2:30 PM > > To: —F–쌤Œá > > Cc: [EMAIL PROTECTED]; [EMAIL PROTECTED

Re: [PHP] Variable Problem

2002-01-18 Thread Jason Wong
On Saturday 19 January 2002 14:45, K.Tomono wrote: > Yes, I think too, it's better way to use an array rather than a dynamic > name of the variable. > > I thought that the first question means how to use a dynamic variable. > > By the way, > > > little array propaganda, jic :) Arrays work great

RE: [PHP] Variable Problem

2002-01-18 Thread K.Tomono
¤Œá > Cc: [EMAIL PROTECTED]; [EMAIL PROTECTED] > Subject: Re: [PHP] Variable Problem > > > > > How do I combine the following so it is treated as one variable. > > It's a good question, but why? Most likely an array will > work best for > this job, arrays are go

Re: [PHP] Variable Problem

2002-01-18 Thread Philip Olson
> How do I combine the following so it is treated as one variable. It's a good question, but why? Most likely an array will work best for this job, arrays are good: http://www.php.net/manual/en/language.types.array.php The man page on foreach is nice too, and has many examples which include

Re: [PHP] Variable Problem

2002-01-18 Thread
Hello. >How do I combine the following so it is treated as one variable > >$i=10 >$result$i="test"; > >I want this to be: > >$result10="test"; > >$i changes so I cannot just put in 10 instead of I. >anybody know how i can do that? > >TIA >Randy How about the below. or Cheers :-) ---

RE: [PHP] Variable problem

2002-01-18 Thread Yoel Benitez Fonseca
Use an array !?, I mean : $result[$i] = "test"; > How do I combine the following so it is treated as one variable > > $i=10 > > $result$i="test"; > > > I want this to be: > > > $result10="test"; > > > $i changes so I cannot just put in 10 instead of I. > > > anybody know how i can do that? -

Re: [PHP] Variable Problem

2002-01-18 Thread val petruchek
Valentin Petruchek (aki Zliy Pes) http://zliypes.com.ua mailto:[EMAIL PROTECTED] - Original Message - From: <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Saturday, January 19, 2002 2:47 AM Subject: [PHP] Variable Problem > > > How do I combine the following so it is treated as one

RE: [PHP] variable problem - help!

2002-01-16 Thread Rick Emery
$row[coloumname_${v$ariable}] -Original Message- From: Dani [mailto:[EMAIL PROTECTED]] Sent: Wednesday, January 16, 2002 8:36 AM To: [EMAIL PROTECTED] Subject: [PHP] variable problem - help! Importance: High Hi! I 'm trying not to hard code my php coding and I'm trying to pass a variab

Re: [PHP] variable problem - help!

2002-01-16 Thread Dani
Thanks for the reply! I really appriciate it! I'll try it first! regards, Dani Stefan Rusterholz wrote: > > Hi! > > > > I 'm trying not to hard code my php coding and I'm trying to pass a > > variable name into the $row[coloumname_$variable]; > $row["columname_$variable"] should do it. > $row

Re: [PHP] variable problem - help!

2002-01-16 Thread Stefan Rusterholz
> Hi! > > I 'm trying not to hard code my php coding and I'm trying to pass a > variable name into the $row[coloumname_$variable]; $row["columname_$variable"] should do it. $row[constant] is threaten as constant which is normally not the programmers intention (set_error_reporting(0) and you'll see

Re: [PHP] variable problem - help!

2002-01-16 Thread Nick Wilson
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 * On 16-01-02 at 12:45 * Dani said > Hi! > > I 'm trying not to hard code my php coding and I'm trying to pass a > variable name into the $row[coloumname_$variable]; > > I get an error message for this code. > > I'm just wondering if I could

Re: [PHP] Variable Problem when UPGRADING...

2001-01-30 Thread Richard Lynch
You set error_reporting to 15 (E_ALL) instead of 7. Turn it back down to 7 or fix your scripts to use if (isset($submit)){ } -- Visit the Zend Store at http://www.zend.com/store/ Wanna help me out? Like Music? Buy a CD: http://l-i-e.com/artists.htm Volunteer a little time: http://chatmusic

Re: [PHP] Variable Problem when UPGRADING...

2001-01-30 Thread Teodor Cimpoesu
James Smith wrote: > > Alright, when i was programming with PHP3, I would use > if statements like this: > > if(!$submit) { >// display form > } else { >// display signup complete > } > > to make multiple pages. Or I would do this: > > if($action == "signup") { >if(!$submit) { >

Re: [PHP] Variable Problem when UPGRADING...

2001-01-30 Thread Philip Olson
hi again james, btw, consider doing this : if (empty($submit)) { or if (!empty($submit)) { as it doesn't run into such problems. or use isset although i tend to almost always use empty, i LOVE empty() !!! each have their uses : http://www.php.net/manual/en/function.empty.php

Re: [PHP] Variable Problem when UPGRADING...

2001-01-29 Thread Philip Olson
this has to do with error reporting, using the function : http://www.php.net/manual/en/function.error-reporting.php definition of types : http://www.php.net/manual/en/phpdevel-errors.php you may have E_ALL or E_NOTICE on within php.ini philip olson http://www.cornado.com/ On Mon, 29 Jan 2