ot;."$cat_adt" ] = "Yeah";
>
> print $a['yx'];
>
>
> save yourself a lot of trouble and dont bother with
> variables-of-variables and trying to get
> $rm_$cat_adt == $rm_x
>
> just use a hash... that's what it's there for ;)
>
>
-of-variables and trying to get
$rm_$cat_adt == $rm_x
just use a hash... that's what it's there for ;)
> -Original Message-
> From: Tom Carter [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, June 20, 2001 5:24 AM
> To: Hasan Niyaz; [EMAIL PROTECTED]
> Subject: Re: [PHP]
Michi,
Yours did the trick...
thank you and everyone else who contributed.
Hasan
- Original Message -
From: <[EMAIL PROTECTED]>
To: "Hasan Niyaz" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Wednesday, June 20, 2001 11:46 AM
Subject: Re: [PHP] insertin
> I have come to a situation where i am having a variable inside another
variable.
> for example.
>
> $rm_$cat_adt
PHP would read this as trying to prepend the variable $cat_adt to the
variable $rm_
You seem to be trying to insert the variable $cat into the middle of a
variable.. possible, but
What on earth are you trying to do? :)
I'm not sure what your getting at, do you mean defining a variable based
on another variables name? Perhaps try using an array, and specifying
$rm($cat)
Sorry, im not too sure what you mean
Ray Hilton
-
[EMAIL PROTECTED]
http://rayh.co.uk
-Original M
> I have come to a situation where i am having a variable inside another
> variable.
> for example.
>
> $rm_$cat_adt
This works for me:
\n";
echo '"abc_def_ghi" = '.$abc_def_ghi."\n";
?>
michi
--
GMX - Die Kommunikationsplattform im Internet.
http://www.gmx.net
--
GMX Tipp:
Machen Sie I
why don't you do something like
$var = $foo && $baa;
?
-Original Message-
From: Hasan Niyaz [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, June 20, 2001 12:07 PM
To: [EMAIL PROTECTED]
Subject: [PHP] inserting a variable into a variable
Hello all,
I have come to a situati
7 matches
Mail list logo
